Would reducing the reference voltage of an ADC have any effect on accuracy?Why would smaller LSB reduce SNR performance in an ADC?AVR 1.1V Internal ADC Reference Over-Voltagecan the input voltage to ADC exceed the reference in LPC 2468Implications of INL on the accuracy and resolution of an ADCSTM32F1 Can't I use the internal voltage reference as the ADC reference?Long term effect of over-voltage on clamping diodes and ADC reference voltagewould using the reference voltage of an ADC as a VOLTAGE SOURCE affect my ADC or the stability of the circuit?Voltage divider for Arduino external ADC reference voltage (AREF)STM32 ADC reference voltageADC variable reference voltagedsPIC33E ADC with external voltage reference

Do I have to worry about players making “bad” choices on level up?

How to replace the "space symbol" (squat-u) in listings?

How to creep the reader out with what seems like a normal person?

Please, smoke with good manners

Why didn't this hurt this character as badly?

Why do computer-science majors learn calculus?

Find the coordinate of two line segments that are perpendicular

Stateful vs non-stateful app

Is it possible to measure lightning discharges as Nikola Tesla?

Phrase for the opposite of "foolproof"

Can not tell colimits from limits

Confusion about capacitors

Examples of non trivial equivalence relations , I mean equivalence relations without the expression " same ... as" in their definition?

What does YCWCYODFTRFDTY mean?

Why the difference in metal between 銀行 and お金?

Pressure to defend the relevance of one's area of mathematics

How can I record the screen and the rear camera on an iPhone simultaneously?

How deep to place a deadman anchor for a slackline?

How to figure out whether the data is sample data or population data apart from the client's information?

Counterexample: a pair of linearly ordered sets that are isomorphic to subsets of the other, but not isomorphic between them

Why was Germany not as successful as other Europeans in establishing overseas colonies?

Where did the extra Pym particles come from in Endgame?

Reverse the word in a string with the same order in javascript

Pulling the rope with one hand is as heavy as with two hands?



Would reducing the reference voltage of an ADC have any effect on accuracy?


Why would smaller LSB reduce SNR performance in an ADC?AVR 1.1V Internal ADC Reference Over-Voltagecan the input voltage to ADC exceed the reference in LPC 2468Implications of INL on the accuracy and resolution of an ADCSTM32F1 Can't I use the internal voltage reference as the ADC reference?Long term effect of over-voltage on clamping diodes and ADC reference voltagewould using the reference voltage of an ADC as a VOLTAGE SOURCE affect my ADC or the stability of the circuit?Voltage divider for Arduino external ADC reference voltage (AREF)STM32 ADC reference voltageADC variable reference voltagedsPIC33E ADC with external voltage reference






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








7












$begingroup$


Regarding the following information taken from a paper:



enter image description here



The paragraph is telling about what happens when the ADC Vref is reduced.



There is the statement from the above quote:




Note that if you reduce the reference voltage to 0.8V, the LSB would
then represent 100mV, allowing you to measure a smaller range of
voltages (0 to 0.8V) with greater accuracy.




Isn't it wrong to say "with greater accuracy"? Shouldn't it be "with greater precision" instead?



(I'm asking because if I don't clarify this point, I will be misunderstanding all the rest)










share|improve this question









$endgroup$











  • $begingroup$
    they use 'precision' in the next sentence. I'm not sure there's a well defined difference between accuracy and precision, the way there is a well defined difference between accuracy and resolution.
    $endgroup$
    – Neil_UK
    Apr 24 at 13:41






  • 1




    $begingroup$
    But accuracy and precision are not same thing afaik. Accuracy I guess is deviation of the mean value from true value. But precision is more about the number of decimals a quantity can be represented. 2.123 is more precise than 2.12. This was I thought.
    $endgroup$
    – atmnt
    Apr 24 at 13:45







  • 1




    $begingroup$
    Your understanding of what "precision" means is not correct. The word precision is usually used to mean repeatability or reproducibility of a measurement. See for example nist.gov/pml/…
    $endgroup$
    – Elliot Alderson
    Apr 24 at 14:43






  • 2




    $begingroup$
    Perhaps you have not seen the bullseye diagram before: cdn.antarcticglaciers.org/wp-content/uploads/2013/11/…
    $endgroup$
    – sstobbe
    Apr 24 at 14:47

















7












$begingroup$


Regarding the following information taken from a paper:



enter image description here



The paragraph is telling about what happens when the ADC Vref is reduced.



There is the statement from the above quote:




Note that if you reduce the reference voltage to 0.8V, the LSB would
then represent 100mV, allowing you to measure a smaller range of
voltages (0 to 0.8V) with greater accuracy.




Isn't it wrong to say "with greater accuracy"? Shouldn't it be "with greater precision" instead?



(I'm asking because if I don't clarify this point, I will be misunderstanding all the rest)










share|improve this question









$endgroup$











  • $begingroup$
    they use 'precision' in the next sentence. I'm not sure there's a well defined difference between accuracy and precision, the way there is a well defined difference between accuracy and resolution.
    $endgroup$
    – Neil_UK
    Apr 24 at 13:41






  • 1




    $begingroup$
    But accuracy and precision are not same thing afaik. Accuracy I guess is deviation of the mean value from true value. But precision is more about the number of decimals a quantity can be represented. 2.123 is more precise than 2.12. This was I thought.
    $endgroup$
    – atmnt
    Apr 24 at 13:45







  • 1




    $begingroup$
    Your understanding of what "precision" means is not correct. The word precision is usually used to mean repeatability or reproducibility of a measurement. See for example nist.gov/pml/…
    $endgroup$
    – Elliot Alderson
    Apr 24 at 14:43






  • 2




    $begingroup$
    Perhaps you have not seen the bullseye diagram before: cdn.antarcticglaciers.org/wp-content/uploads/2013/11/…
    $endgroup$
    – sstobbe
    Apr 24 at 14:47













7












7








7


1



$begingroup$


Regarding the following information taken from a paper:



enter image description here



The paragraph is telling about what happens when the ADC Vref is reduced.



There is the statement from the above quote:




Note that if you reduce the reference voltage to 0.8V, the LSB would
then represent 100mV, allowing you to measure a smaller range of
voltages (0 to 0.8V) with greater accuracy.




Isn't it wrong to say "with greater accuracy"? Shouldn't it be "with greater precision" instead?



(I'm asking because if I don't clarify this point, I will be misunderstanding all the rest)










share|improve this question









$endgroup$




Regarding the following information taken from a paper:



enter image description here



The paragraph is telling about what happens when the ADC Vref is reduced.



There is the statement from the above quote:




Note that if you reduce the reference voltage to 0.8V, the LSB would
then represent 100mV, allowing you to measure a smaller range of
voltages (0 to 0.8V) with greater accuracy.




Isn't it wrong to say "with greater accuracy"? Shouldn't it be "with greater precision" instead?



(I'm asking because if I don't clarify this point, I will be misunderstanding all the rest)







adc accuracy resolution






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Apr 24 at 13:21









atmntatmnt

859625




859625











  • $begingroup$
    they use 'precision' in the next sentence. I'm not sure there's a well defined difference between accuracy and precision, the way there is a well defined difference between accuracy and resolution.
    $endgroup$
    – Neil_UK
    Apr 24 at 13:41






  • 1




    $begingroup$
    But accuracy and precision are not same thing afaik. Accuracy I guess is deviation of the mean value from true value. But precision is more about the number of decimals a quantity can be represented. 2.123 is more precise than 2.12. This was I thought.
    $endgroup$
    – atmnt
    Apr 24 at 13:45







  • 1




    $begingroup$
    Your understanding of what "precision" means is not correct. The word precision is usually used to mean repeatability or reproducibility of a measurement. See for example nist.gov/pml/…
    $endgroup$
    – Elliot Alderson
    Apr 24 at 14:43






  • 2




    $begingroup$
    Perhaps you have not seen the bullseye diagram before: cdn.antarcticglaciers.org/wp-content/uploads/2013/11/…
    $endgroup$
    – sstobbe
    Apr 24 at 14:47
















  • $begingroup$
    they use 'precision' in the next sentence. I'm not sure there's a well defined difference between accuracy and precision, the way there is a well defined difference between accuracy and resolution.
    $endgroup$
    – Neil_UK
    Apr 24 at 13:41






  • 1




    $begingroup$
    But accuracy and precision are not same thing afaik. Accuracy I guess is deviation of the mean value from true value. But precision is more about the number of decimals a quantity can be represented. 2.123 is more precise than 2.12. This was I thought.
    $endgroup$
    – atmnt
    Apr 24 at 13:45







  • 1




    $begingroup$
    Your understanding of what "precision" means is not correct. The word precision is usually used to mean repeatability or reproducibility of a measurement. See for example nist.gov/pml/…
    $endgroup$
    – Elliot Alderson
    Apr 24 at 14:43






  • 2




    $begingroup$
    Perhaps you have not seen the bullseye diagram before: cdn.antarcticglaciers.org/wp-content/uploads/2013/11/…
    $endgroup$
    – sstobbe
    Apr 24 at 14:47















$begingroup$
they use 'precision' in the next sentence. I'm not sure there's a well defined difference between accuracy and precision, the way there is a well defined difference between accuracy and resolution.
$endgroup$
– Neil_UK
Apr 24 at 13:41




$begingroup$
they use 'precision' in the next sentence. I'm not sure there's a well defined difference between accuracy and precision, the way there is a well defined difference between accuracy and resolution.
$endgroup$
– Neil_UK
Apr 24 at 13:41




1




1




$begingroup$
But accuracy and precision are not same thing afaik. Accuracy I guess is deviation of the mean value from true value. But precision is more about the number of decimals a quantity can be represented. 2.123 is more precise than 2.12. This was I thought.
$endgroup$
– atmnt
Apr 24 at 13:45





$begingroup$
But accuracy and precision are not same thing afaik. Accuracy I guess is deviation of the mean value from true value. But precision is more about the number of decimals a quantity can be represented. 2.123 is more precise than 2.12. This was I thought.
$endgroup$
– atmnt
Apr 24 at 13:45





1




1




$begingroup$
Your understanding of what "precision" means is not correct. The word precision is usually used to mean repeatability or reproducibility of a measurement. See for example nist.gov/pml/…
$endgroup$
– Elliot Alderson
Apr 24 at 14:43




$begingroup$
Your understanding of what "precision" means is not correct. The word precision is usually used to mean repeatability or reproducibility of a measurement. See for example nist.gov/pml/…
$endgroup$
– Elliot Alderson
Apr 24 at 14:43




2




2




$begingroup$
Perhaps you have not seen the bullseye diagram before: cdn.antarcticglaciers.org/wp-content/uploads/2013/11/…
$endgroup$
– sstobbe
Apr 24 at 14:47




$begingroup$
Perhaps you have not seen the bullseye diagram before: cdn.antarcticglaciers.org/wp-content/uploads/2013/11/…
$endgroup$
– sstobbe
Apr 24 at 14:47










6 Answers
6






active

oldest

votes


















9












$begingroup$

I think precision means more numbers, like: 1.23 V vs 1.2300 V, the latter has more precision. However, that says nothing about the true value of the voltage. It is possible that my inaccurate meter says 1.2300 V while the actual voltage is 1.220000 V



More accuracy means that the value I get is closer to the real value. So my accurate meter would show: 1.221 V while the actual value is 1.220000 V.



So 1.221 V has greater accuracy (but less precision)



while



1.2300 V has greater precision (but less accuracy).



In the ADC example the amount of numbers (different reading) stays the same: 8 readings. So precision remains unaffected whatever the reference voltage is. Accuracy does increase though as the reference voltage is decreased because the LSB intervals become smaller as Vref decreases. That means that the value of the error between the actually measured voltage and the value which the ADC outputs (quantization error) will become smaller.



Also: instead "precision" engineers more often use "resolution".






share|improve this answer











$endgroup$








  • 1




    $begingroup$
    I also thought similar but then saying "with greater accuracy" in that context is wrong correct? Better resolution causes better precision but not better accuracy.
    $endgroup$
    – atmnt
    Apr 24 at 13:48











  • $begingroup$
    It is the other way round, precision stays the same due to the ADC being 8 bit. Accuracy increases as the error between reported value and real value becomes smaller when Vref is decreased.
    $endgroup$
    – Bimpelrekkie
    Apr 24 at 13:52










  • $begingroup$
    You mean 3-bit instead of 8 bit ?
    $endgroup$
    – atmnt
    Apr 24 at 13:53











  • $begingroup$
    You're right, 3 bit, 8 values
    $endgroup$
    – Bimpelrekkie
    Apr 24 at 13:56











  • $begingroup$
    I see. Just one more thing. If the Vref would remain the same but the ADC resolution was increased lets say to 6-bit from 3-bit; for that case can we say the precision gets better but accuracy remains the same? Or they both get better? I hope you have comment on this because this is very critical to clarify.
    $endgroup$
    – atmnt
    Apr 24 at 14:05



















5












$begingroup$


Isn't it wrong to say "with greater accuracy"? Shouldn't it be "with greater precision" instead?




Oh, good. Someone who knows the difference.



To some extent, yes, with greater accuracy. But probably not by the ratio that you reduced the reference voltage, and to a diminishing amount as you do so. Some of the error sources in an ADC are in the front end, and basically reflect back as a voltage on the input. But -- mostly for SAR ADCs -- some of the error sources in an ADC are in the conversion itself.



A vastly simplified description of the operation of a SAR converter is that it makes educated guesses at the answer, applies them to a DAC, and compares the resulting analog signal to the input. Nonlinearity (incremental and integral) of an ADC is almost entirely from the built-in DAC, and reducing the reference voltage should reduce the magnitude of those errors proportionally.






share|improve this answer









$endgroup$




















    3












    $begingroup$

    Reducing the reference voltage simply means that the size of the "steps" between digital values is reduced. This increases the resolution of the converter at the cost of range, but if the measurement range is similarly constrained, then the increased resolution is a benefit.



    I would not expect changing the reference voltage to have an impact on accuracy, except that in some cases when you set the reference voltage at or near the supply voltage, then the linearity at the top end of the range may suffer in some cases (this is probably more an issue with DACs than ADCs though).



    Accuracy in ADCs or DACs has 3 components: offset, linearity and noise. Offset is, effectively, the difference between zero volts and whatever voltage actually results in a zero reading. Linearity is the consistency of the step size across the entire digital range. Noise is how much change you can expect with the same input read multiple times in succession. I wouldn't expect changing the reference voltage to impact any of these except linearity, as I said before.






    share|improve this answer











    $endgroup$




















      2












      $begingroup$

      With smaller Vref, the ADC's comparator will have smaller voltages to use in making decisions, thus the errors (the differential non-linearity) will change.



      You will have the same # bits out, but the integral linearity and the differential linearity become unpredictable IMHO.



      Additionally, the random noise and the power-supply-rejection become more important. If the successive-approximation is performed by charge-splitting etc, then the size of the capacitors (binary weighted?) matters. Using



      Vnoise = sqrt (K * T /C)



      you'll compute the TOTAL integrated random noise of a 10pF capacitor is 20 microVolts RMS, or about 130 microVolts PeakPeak at the 1PPM level. As the caps become smaller, say 0.1pF, the PeakPeak noise now is sqrt(10p/0.1p) or sqrt(100) or 10X more random noise, which is 1,300 microVolts.






      share|improve this answer











      $endgroup$




















        1












        $begingroup$

        Typically, the term "accuracy" refers to systematic part of the error, while "precision" refers to the random part:



        enter image description here



        Reducing the ADC range (by lowering the reference voltage) will increase the resolution and reduce the quantization noise (which is not systematic*), thus improving the absolute precision. However, this improvement will only be visible if the quantization noise is dominant: if another kind of significant random noise (e.g. from AC on the power supply line) is present, the improvement in precision will not be noticeable.



        Accuracy (aka trueness) may also get better depending on the internal properties of the ADC. Non-linearity and gain errors are (usually) proportional to the reference voltage, so those absolute errors will typically be reduced, while the offset error may often not change. The overall change in accuracy will again depend on which of those errors is dominant.



        According to Wikipedia, "accuracy" can be used to describe a combination of both random and systematic errors, so when both precision and trueness are improved, it's not wrong to say that the measurement has better accuracy.



        (*) - quantization error actually depends on the signal, but it's a very useful assumption needed for the additive noise model, which is automatically holds when this error is relatively small. When the quantization noise is large, artificial random noise (dither) is often applied to make the additive noise model work.






        share|improve this answer











        $endgroup$








        • 1




          $begingroup$
          Too clear an illustration to not Vote UP.
          $endgroup$
          – analogsystemsrf
          2 days ago


















        0












        $begingroup$

        I believe that you simply don't have all of the information. It is certainly true that resolution and accuracy are two very different things. The absolute resolution or voltage resolution is directly a function of the converter's reference voltage. With $N$ bits, the voltage resolution is $V_ref/2^N$. The word precision is not a good choice in this discussion; its meaning is less well defined and generally refers more to the repeatability of a measurement.



        However, I think what is missing from the one slide you show is that the accuracy of an ADC converter is typically specified as some number of bits rather than as an absolute voltage. The voltage equivalent of a "bit" is the amount of voltage change that would cause a change in one in the LSB of the converted value. This is sometimes called just $V_LSB$. So, if you change the reference voltage then the value of $V_LSB$ will also change and the relative accuracy of the converter remains the same. However, lower values of the reference voltage result in smaller values of $V_LSB$, so decreasing the reference voltage leads to a smaller absolute accuracy (in volts).






        share|improve this answer











        $endgroup$












        • $begingroup$
          Your "precision is directly a function of the converter's reference voltage" does not match with the other answer which says the precision stays the same. There is still some confusion.
          $endgroup$
          – atmnt
          Apr 24 at 14:16











        • $begingroup$
          You're right...but we shouldn't be using the word precision at all. We should be talking about the resolution of the converter. I will edit.
          $endgroup$
          – Elliot Alderson
          Apr 24 at 14:27











        Your Answer






        StackExchange.ifUsing("editor", function ()
        return StackExchange.using("schematics", function ()
        StackExchange.schematics.init();
        );
        , "cicuitlab");

        StackExchange.ready(function()
        var channelOptions =
        tags: "".split(" "),
        id: "135"
        ;
        initTagRenderer("".split(" "), "".split(" "), channelOptions);

        StackExchange.using("externalEditor", function()
        // Have to fire editor after snippets, if snippets enabled
        if (StackExchange.settings.snippets.snippetsEnabled)
        StackExchange.using("snippets", function()
        createEditor();
        );

        else
        createEditor();

        );

        function createEditor()
        StackExchange.prepareEditor(
        heartbeatType: 'answer',
        autoActivateHeartbeat: false,
        convertImagesToLinks: false,
        noModals: true,
        showLowRepImageUploadWarning: true,
        reputationToPostImages: null,
        bindNavPrevention: true,
        postfix: "",
        imageUploader:
        brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
        contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
        allowUrls: true
        ,
        onDemand: true,
        discardSelector: ".discard-answer"
        ,immediatelyShowMarkdownHelp:true
        );



        );













        draft saved

        draft discarded


















        StackExchange.ready(
        function ()
        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f435214%2fwould-reducing-the-reference-voltage-of-an-adc-have-any-effect-on-accuracy%23new-answer', 'question_page');

        );

        Post as a guest















        Required, but never shown

























        6 Answers
        6






        active

        oldest

        votes








        6 Answers
        6






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        9












        $begingroup$

        I think precision means more numbers, like: 1.23 V vs 1.2300 V, the latter has more precision. However, that says nothing about the true value of the voltage. It is possible that my inaccurate meter says 1.2300 V while the actual voltage is 1.220000 V



        More accuracy means that the value I get is closer to the real value. So my accurate meter would show: 1.221 V while the actual value is 1.220000 V.



        So 1.221 V has greater accuracy (but less precision)



        while



        1.2300 V has greater precision (but less accuracy).



        In the ADC example the amount of numbers (different reading) stays the same: 8 readings. So precision remains unaffected whatever the reference voltage is. Accuracy does increase though as the reference voltage is decreased because the LSB intervals become smaller as Vref decreases. That means that the value of the error between the actually measured voltage and the value which the ADC outputs (quantization error) will become smaller.



        Also: instead "precision" engineers more often use "resolution".






        share|improve this answer











        $endgroup$








        • 1




          $begingroup$
          I also thought similar but then saying "with greater accuracy" in that context is wrong correct? Better resolution causes better precision but not better accuracy.
          $endgroup$
          – atmnt
          Apr 24 at 13:48











        • $begingroup$
          It is the other way round, precision stays the same due to the ADC being 8 bit. Accuracy increases as the error between reported value and real value becomes smaller when Vref is decreased.
          $endgroup$
          – Bimpelrekkie
          Apr 24 at 13:52










        • $begingroup$
          You mean 3-bit instead of 8 bit ?
          $endgroup$
          – atmnt
          Apr 24 at 13:53











        • $begingroup$
          You're right, 3 bit, 8 values
          $endgroup$
          – Bimpelrekkie
          Apr 24 at 13:56











        • $begingroup$
          I see. Just one more thing. If the Vref would remain the same but the ADC resolution was increased lets say to 6-bit from 3-bit; for that case can we say the precision gets better but accuracy remains the same? Or they both get better? I hope you have comment on this because this is very critical to clarify.
          $endgroup$
          – atmnt
          Apr 24 at 14:05
















        9












        $begingroup$

        I think precision means more numbers, like: 1.23 V vs 1.2300 V, the latter has more precision. However, that says nothing about the true value of the voltage. It is possible that my inaccurate meter says 1.2300 V while the actual voltage is 1.220000 V



        More accuracy means that the value I get is closer to the real value. So my accurate meter would show: 1.221 V while the actual value is 1.220000 V.



        So 1.221 V has greater accuracy (but less precision)



        while



        1.2300 V has greater precision (but less accuracy).



        In the ADC example the amount of numbers (different reading) stays the same: 8 readings. So precision remains unaffected whatever the reference voltage is. Accuracy does increase though as the reference voltage is decreased because the LSB intervals become smaller as Vref decreases. That means that the value of the error between the actually measured voltage and the value which the ADC outputs (quantization error) will become smaller.



        Also: instead "precision" engineers more often use "resolution".






        share|improve this answer











        $endgroup$








        • 1




          $begingroup$
          I also thought similar but then saying "with greater accuracy" in that context is wrong correct? Better resolution causes better precision but not better accuracy.
          $endgroup$
          – atmnt
          Apr 24 at 13:48











        • $begingroup$
          It is the other way round, precision stays the same due to the ADC being 8 bit. Accuracy increases as the error between reported value and real value becomes smaller when Vref is decreased.
          $endgroup$
          – Bimpelrekkie
          Apr 24 at 13:52










        • $begingroup$
          You mean 3-bit instead of 8 bit ?
          $endgroup$
          – atmnt
          Apr 24 at 13:53











        • $begingroup$
          You're right, 3 bit, 8 values
          $endgroup$
          – Bimpelrekkie
          Apr 24 at 13:56











        • $begingroup$
          I see. Just one more thing. If the Vref would remain the same but the ADC resolution was increased lets say to 6-bit from 3-bit; for that case can we say the precision gets better but accuracy remains the same? Or they both get better? I hope you have comment on this because this is very critical to clarify.
          $endgroup$
          – atmnt
          Apr 24 at 14:05














        9












        9








        9





        $begingroup$

        I think precision means more numbers, like: 1.23 V vs 1.2300 V, the latter has more precision. However, that says nothing about the true value of the voltage. It is possible that my inaccurate meter says 1.2300 V while the actual voltage is 1.220000 V



        More accuracy means that the value I get is closer to the real value. So my accurate meter would show: 1.221 V while the actual value is 1.220000 V.



        So 1.221 V has greater accuracy (but less precision)



        while



        1.2300 V has greater precision (but less accuracy).



        In the ADC example the amount of numbers (different reading) stays the same: 8 readings. So precision remains unaffected whatever the reference voltage is. Accuracy does increase though as the reference voltage is decreased because the LSB intervals become smaller as Vref decreases. That means that the value of the error between the actually measured voltage and the value which the ADC outputs (quantization error) will become smaller.



        Also: instead "precision" engineers more often use "resolution".






        share|improve this answer











        $endgroup$



        I think precision means more numbers, like: 1.23 V vs 1.2300 V, the latter has more precision. However, that says nothing about the true value of the voltage. It is possible that my inaccurate meter says 1.2300 V while the actual voltage is 1.220000 V



        More accuracy means that the value I get is closer to the real value. So my accurate meter would show: 1.221 V while the actual value is 1.220000 V.



        So 1.221 V has greater accuracy (but less precision)



        while



        1.2300 V has greater precision (but less accuracy).



        In the ADC example the amount of numbers (different reading) stays the same: 8 readings. So precision remains unaffected whatever the reference voltage is. Accuracy does increase though as the reference voltage is decreased because the LSB intervals become smaller as Vref decreases. That means that the value of the error between the actually measured voltage and the value which the ADC outputs (quantization error) will become smaller.



        Also: instead "precision" engineers more often use "resolution".







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Apr 24 at 13:56

























        answered Apr 24 at 13:46









        BimpelrekkieBimpelrekkie

        52k246115




        52k246115







        • 1




          $begingroup$
          I also thought similar but then saying "with greater accuracy" in that context is wrong correct? Better resolution causes better precision but not better accuracy.
          $endgroup$
          – atmnt
          Apr 24 at 13:48











        • $begingroup$
          It is the other way round, precision stays the same due to the ADC being 8 bit. Accuracy increases as the error between reported value and real value becomes smaller when Vref is decreased.
          $endgroup$
          – Bimpelrekkie
          Apr 24 at 13:52










        • $begingroup$
          You mean 3-bit instead of 8 bit ?
          $endgroup$
          – atmnt
          Apr 24 at 13:53











        • $begingroup$
          You're right, 3 bit, 8 values
          $endgroup$
          – Bimpelrekkie
          Apr 24 at 13:56











        • $begingroup$
          I see. Just one more thing. If the Vref would remain the same but the ADC resolution was increased lets say to 6-bit from 3-bit; for that case can we say the precision gets better but accuracy remains the same? Or they both get better? I hope you have comment on this because this is very critical to clarify.
          $endgroup$
          – atmnt
          Apr 24 at 14:05













        • 1




          $begingroup$
          I also thought similar but then saying "with greater accuracy" in that context is wrong correct? Better resolution causes better precision but not better accuracy.
          $endgroup$
          – atmnt
          Apr 24 at 13:48











        • $begingroup$
          It is the other way round, precision stays the same due to the ADC being 8 bit. Accuracy increases as the error between reported value and real value becomes smaller when Vref is decreased.
          $endgroup$
          – Bimpelrekkie
          Apr 24 at 13:52










        • $begingroup$
          You mean 3-bit instead of 8 bit ?
          $endgroup$
          – atmnt
          Apr 24 at 13:53











        • $begingroup$
          You're right, 3 bit, 8 values
          $endgroup$
          – Bimpelrekkie
          Apr 24 at 13:56











        • $begingroup$
          I see. Just one more thing. If the Vref would remain the same but the ADC resolution was increased lets say to 6-bit from 3-bit; for that case can we say the precision gets better but accuracy remains the same? Or they both get better? I hope you have comment on this because this is very critical to clarify.
          $endgroup$
          – atmnt
          Apr 24 at 14:05








        1




        1




        $begingroup$
        I also thought similar but then saying "with greater accuracy" in that context is wrong correct? Better resolution causes better precision but not better accuracy.
        $endgroup$
        – atmnt
        Apr 24 at 13:48





        $begingroup$
        I also thought similar but then saying "with greater accuracy" in that context is wrong correct? Better resolution causes better precision but not better accuracy.
        $endgroup$
        – atmnt
        Apr 24 at 13:48













        $begingroup$
        It is the other way round, precision stays the same due to the ADC being 8 bit. Accuracy increases as the error between reported value and real value becomes smaller when Vref is decreased.
        $endgroup$
        – Bimpelrekkie
        Apr 24 at 13:52




        $begingroup$
        It is the other way round, precision stays the same due to the ADC being 8 bit. Accuracy increases as the error between reported value and real value becomes smaller when Vref is decreased.
        $endgroup$
        – Bimpelrekkie
        Apr 24 at 13:52












        $begingroup$
        You mean 3-bit instead of 8 bit ?
        $endgroup$
        – atmnt
        Apr 24 at 13:53





        $begingroup$
        You mean 3-bit instead of 8 bit ?
        $endgroup$
        – atmnt
        Apr 24 at 13:53













        $begingroup$
        You're right, 3 bit, 8 values
        $endgroup$
        – Bimpelrekkie
        Apr 24 at 13:56





        $begingroup$
        You're right, 3 bit, 8 values
        $endgroup$
        – Bimpelrekkie
        Apr 24 at 13:56













        $begingroup$
        I see. Just one more thing. If the Vref would remain the same but the ADC resolution was increased lets say to 6-bit from 3-bit; for that case can we say the precision gets better but accuracy remains the same? Or they both get better? I hope you have comment on this because this is very critical to clarify.
        $endgroup$
        – atmnt
        Apr 24 at 14:05





        $begingroup$
        I see. Just one more thing. If the Vref would remain the same but the ADC resolution was increased lets say to 6-bit from 3-bit; for that case can we say the precision gets better but accuracy remains the same? Or they both get better? I hope you have comment on this because this is very critical to clarify.
        $endgroup$
        – atmnt
        Apr 24 at 14:05














        5












        $begingroup$


        Isn't it wrong to say "with greater accuracy"? Shouldn't it be "with greater precision" instead?




        Oh, good. Someone who knows the difference.



        To some extent, yes, with greater accuracy. But probably not by the ratio that you reduced the reference voltage, and to a diminishing amount as you do so. Some of the error sources in an ADC are in the front end, and basically reflect back as a voltage on the input. But -- mostly for SAR ADCs -- some of the error sources in an ADC are in the conversion itself.



        A vastly simplified description of the operation of a SAR converter is that it makes educated guesses at the answer, applies them to a DAC, and compares the resulting analog signal to the input. Nonlinearity (incremental and integral) of an ADC is almost entirely from the built-in DAC, and reducing the reference voltage should reduce the magnitude of those errors proportionally.






        share|improve this answer









        $endgroup$

















          5












          $begingroup$


          Isn't it wrong to say "with greater accuracy"? Shouldn't it be "with greater precision" instead?




          Oh, good. Someone who knows the difference.



          To some extent, yes, with greater accuracy. But probably not by the ratio that you reduced the reference voltage, and to a diminishing amount as you do so. Some of the error sources in an ADC are in the front end, and basically reflect back as a voltage on the input. But -- mostly for SAR ADCs -- some of the error sources in an ADC are in the conversion itself.



          A vastly simplified description of the operation of a SAR converter is that it makes educated guesses at the answer, applies them to a DAC, and compares the resulting analog signal to the input. Nonlinearity (incremental and integral) of an ADC is almost entirely from the built-in DAC, and reducing the reference voltage should reduce the magnitude of those errors proportionally.






          share|improve this answer









          $endgroup$















            5












            5








            5





            $begingroup$


            Isn't it wrong to say "with greater accuracy"? Shouldn't it be "with greater precision" instead?




            Oh, good. Someone who knows the difference.



            To some extent, yes, with greater accuracy. But probably not by the ratio that you reduced the reference voltage, and to a diminishing amount as you do so. Some of the error sources in an ADC are in the front end, and basically reflect back as a voltage on the input. But -- mostly for SAR ADCs -- some of the error sources in an ADC are in the conversion itself.



            A vastly simplified description of the operation of a SAR converter is that it makes educated guesses at the answer, applies them to a DAC, and compares the resulting analog signal to the input. Nonlinearity (incremental and integral) of an ADC is almost entirely from the built-in DAC, and reducing the reference voltage should reduce the magnitude of those errors proportionally.






            share|improve this answer









            $endgroup$




            Isn't it wrong to say "with greater accuracy"? Shouldn't it be "with greater precision" instead?




            Oh, good. Someone who knows the difference.



            To some extent, yes, with greater accuracy. But probably not by the ratio that you reduced the reference voltage, and to a diminishing amount as you do so. Some of the error sources in an ADC are in the front end, and basically reflect back as a voltage on the input. But -- mostly for SAR ADCs -- some of the error sources in an ADC are in the conversion itself.



            A vastly simplified description of the operation of a SAR converter is that it makes educated guesses at the answer, applies them to a DAC, and compares the resulting analog signal to the input. Nonlinearity (incremental and integral) of an ADC is almost entirely from the built-in DAC, and reducing the reference voltage should reduce the magnitude of those errors proportionally.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Apr 24 at 14:54









            TimWescottTimWescott

            7,2591416




            7,2591416





















                3












                $begingroup$

                Reducing the reference voltage simply means that the size of the "steps" between digital values is reduced. This increases the resolution of the converter at the cost of range, but if the measurement range is similarly constrained, then the increased resolution is a benefit.



                I would not expect changing the reference voltage to have an impact on accuracy, except that in some cases when you set the reference voltage at or near the supply voltage, then the linearity at the top end of the range may suffer in some cases (this is probably more an issue with DACs than ADCs though).



                Accuracy in ADCs or DACs has 3 components: offset, linearity and noise. Offset is, effectively, the difference between zero volts and whatever voltage actually results in a zero reading. Linearity is the consistency of the step size across the entire digital range. Noise is how much change you can expect with the same input read multiple times in succession. I wouldn't expect changing the reference voltage to impact any of these except linearity, as I said before.






                share|improve this answer











                $endgroup$

















                  3












                  $begingroup$

                  Reducing the reference voltage simply means that the size of the "steps" between digital values is reduced. This increases the resolution of the converter at the cost of range, but if the measurement range is similarly constrained, then the increased resolution is a benefit.



                  I would not expect changing the reference voltage to have an impact on accuracy, except that in some cases when you set the reference voltage at or near the supply voltage, then the linearity at the top end of the range may suffer in some cases (this is probably more an issue with DACs than ADCs though).



                  Accuracy in ADCs or DACs has 3 components: offset, linearity and noise. Offset is, effectively, the difference between zero volts and whatever voltage actually results in a zero reading. Linearity is the consistency of the step size across the entire digital range. Noise is how much change you can expect with the same input read multiple times in succession. I wouldn't expect changing the reference voltage to impact any of these except linearity, as I said before.






                  share|improve this answer











                  $endgroup$















                    3












                    3








                    3





                    $begingroup$

                    Reducing the reference voltage simply means that the size of the "steps" between digital values is reduced. This increases the resolution of the converter at the cost of range, but if the measurement range is similarly constrained, then the increased resolution is a benefit.



                    I would not expect changing the reference voltage to have an impact on accuracy, except that in some cases when you set the reference voltage at or near the supply voltage, then the linearity at the top end of the range may suffer in some cases (this is probably more an issue with DACs than ADCs though).



                    Accuracy in ADCs or DACs has 3 components: offset, linearity and noise. Offset is, effectively, the difference between zero volts and whatever voltage actually results in a zero reading. Linearity is the consistency of the step size across the entire digital range. Noise is how much change you can expect with the same input read multiple times in succession. I wouldn't expect changing the reference voltage to impact any of these except linearity, as I said before.






                    share|improve this answer











                    $endgroup$



                    Reducing the reference voltage simply means that the size of the "steps" between digital values is reduced. This increases the resolution of the converter at the cost of range, but if the measurement range is similarly constrained, then the increased resolution is a benefit.



                    I would not expect changing the reference voltage to have an impact on accuracy, except that in some cases when you set the reference voltage at or near the supply voltage, then the linearity at the top end of the range may suffer in some cases (this is probably more an issue with DACs than ADCs though).



                    Accuracy in ADCs or DACs has 3 components: offset, linearity and noise. Offset is, effectively, the difference between zero volts and whatever voltage actually results in a zero reading. Linearity is the consistency of the step size across the entire digital range. Noise is how much change you can expect with the same input read multiple times in succession. I wouldn't expect changing the reference voltage to impact any of these except linearity, as I said before.







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Apr 24 at 14:45

























                    answered Apr 24 at 14:39









                    nsayernsayer

                    541924




                    541924





















                        2












                        $begingroup$

                        With smaller Vref, the ADC's comparator will have smaller voltages to use in making decisions, thus the errors (the differential non-linearity) will change.



                        You will have the same # bits out, but the integral linearity and the differential linearity become unpredictable IMHO.



                        Additionally, the random noise and the power-supply-rejection become more important. If the successive-approximation is performed by charge-splitting etc, then the size of the capacitors (binary weighted?) matters. Using



                        Vnoise = sqrt (K * T /C)



                        you'll compute the TOTAL integrated random noise of a 10pF capacitor is 20 microVolts RMS, or about 130 microVolts PeakPeak at the 1PPM level. As the caps become smaller, say 0.1pF, the PeakPeak noise now is sqrt(10p/0.1p) or sqrt(100) or 10X more random noise, which is 1,300 microVolts.






                        share|improve this answer











                        $endgroup$

















                          2












                          $begingroup$

                          With smaller Vref, the ADC's comparator will have smaller voltages to use in making decisions, thus the errors (the differential non-linearity) will change.



                          You will have the same # bits out, but the integral linearity and the differential linearity become unpredictable IMHO.



                          Additionally, the random noise and the power-supply-rejection become more important. If the successive-approximation is performed by charge-splitting etc, then the size of the capacitors (binary weighted?) matters. Using



                          Vnoise = sqrt (K * T /C)



                          you'll compute the TOTAL integrated random noise of a 10pF capacitor is 20 microVolts RMS, or about 130 microVolts PeakPeak at the 1PPM level. As the caps become smaller, say 0.1pF, the PeakPeak noise now is sqrt(10p/0.1p) or sqrt(100) or 10X more random noise, which is 1,300 microVolts.






                          share|improve this answer











                          $endgroup$















                            2












                            2








                            2





                            $begingroup$

                            With smaller Vref, the ADC's comparator will have smaller voltages to use in making decisions, thus the errors (the differential non-linearity) will change.



                            You will have the same # bits out, but the integral linearity and the differential linearity become unpredictable IMHO.



                            Additionally, the random noise and the power-supply-rejection become more important. If the successive-approximation is performed by charge-splitting etc, then the size of the capacitors (binary weighted?) matters. Using



                            Vnoise = sqrt (K * T /C)



                            you'll compute the TOTAL integrated random noise of a 10pF capacitor is 20 microVolts RMS, or about 130 microVolts PeakPeak at the 1PPM level. As the caps become smaller, say 0.1pF, the PeakPeak noise now is sqrt(10p/0.1p) or sqrt(100) or 10X more random noise, which is 1,300 microVolts.






                            share|improve this answer











                            $endgroup$



                            With smaller Vref, the ADC's comparator will have smaller voltages to use in making decisions, thus the errors (the differential non-linearity) will change.



                            You will have the same # bits out, but the integral linearity and the differential linearity become unpredictable IMHO.



                            Additionally, the random noise and the power-supply-rejection become more important. If the successive-approximation is performed by charge-splitting etc, then the size of the capacitors (binary weighted?) matters. Using



                            Vnoise = sqrt (K * T /C)



                            you'll compute the TOTAL integrated random noise of a 10pF capacitor is 20 microVolts RMS, or about 130 microVolts PeakPeak at the 1PPM level. As the caps become smaller, say 0.1pF, the PeakPeak noise now is sqrt(10p/0.1p) or sqrt(100) or 10X more random noise, which is 1,300 microVolts.







                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited Apr 25 at 2:07

























                            answered Apr 24 at 16:29









                            analogsystemsrfanalogsystemsrf

                            16.5k2823




                            16.5k2823





















                                1












                                $begingroup$

                                Typically, the term "accuracy" refers to systematic part of the error, while "precision" refers to the random part:



                                enter image description here



                                Reducing the ADC range (by lowering the reference voltage) will increase the resolution and reduce the quantization noise (which is not systematic*), thus improving the absolute precision. However, this improvement will only be visible if the quantization noise is dominant: if another kind of significant random noise (e.g. from AC on the power supply line) is present, the improvement in precision will not be noticeable.



                                Accuracy (aka trueness) may also get better depending on the internal properties of the ADC. Non-linearity and gain errors are (usually) proportional to the reference voltage, so those absolute errors will typically be reduced, while the offset error may often not change. The overall change in accuracy will again depend on which of those errors is dominant.



                                According to Wikipedia, "accuracy" can be used to describe a combination of both random and systematic errors, so when both precision and trueness are improved, it's not wrong to say that the measurement has better accuracy.



                                (*) - quantization error actually depends on the signal, but it's a very useful assumption needed for the additive noise model, which is automatically holds when this error is relatively small. When the quantization noise is large, artificial random noise (dither) is often applied to make the additive noise model work.






                                share|improve this answer











                                $endgroup$








                                • 1




                                  $begingroup$
                                  Too clear an illustration to not Vote UP.
                                  $endgroup$
                                  – analogsystemsrf
                                  2 days ago















                                1












                                $begingroup$

                                Typically, the term "accuracy" refers to systematic part of the error, while "precision" refers to the random part:



                                enter image description here



                                Reducing the ADC range (by lowering the reference voltage) will increase the resolution and reduce the quantization noise (which is not systematic*), thus improving the absolute precision. However, this improvement will only be visible if the quantization noise is dominant: if another kind of significant random noise (e.g. from AC on the power supply line) is present, the improvement in precision will not be noticeable.



                                Accuracy (aka trueness) may also get better depending on the internal properties of the ADC. Non-linearity and gain errors are (usually) proportional to the reference voltage, so those absolute errors will typically be reduced, while the offset error may often not change. The overall change in accuracy will again depend on which of those errors is dominant.



                                According to Wikipedia, "accuracy" can be used to describe a combination of both random and systematic errors, so when both precision and trueness are improved, it's not wrong to say that the measurement has better accuracy.



                                (*) - quantization error actually depends on the signal, but it's a very useful assumption needed for the additive noise model, which is automatically holds when this error is relatively small. When the quantization noise is large, artificial random noise (dither) is often applied to make the additive noise model work.






                                share|improve this answer











                                $endgroup$








                                • 1




                                  $begingroup$
                                  Too clear an illustration to not Vote UP.
                                  $endgroup$
                                  – analogsystemsrf
                                  2 days ago













                                1












                                1








                                1





                                $begingroup$

                                Typically, the term "accuracy" refers to systematic part of the error, while "precision" refers to the random part:



                                enter image description here



                                Reducing the ADC range (by lowering the reference voltage) will increase the resolution and reduce the quantization noise (which is not systematic*), thus improving the absolute precision. However, this improvement will only be visible if the quantization noise is dominant: if another kind of significant random noise (e.g. from AC on the power supply line) is present, the improvement in precision will not be noticeable.



                                Accuracy (aka trueness) may also get better depending on the internal properties of the ADC. Non-linearity and gain errors are (usually) proportional to the reference voltage, so those absolute errors will typically be reduced, while the offset error may often not change. The overall change in accuracy will again depend on which of those errors is dominant.



                                According to Wikipedia, "accuracy" can be used to describe a combination of both random and systematic errors, so when both precision and trueness are improved, it's not wrong to say that the measurement has better accuracy.



                                (*) - quantization error actually depends on the signal, but it's a very useful assumption needed for the additive noise model, which is automatically holds when this error is relatively small. When the quantization noise is large, artificial random noise (dither) is often applied to make the additive noise model work.






                                share|improve this answer











                                $endgroup$



                                Typically, the term "accuracy" refers to systematic part of the error, while "precision" refers to the random part:



                                enter image description here



                                Reducing the ADC range (by lowering the reference voltage) will increase the resolution and reduce the quantization noise (which is not systematic*), thus improving the absolute precision. However, this improvement will only be visible if the quantization noise is dominant: if another kind of significant random noise (e.g. from AC on the power supply line) is present, the improvement in precision will not be noticeable.



                                Accuracy (aka trueness) may also get better depending on the internal properties of the ADC. Non-linearity and gain errors are (usually) proportional to the reference voltage, so those absolute errors will typically be reduced, while the offset error may often not change. The overall change in accuracy will again depend on which of those errors is dominant.



                                According to Wikipedia, "accuracy" can be used to describe a combination of both random and systematic errors, so when both precision and trueness are improved, it's not wrong to say that the measurement has better accuracy.



                                (*) - quantization error actually depends on the signal, but it's a very useful assumption needed for the additive noise model, which is automatically holds when this error is relatively small. When the quantization noise is large, artificial random noise (dither) is often applied to make the additive noise model work.







                                share|improve this answer














                                share|improve this answer



                                share|improve this answer








                                edited Apr 25 at 13:21

























                                answered Apr 25 at 12:13









                                Dmitry GrigoryevDmitry Grigoryev

                                18.6k22878




                                18.6k22878







                                • 1




                                  $begingroup$
                                  Too clear an illustration to not Vote UP.
                                  $endgroup$
                                  – analogsystemsrf
                                  2 days ago












                                • 1




                                  $begingroup$
                                  Too clear an illustration to not Vote UP.
                                  $endgroup$
                                  – analogsystemsrf
                                  2 days ago







                                1




                                1




                                $begingroup$
                                Too clear an illustration to not Vote UP.
                                $endgroup$
                                – analogsystemsrf
                                2 days ago




                                $begingroup$
                                Too clear an illustration to not Vote UP.
                                $endgroup$
                                – analogsystemsrf
                                2 days ago











                                0












                                $begingroup$

                                I believe that you simply don't have all of the information. It is certainly true that resolution and accuracy are two very different things. The absolute resolution or voltage resolution is directly a function of the converter's reference voltage. With $N$ bits, the voltage resolution is $V_ref/2^N$. The word precision is not a good choice in this discussion; its meaning is less well defined and generally refers more to the repeatability of a measurement.



                                However, I think what is missing from the one slide you show is that the accuracy of an ADC converter is typically specified as some number of bits rather than as an absolute voltage. The voltage equivalent of a "bit" is the amount of voltage change that would cause a change in one in the LSB of the converted value. This is sometimes called just $V_LSB$. So, if you change the reference voltage then the value of $V_LSB$ will also change and the relative accuracy of the converter remains the same. However, lower values of the reference voltage result in smaller values of $V_LSB$, so decreasing the reference voltage leads to a smaller absolute accuracy (in volts).






                                share|improve this answer











                                $endgroup$












                                • $begingroup$
                                  Your "precision is directly a function of the converter's reference voltage" does not match with the other answer which says the precision stays the same. There is still some confusion.
                                  $endgroup$
                                  – atmnt
                                  Apr 24 at 14:16











                                • $begingroup$
                                  You're right...but we shouldn't be using the word precision at all. We should be talking about the resolution of the converter. I will edit.
                                  $endgroup$
                                  – Elliot Alderson
                                  Apr 24 at 14:27















                                0












                                $begingroup$

                                I believe that you simply don't have all of the information. It is certainly true that resolution and accuracy are two very different things. The absolute resolution or voltage resolution is directly a function of the converter's reference voltage. With $N$ bits, the voltage resolution is $V_ref/2^N$. The word precision is not a good choice in this discussion; its meaning is less well defined and generally refers more to the repeatability of a measurement.



                                However, I think what is missing from the one slide you show is that the accuracy of an ADC converter is typically specified as some number of bits rather than as an absolute voltage. The voltage equivalent of a "bit" is the amount of voltage change that would cause a change in one in the LSB of the converted value. This is sometimes called just $V_LSB$. So, if you change the reference voltage then the value of $V_LSB$ will also change and the relative accuracy of the converter remains the same. However, lower values of the reference voltage result in smaller values of $V_LSB$, so decreasing the reference voltage leads to a smaller absolute accuracy (in volts).






                                share|improve this answer











                                $endgroup$












                                • $begingroup$
                                  Your "precision is directly a function of the converter's reference voltage" does not match with the other answer which says the precision stays the same. There is still some confusion.
                                  $endgroup$
                                  – atmnt
                                  Apr 24 at 14:16











                                • $begingroup$
                                  You're right...but we shouldn't be using the word precision at all. We should be talking about the resolution of the converter. I will edit.
                                  $endgroup$
                                  – Elliot Alderson
                                  Apr 24 at 14:27













                                0












                                0








                                0





                                $begingroup$

                                I believe that you simply don't have all of the information. It is certainly true that resolution and accuracy are two very different things. The absolute resolution or voltage resolution is directly a function of the converter's reference voltage. With $N$ bits, the voltage resolution is $V_ref/2^N$. The word precision is not a good choice in this discussion; its meaning is less well defined and generally refers more to the repeatability of a measurement.



                                However, I think what is missing from the one slide you show is that the accuracy of an ADC converter is typically specified as some number of bits rather than as an absolute voltage. The voltage equivalent of a "bit" is the amount of voltage change that would cause a change in one in the LSB of the converted value. This is sometimes called just $V_LSB$. So, if you change the reference voltage then the value of $V_LSB$ will also change and the relative accuracy of the converter remains the same. However, lower values of the reference voltage result in smaller values of $V_LSB$, so decreasing the reference voltage leads to a smaller absolute accuracy (in volts).






                                share|improve this answer











                                $endgroup$



                                I believe that you simply don't have all of the information. It is certainly true that resolution and accuracy are two very different things. The absolute resolution or voltage resolution is directly a function of the converter's reference voltage. With $N$ bits, the voltage resolution is $V_ref/2^N$. The word precision is not a good choice in this discussion; its meaning is less well defined and generally refers more to the repeatability of a measurement.



                                However, I think what is missing from the one slide you show is that the accuracy of an ADC converter is typically specified as some number of bits rather than as an absolute voltage. The voltage equivalent of a "bit" is the amount of voltage change that would cause a change in one in the LSB of the converted value. This is sometimes called just $V_LSB$. So, if you change the reference voltage then the value of $V_LSB$ will also change and the relative accuracy of the converter remains the same. However, lower values of the reference voltage result in smaller values of $V_LSB$, so decreasing the reference voltage leads to a smaller absolute accuracy (in volts).







                                share|improve this answer














                                share|improve this answer



                                share|improve this answer








                                edited Apr 24 at 14:31

























                                answered Apr 24 at 14:07









                                Elliot AldersonElliot Alderson

                                8,27021022




                                8,27021022











                                • $begingroup$
                                  Your "precision is directly a function of the converter's reference voltage" does not match with the other answer which says the precision stays the same. There is still some confusion.
                                  $endgroup$
                                  – atmnt
                                  Apr 24 at 14:16











                                • $begingroup$
                                  You're right...but we shouldn't be using the word precision at all. We should be talking about the resolution of the converter. I will edit.
                                  $endgroup$
                                  – Elliot Alderson
                                  Apr 24 at 14:27
















                                • $begingroup$
                                  Your "precision is directly a function of the converter's reference voltage" does not match with the other answer which says the precision stays the same. There is still some confusion.
                                  $endgroup$
                                  – atmnt
                                  Apr 24 at 14:16











                                • $begingroup$
                                  You're right...but we shouldn't be using the word precision at all. We should be talking about the resolution of the converter. I will edit.
                                  $endgroup$
                                  – Elliot Alderson
                                  Apr 24 at 14:27















                                $begingroup$
                                Your "precision is directly a function of the converter's reference voltage" does not match with the other answer which says the precision stays the same. There is still some confusion.
                                $endgroup$
                                – atmnt
                                Apr 24 at 14:16





                                $begingroup$
                                Your "precision is directly a function of the converter's reference voltage" does not match with the other answer which says the precision stays the same. There is still some confusion.
                                $endgroup$
                                – atmnt
                                Apr 24 at 14:16













                                $begingroup$
                                You're right...but we shouldn't be using the word precision at all. We should be talking about the resolution of the converter. I will edit.
                                $endgroup$
                                – Elliot Alderson
                                Apr 24 at 14:27




                                $begingroup$
                                You're right...but we shouldn't be using the word precision at all. We should be talking about the resolution of the converter. I will edit.
                                $endgroup$
                                – Elliot Alderson
                                Apr 24 at 14:27

















                                draft saved

                                draft discarded
















































                                Thanks for contributing an answer to Electrical Engineering Stack Exchange!


                                • Please be sure to answer the question. Provide details and share your research!

                                But avoid


                                • Asking for help, clarification, or responding to other answers.

                                • Making statements based on opinion; back them up with references or personal experience.

                                Use MathJax to format equations. MathJax reference.


                                To learn more, see our tips on writing great answers.




                                draft saved


                                draft discarded














                                StackExchange.ready(
                                function ()
                                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f435214%2fwould-reducing-the-reference-voltage-of-an-adc-have-any-effect-on-accuracy%23new-answer', 'question_page');

                                );

                                Post as a guest















                                Required, but never shown





















































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown

































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown







                                Popular posts from this blog

                                Bulk add to cart function issuecart vs. mini cart issue … rwd themeRedirect Add to cart button to cart pageAdd to cart issue - Magento 2.1The requested Payment Method is not available When creating an orderM2: reason add-to-cart might not function in production modeAdd to cart issue in some android devicesMagento 2 - custom price can not add to subtotal and grand total after add to cartAdd to cart codeIssue with my cart module on pdp and cart pages, just keeps spinningBulk price and quantity update using rest api

                                БиармияSxpst500bh2ntaf! 3h2r