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Is there an equivalent of cd - for cp or mv
What is the zsh equivalent of bash's !$ (Bang Dollar)?Is there a Konsole equivalent for gnome?equivalent “echo on” for linux?Is there anything like emacs tramp for shell (bash/zsh)?What is the bash equivalent of zsh vared command?Where should I export an environment variable so that all combinations of bash/dash, interactive/non-interactive, login/non-login, will pick it up?zsh complete cd with two argumentsHow to use linux to not get crazy with root privilegesHow to synchronize two directories (on external harddrives with Linux), recognizing file movements?Is there an FTP or FTP-like client which allows “delta uploads” - i.e. only uploading the parts of a file which have been changed?
In Bash and similar shells cd - changes the current directory to a previously visited one. It's often very handy. I wonder if there is similar shorthand for copying or moving files, like:
~/project-a/ $ cd ../project-b
~/project-b/ $ cp Makefile LICENSE - # this won't work, hence the question
I'd be also happy with zsh specific answers.
linux bash file-transfer zsh
asked 2 days ago
Tadeusz ŁazurskiTadeusz Łazurski
313310
add a comment |
In Bash and similar shells cd - changes the current directory to a previously visited one. It's often very handy. I wonder if there is similar shorthand for copying or moving files, like:
~/project-a/ $ cd ../project-b
~/project-b/ $ cp Makefile LICENSE - # this won't work, hence the question
I'd be also happy with zsh specific answers.
linux bash file-transfer zsh
asked 2 days ago
Tadeusz ŁazurskiTadeusz Łazurski
313310
5
With bash: Instead of-pressEscand then.to get from last command its last argument (here:../project-b).
– Cyrus
2 days ago
That's true @Cyrus, but in the example the intention is to copy fromproject-btoproject-a.
– Tadeusz Łazurski
2 days ago
@Cyrus, I was always aware that bash has some Emacs-like key bindings and am a heavy Emacs user myself. I was always happily using the general line movement keys of emacs on the shell (C-a etc.). But your comment prompted me to actually look for key bindings inman bash. Holy moly... it really is Emacs-like, complete with the kill ring, the mark semantics (C-space) etc. Thanks for bringing that up.
– AnoE
yesterday
add a comment |
In Bash and similar shells cd - changes the current directory to a previously visited one. It's often very handy. I wonder if there is similar shorthand for copying or moving files, like:
~/project-a/ $ cd ../project-b
~/project-b/ $ cp Makefile LICENSE - # this won't work, hence the question
I'd be also happy with zsh specific answers.
linux bash file-transfer zsh
asked 2 days ago
Tadeusz ŁazurskiTadeusz Łazurski
313310
In Bash and similar shells cd - changes the current directory to a previously visited one. It's often very handy. I wonder if there is similar shorthand for copying or moving files, like:
~/project-a/ $ cd ../project-b
~/project-b/ $ cp Makefile LICENSE - # this won't work, hence the question
I'd be also happy with zsh specific answers.
linux bash file-transfer zsh
linux bash file-transfer zsh
asked 2 days ago
Tadeusz ŁazurskiTadeusz Łazurski
313310
asked 2 days ago
Tadeusz ŁazurskiTadeusz Łazurski
313310
asked 2 days ago
Tadeusz ŁazurskiTadeusz Łazurski
313310
asked 2 days ago
Tadeusz ŁazurskiTadeusz Łazurski
313310
asked 2 days ago
Tadeusz ŁazurskiTadeusz Łazurski
313310
313310
5
With bash: Instead of-pressEscand then.to get from last command its last argument (here:../project-b).
– Cyrus
2 days ago
That's true @Cyrus, but in the example the intention is to copy fromproject-btoproject-a.
– Tadeusz Łazurski
2 days ago
@Cyrus, I was always aware that bash has some Emacs-like key bindings and am a heavy Emacs user myself. I was always happily using the general line movement keys of emacs on the shell (C-a etc.). But your comment prompted me to actually look for key bindings inman bash. Holy moly... it really is Emacs-like, complete with the kill ring, the mark semantics (C-space) etc. Thanks for bringing that up.
– AnoE
yesterday
add a comment |
5
With bash: Instead of-pressEscand then.to get from last command its last argument (here:../project-b).
– Cyrus
2 days ago
That's true @Cyrus, but in the example the intention is to copy fromproject-btoproject-a.
– Tadeusz Łazurski
2 days ago
@Cyrus, I was always aware that bash has some Emacs-like key bindings and am a heavy Emacs user myself. I was always happily using the general line movement keys of emacs on the shell (C-a etc.). But your comment prompted me to actually look for key bindings inman bash. Holy moly... it really is Emacs-like, complete with the kill ring, the mark semantics (C-space) etc. Thanks for bringing that up.
– AnoE
yesterday
5
5
With bash: Instead of
- press Esc and then . to get from last command its last argument (here: ../project-b).– Cyrus
2 days ago
With bash: Instead of
- press Esc and then . to get from last command its last argument (here: ../project-b).– Cyrus
2 days ago
That's true @Cyrus, but in the example the intention is to copy from
project-b to project-a.– Tadeusz Łazurski
2 days ago
That's true @Cyrus, but in the example the intention is to copy from
project-b to project-a.– Tadeusz Łazurski
2 days ago
@Cyrus, I was always aware that bash has some Emacs-like key bindings and am a heavy Emacs user myself. I was always happily using the general line movement keys of emacs on the shell (C-a etc.). But your comment prompted me to actually look for key bindings in
man bash. Holy moly... it really is Emacs-like, complete with the kill ring, the mark semantics (C-space) etc. Thanks for bringing that up.– AnoE
yesterday
@Cyrus, I was always aware that bash has some Emacs-like key bindings and am a heavy Emacs user myself. I was always happily using the general line movement keys of emacs on the shell (C-a etc.). But your comment prompted me to actually look for key bindings in
man bash. Holy moly... it really is Emacs-like, complete with the kill ring, the mark semantics (C-space) etc. Thanks for bringing that up.– AnoE
yesterday
add a comment |
2 Answers
2
active
oldest
votes
If your shell has cd -, then it will likely have either the special variable $OLDPWD and/or the shortcut ~- for the directory you've been in previously.
cp Makefile LICENSE "$OLDPWD/"
cp Makefile LICENSE ~-
cat ~-/Makefile
Indeed the POSIX shell language (upon which ksh/bash/zsh are built) specifies that cd - should be equal to cd "$OLDPWD".
answered 2 days ago
grawitygrawity
242k37512569
1
Tilde expansion has a lot more to it even than that. For an additional taste, unix.stackexchange.com/a/286628/135943 and that doesn’t even cover home directories.
– Wildcard
2 days ago
add a comment |
You can always use shell backquotes.
They act like a subshell : the command in the backquotes is executed first, and its output is placed as argument of the main command.
~/folderA$ cd ../folderB
~/folderB$ cp Makefile `cd -`
# gets expended to "cp Makefile ~/folderA"
answered 2 days ago
Nathanael C.Nathanael C.
511
New contributor
Nathanael C. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
4
No, the commandcd -outputs nothing, so `cd -` expands to the empty string. Try the command % echo `cd -` to verify. You would need to use something like % echo `cd -; pwd` ...
– Neal Young
2 days ago
2
@NealYoung: It seems that there’s something wrong with your shell. POSIX says “When a <hyphen-minus> is used as the operand [tocd], this shall be equivalent to the command:cd "$OLDPWD" && pwd, which changes to the previous working directory and then writes its name.” … (Cont’d)
– G-Man
2 days ago
1
(Cont’d) … And bash(1) says “An argument of-is converted to$OLDPWDbefore the directory change is attempted. If a non-empty directory name fromCDPATHis used, or if-is the first argument, and the directory change is successful, the absolute pathname of the new working directory is written to the standard output.”
– G-Man
2 days ago
@Nathanael C.: But please use"$(cd -)".
– G-Man
2 days ago
There's only "something wrong" if the shell claims POSIX compliance, and I think it's perfectly normal for shells that weren't invoked as /bin/sh and aren't specifically trying to emulate a POSIX shell to implement their language in whatever way they want...
– grawity
2 days ago
|
show 1 more comment
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votes
If your shell has cd -, then it will likely have either the special variable $OLDPWD and/or the shortcut ~- for the directory you've been in previously.
cp Makefile LICENSE "$OLDPWD/"
cp Makefile LICENSE ~-
cat ~-/Makefile
Indeed the POSIX shell language (upon which ksh/bash/zsh are built) specifies that cd - should be equal to cd "$OLDPWD".
answered 2 days ago
grawitygrawity
242k37512569
1
Tilde expansion has a lot more to it even than that. For an additional taste, unix.stackexchange.com/a/286628/135943 and that doesn’t even cover home directories.
– Wildcard
2 days ago
add a comment |
If your shell has cd -, then it will likely have either the special variable $OLDPWD and/or the shortcut ~- for the directory you've been in previously.
cp Makefile LICENSE "$OLDPWD/"
cp Makefile LICENSE ~-
cat ~-/Makefile
Indeed the POSIX shell language (upon which ksh/bash/zsh are built) specifies that cd - should be equal to cd "$OLDPWD".
answered 2 days ago
grawitygrawity
242k37512569
1
Tilde expansion has a lot more to it even than that. For an additional taste, unix.stackexchange.com/a/286628/135943 and that doesn’t even cover home directories.
– Wildcard
2 days ago
add a comment |
If your shell has cd -, then it will likely have either the special variable $OLDPWD and/or the shortcut ~- for the directory you've been in previously.
cp Makefile LICENSE "$OLDPWD/"
cp Makefile LICENSE ~-
cat ~-/Makefile
Indeed the POSIX shell language (upon which ksh/bash/zsh are built) specifies that cd - should be equal to cd "$OLDPWD".
answered 2 days ago
grawitygrawity
242k37512569
If your shell has cd -, then it will likely have either the special variable $OLDPWD and/or the shortcut ~- for the directory you've been in previously.
cp Makefile LICENSE "$OLDPWD/"
cp Makefile LICENSE ~-
cat ~-/Makefile
Indeed the POSIX shell language (upon which ksh/bash/zsh are built) specifies that cd - should be equal to cd "$OLDPWD".
answered 2 days ago
grawitygrawity
242k37512569
edited 2 days ago
answered 2 days ago
grawitygrawity
242k37512569
answered 2 days ago
grawitygrawity
242k37512569
answered 2 days ago
grawitygrawity
242k37512569
242k37512569
1
Tilde expansion has a lot more to it even than that. For an additional taste, unix.stackexchange.com/a/286628/135943 and that doesn’t even cover home directories.
– Wildcard
2 days ago
add a comment |
1
Tilde expansion has a lot more to it even than that. For an additional taste, unix.stackexchange.com/a/286628/135943 and that doesn’t even cover home directories.
– Wildcard
2 days ago
1
1
Tilde expansion has a lot more to it even than that. For an additional taste, unix.stackexchange.com/a/286628/135943 and that doesn’t even cover home directories.
– Wildcard
2 days ago
Tilde expansion has a lot more to it even than that. For an additional taste, unix.stackexchange.com/a/286628/135943 and that doesn’t even cover home directories.
– Wildcard
2 days ago
add a comment |
You can always use shell backquotes.
They act like a subshell : the command in the backquotes is executed first, and its output is placed as argument of the main command.
~/folderA$ cd ../folderB
~/folderB$ cp Makefile `cd -`
# gets expended to "cp Makefile ~/folderA"
answered 2 days ago
Nathanael C.Nathanael C.
511
New contributor
Nathanael C. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
4
No, the commandcd -outputs nothing, so `cd -` expands to the empty string. Try the command % echo `cd -` to verify. You would need to use something like % echo `cd -; pwd` ...
– Neal Young
2 days ago
2
@NealYoung: It seems that there’s something wrong with your shell. POSIX says “When a <hyphen-minus> is used as the operand [tocd], this shall be equivalent to the command:cd "$OLDPWD" && pwd, which changes to the previous working directory and then writes its name.” … (Cont’d)
– G-Man
2 days ago
1
(Cont’d) … And bash(1) says “An argument of-is converted to$OLDPWDbefore the directory change is attempted. If a non-empty directory name fromCDPATHis used, or if-is the first argument, and the directory change is successful, the absolute pathname of the new working directory is written to the standard output.”
– G-Man
2 days ago
@Nathanael C.: But please use"$(cd -)".
– G-Man
2 days ago
There's only "something wrong" if the shell claims POSIX compliance, and I think it's perfectly normal for shells that weren't invoked as /bin/sh and aren't specifically trying to emulate a POSIX shell to implement their language in whatever way they want...
– grawity
2 days ago
|
show 1 more comment
You can always use shell backquotes.
They act like a subshell : the command in the backquotes is executed first, and its output is placed as argument of the main command.
~/folderA$ cd ../folderB
~/folderB$ cp Makefile `cd -`
# gets expended to "cp Makefile ~/folderA"
answered 2 days ago
Nathanael C.Nathanael C.
511
New contributor
Nathanael C. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
4
No, the commandcd -outputs nothing, so `cd -` expands to the empty string. Try the command % echo `cd -` to verify. You would need to use something like % echo `cd -; pwd` ...
– Neal Young
2 days ago
2
@NealYoung: It seems that there’s something wrong with your shell. POSIX says “When a <hyphen-minus> is used as the operand [tocd], this shall be equivalent to the command:cd "$OLDPWD" && pwd, which changes to the previous working directory and then writes its name.” … (Cont’d)
– G-Man
2 days ago
1
(Cont’d) … And bash(1) says “An argument of-is converted to$OLDPWDbefore the directory change is attempted. If a non-empty directory name fromCDPATHis used, or if-is the first argument, and the directory change is successful, the absolute pathname of the new working directory is written to the standard output.”
– G-Man
2 days ago
@Nathanael C.: But please use"$(cd -)".
– G-Man
2 days ago
There's only "something wrong" if the shell claims POSIX compliance, and I think it's perfectly normal for shells that weren't invoked as /bin/sh and aren't specifically trying to emulate a POSIX shell to implement their language in whatever way they want...
– grawity
2 days ago
|
show 1 more comment
You can always use shell backquotes.
They act like a subshell : the command in the backquotes is executed first, and its output is placed as argument of the main command.
~/folderA$ cd ../folderB
~/folderB$ cp Makefile `cd -`
# gets expended to "cp Makefile ~/folderA"
answered 2 days ago
Nathanael C.Nathanael C.
511
New contributor
Nathanael C. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
You can always use shell backquotes.
They act like a subshell : the command in the backquotes is executed first, and its output is placed as argument of the main command.
~/folderA$ cd ../folderB
~/folderB$ cp Makefile `cd -`
# gets expended to "cp Makefile ~/folderA"
answered 2 days ago
Nathanael C.Nathanael C.
511
New contributor
Nathanael C. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
Nathanael C.Nathanael C.
511
New contributor
Nathanael C. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
Nathanael C.Nathanael C.
511
answered 2 days ago
Nathanael C.Nathanael C.
511
511
New contributor
Nathanael C. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Nathanael C. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Nathanael C. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
4
No, the commandcd -outputs nothing, so `cd -` expands to the empty string. Try the command % echo `cd -` to verify. You would need to use something like % echo `cd -; pwd` ...
– Neal Young
2 days ago
2
@NealYoung: It seems that there’s something wrong with your shell. POSIX says “When a <hyphen-minus> is used as the operand [tocd], this shall be equivalent to the command:cd "$OLDPWD" && pwd, which changes to the previous working directory and then writes its name.” … (Cont’d)
– G-Man
2 days ago
1
(Cont’d) … And bash(1) says “An argument of-is converted to$OLDPWDbefore the directory change is attempted. If a non-empty directory name fromCDPATHis used, or if-is the first argument, and the directory change is successful, the absolute pathname of the new working directory is written to the standard output.”
– G-Man
2 days ago
@Nathanael C.: But please use"$(cd -)".
– G-Man
2 days ago
There's only "something wrong" if the shell claims POSIX compliance, and I think it's perfectly normal for shells that weren't invoked as /bin/sh and aren't specifically trying to emulate a POSIX shell to implement their language in whatever way they want...
– grawity
2 days ago
|
show 1 more comment
4
No, the commandcd -outputs nothing, so `cd -` expands to the empty string. Try the command % echo `cd -` to verify. You would need to use something like % echo `cd -; pwd` ...
– Neal Young
2 days ago
2
@NealYoung: It seems that there’s something wrong with your shell. POSIX says “When a <hyphen-minus> is used as the operand [tocd], this shall be equivalent to the command:cd "$OLDPWD" && pwd, which changes to the previous working directory and then writes its name.” … (Cont’d)
– G-Man
2 days ago
1
(Cont’d) … And bash(1) says “An argument of-is converted to$OLDPWDbefore the directory change is attempted. If a non-empty directory name fromCDPATHis used, or if-is the first argument, and the directory change is successful, the absolute pathname of the new working directory is written to the standard output.”
– G-Man
2 days ago
@Nathanael C.: But please use"$(cd -)".
– G-Man
2 days ago
There's only "something wrong" if the shell claims POSIX compliance, and I think it's perfectly normal for shells that weren't invoked as /bin/sh and aren't specifically trying to emulate a POSIX shell to implement their language in whatever way they want...
– grawity
2 days ago
4
4
No, the command
cd - outputs nothing, so `cd -` expands to the empty string. Try the command % echo `cd -` to verify. You would need to use something like % echo `cd -; pwd` ...– Neal Young
2 days ago
No, the command
cd - outputs nothing, so `cd -` expands to the empty string. Try the command % echo `cd -` to verify. You would need to use something like % echo `cd -; pwd` ...– Neal Young
2 days ago
2
2
@NealYoung: It seems that there’s something wrong with your shell. POSIX says “When a <hyphen-minus> is used as the operand [to
cd], this shall be equivalent to the command: cd "$OLDPWD" && pwd, which changes to the previous working directory and then writes its name.” … (Cont’d)– G-Man
2 days ago
@NealYoung: It seems that there’s something wrong with your shell. POSIX says “When a <hyphen-minus> is used as the operand [to
cd], this shall be equivalent to the command: cd "$OLDPWD" && pwd, which changes to the previous working directory and then writes its name.” … (Cont’d)– G-Man
2 days ago
1
1
(Cont’d) … And bash(1) says “An argument of
- is converted to $OLDPWD before the directory change is attempted. If a non-empty directory name from CDPATH is used, or if - is the first argument, and the directory change is successful, the absolute pathname of the new working directory is written to the standard output.”– G-Man
2 days ago
(Cont’d) … And bash(1) says “An argument of
- is converted to $OLDPWD before the directory change is attempted. If a non-empty directory name from CDPATH is used, or if - is the first argument, and the directory change is successful, the absolute pathname of the new working directory is written to the standard output.”– G-Man
2 days ago
@Nathanael C.: But please use
"$(cd -)".– G-Man
2 days ago
@Nathanael C.: But please use
"$(cd -)".– G-Man
2 days ago
There's only "something wrong" if the shell claims POSIX compliance, and I think it's perfectly normal for shells that weren't invoked as /bin/sh and aren't specifically trying to emulate a POSIX shell to implement their language in whatever way they want...
– grawity
2 days ago
There's only "something wrong" if the shell claims POSIX compliance, and I think it's perfectly normal for shells that weren't invoked as /bin/sh and aren't specifically trying to emulate a POSIX shell to implement their language in whatever way they want...
– grawity
2 days ago
|
show 1 more comment
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5
With bash: Instead of
-pressEscand then.to get from last command its last argument (here:../project-b).– Cyrus
2 days ago
That's true @Cyrus, but in the example the intention is to copy from
project-btoproject-a.– Tadeusz Łazurski
2 days ago
@Cyrus, I was always aware that bash has some Emacs-like key bindings and am a heavy Emacs user myself. I was always happily using the general line movement keys of emacs on the shell (C-a etc.). But your comment prompted me to actually look for key bindings in
man bash. Holy moly... it really is Emacs-like, complete with the kill ring, the mark semantics (C-space) etc. Thanks for bringing that up.– AnoE
yesterday