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How to use ReplaceAll on an expression that contains a rule
Replacement rule only matches part of expressionHow can I avoid this ReplaceAll trap?StringReplace, ReplaceAll and Rule interact in a bizarre wayReplaceAll in an expression including large InterpolatingFunctionWhen I use Rule, why doesn't this work?How to apply substitution when expression contains powers of the quanityHow to ReplaceAll except within specified headsIs there a limit to ReplaceAll rule list?Apply replacement rules to all levelsHow to use ReplaceAll and RuleDelayed with an Association?
$begingroup$
I know I have seen this before but can't seem to locate it today.
I am trying to take an expression that has some rules in it and replace one of that parts that contain a rule using ReplaceAll
For a simple example consider:
testExpression = "stuff", Axes -> False, True
(* "stuff", Axes -> False, True *)
and I want to replace the
Axes -> False, True
with
Axes -> False
I have tried
testExpression /.
Hold[Axes -> False, True] -> Hold[Axes -> False]
(* "stuff", Axes -> False, True *)
as well as
testExpression /.
Hold[Rule[Axes , False, True]] -> Hold[Rule[Axes , False]]
(* "stuff", Axes -> False, True *)
I promise to add this to my set of notes if someone could kindly enlighten me.
replacement
$endgroup$
add a comment |
$begingroup$
I know I have seen this before but can't seem to locate it today.
I am trying to take an expression that has some rules in it and replace one of that parts that contain a rule using ReplaceAll
For a simple example consider:
testExpression = "stuff", Axes -> False, True
(* "stuff", Axes -> False, True *)
and I want to replace the
Axes -> False, True
with
Axes -> False
I have tried
testExpression /.
Hold[Axes -> False, True] -> Hold[Axes -> False]
(* "stuff", Axes -> False, True *)
as well as
testExpression /.
Hold[Rule[Axes , False, True]] -> Hold[Rule[Axes , False]]
(* "stuff", Axes -> False, True *)
I promise to add this to my set of notes if someone could kindly enlighten me.
replacement
$endgroup$
add a comment |
$begingroup$
I know I have seen this before but can't seem to locate it today.
I am trying to take an expression that has some rules in it and replace one of that parts that contain a rule using ReplaceAll
For a simple example consider:
testExpression = "stuff", Axes -> False, True
(* "stuff", Axes -> False, True *)
and I want to replace the
Axes -> False, True
with
Axes -> False
I have tried
testExpression /.
Hold[Axes -> False, True] -> Hold[Axes -> False]
(* "stuff", Axes -> False, True *)
as well as
testExpression /.
Hold[Rule[Axes , False, True]] -> Hold[Rule[Axes , False]]
(* "stuff", Axes -> False, True *)
I promise to add this to my set of notes if someone could kindly enlighten me.
replacement
$endgroup$
I know I have seen this before but can't seem to locate it today.
I am trying to take an expression that has some rules in it and replace one of that parts that contain a rule using ReplaceAll
For a simple example consider:
testExpression = "stuff", Axes -> False, True
(* "stuff", Axes -> False, True *)
and I want to replace the
Axes -> False, True
with
Axes -> False
I have tried
testExpression /.
Hold[Axes -> False, True] -> Hold[Axes -> False]
(* "stuff", Axes -> False, True *)
as well as
testExpression /.
Hold[Rule[Axes , False, True]] -> Hold[Rule[Axes , False]]
(* "stuff", Axes -> False, True *)
I promise to add this to my set of notes if someone could kindly enlighten me.
replacement
replacement
asked 2 days ago
Jack LaVigneJack LaVigne
12k21632
12k21632
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Here are a couple possibilities:
testExpression /. Rule[Axes, False, True] -> Axes -> False
testExpression /. HoldPattern[Axes -> False, True] -> Axes -> False
"stuff", Axes -> False
"stuff", Axes -> False
$endgroup$
add a comment |
$begingroup$
I think this is just a matter of getting the parentheses right
testExpression /. (Axes -> False, True) -> (Axes -> False)
(* "stuff", Axes -> False *)
$endgroup$
$begingroup$
I'd have posted this too. (+1)
$endgroup$
– J. M. is slightly pensive♦
2 days ago
$begingroup$
Wish I could accept them both
$endgroup$
– Jack LaVigne
yesterday
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Here are a couple possibilities:
testExpression /. Rule[Axes, False, True] -> Axes -> False
testExpression /. HoldPattern[Axes -> False, True] -> Axes -> False
"stuff", Axes -> False
"stuff", Axes -> False
$endgroup$
add a comment |
$begingroup$
Here are a couple possibilities:
testExpression /. Rule[Axes, False, True] -> Axes -> False
testExpression /. HoldPattern[Axes -> False, True] -> Axes -> False
"stuff", Axes -> False
"stuff", Axes -> False
$endgroup$
add a comment |
$begingroup$
Here are a couple possibilities:
testExpression /. Rule[Axes, False, True] -> Axes -> False
testExpression /. HoldPattern[Axes -> False, True] -> Axes -> False
"stuff", Axes -> False
"stuff", Axes -> False
$endgroup$
Here are a couple possibilities:
testExpression /. Rule[Axes, False, True] -> Axes -> False
testExpression /. HoldPattern[Axes -> False, True] -> Axes -> False
"stuff", Axes -> False
"stuff", Axes -> False
answered 2 days ago
Carl WollCarl Woll
72.3k395186
72.3k395186
add a comment |
add a comment |
$begingroup$
I think this is just a matter of getting the parentheses right
testExpression /. (Axes -> False, True) -> (Axes -> False)
(* "stuff", Axes -> False *)
$endgroup$
$begingroup$
I'd have posted this too. (+1)
$endgroup$
– J. M. is slightly pensive♦
2 days ago
$begingroup$
Wish I could accept them both
$endgroup$
– Jack LaVigne
yesterday
add a comment |
$begingroup$
I think this is just a matter of getting the parentheses right
testExpression /. (Axes -> False, True) -> (Axes -> False)
(* "stuff", Axes -> False *)
$endgroup$
$begingroup$
I'd have posted this too. (+1)
$endgroup$
– J. M. is slightly pensive♦
2 days ago
$begingroup$
Wish I could accept them both
$endgroup$
– Jack LaVigne
yesterday
add a comment |
$begingroup$
I think this is just a matter of getting the parentheses right
testExpression /. (Axes -> False, True) -> (Axes -> False)
(* "stuff", Axes -> False *)
$endgroup$
I think this is just a matter of getting the parentheses right
testExpression /. (Axes -> False, True) -> (Axes -> False)
(* "stuff", Axes -> False *)
answered 2 days ago
mikadomikado
6,8421929
6,8421929
$begingroup$
I'd have posted this too. (+1)
$endgroup$
– J. M. is slightly pensive♦
2 days ago
$begingroup$
Wish I could accept them both
$endgroup$
– Jack LaVigne
yesterday
add a comment |
$begingroup$
I'd have posted this too. (+1)
$endgroup$
– J. M. is slightly pensive♦
2 days ago
$begingroup$
Wish I could accept them both
$endgroup$
– Jack LaVigne
yesterday
$begingroup$
I'd have posted this too. (+1)
$endgroup$
– J. M. is slightly pensive♦
2 days ago
$begingroup$
I'd have posted this too. (+1)
$endgroup$
– J. M. is slightly pensive♦
2 days ago
$begingroup$
Wish I could accept them both
$endgroup$
– Jack LaVigne
yesterday
$begingroup$
Wish I could accept them both
$endgroup$
– Jack LaVigne
yesterday
add a comment |
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