Why does the nucleus not repel itself? [duplicate] Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) 2019 Moderator Election Q&A - Question CollectionProtons' repulsion within a nucleusWhy do electrons occupy the space around nuclei, and not collide with them?How positively charged protons remain glued to each other while they should repel each other out of nucleus?Why isn't Hydrogen's electron pulled into the nucleus?Why would two protons repel?About the flow of currentRelativistic explanation of attraction between two parallel currentsWhy do protons stay together in nucleus even though they are like charges?Why do protons in the atom need to communicate with electrons?What keeps quarks separate (strong force pulls, but what repels to equal out)replacing positive soup with neutral soup in plum pudding model after Rutherford gold foil experiment
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Why does the nucleus not repel itself? [duplicate]
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
2019 Moderator Election Q&A - Question CollectionProtons' repulsion within a nucleusWhy do electrons occupy the space around nuclei, and not collide with them?How positively charged protons remain glued to each other while they should repel each other out of nucleus?Why isn't Hydrogen's electron pulled into the nucleus?Why would two protons repel?About the flow of currentRelativistic explanation of attraction between two parallel currentsWhy do protons stay together in nucleus even though they are like charges?Why do protons in the atom need to communicate with electrons?What keeps quarks separate (strong force pulls, but what repels to equal out)replacing positive soup with neutral soup in plum pudding model after Rutherford gold foil experiment
$begingroup$
This question already has an answer here:
Protons' repulsion within a nucleus
3 answers
If the nucleus is densely positively charged, why don’t the protons in the nucleus repel from each other and move towards the orbiting electrons?
Because each proton is not only being repelled by the other protons, it is also being pulled by the oppositely charged electrons
Why don’t these conditions make the atomic model impossible? I understand that electrons are in energy levels start so cannot force their way into the nucleus, but why not the reverse?
electromagnetism forces nuclear-physics protons strong-force
edited Apr 12 at 8:02
Qmechanic♦
108k122001246
asked Apr 11 at 14:12
Ubaid HassanUbaid Hassan
37513
New contributor
Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
marked as duplicate by Qmechanic♦ Apr 12 at 8:05
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
$begingroup$
This question already has an answer here:
Protons' repulsion within a nucleus
3 answers
If the nucleus is densely positively charged, why don’t the protons in the nucleus repel from each other and move towards the orbiting electrons?
Because each proton is not only being repelled by the other protons, it is also being pulled by the oppositely charged electrons
Why don’t these conditions make the atomic model impossible? I understand that electrons are in energy levels start so cannot force their way into the nucleus, but why not the reverse?
electromagnetism forces nuclear-physics protons strong-force
edited Apr 12 at 8:02
Qmechanic♦
108k122001246
asked Apr 11 at 14:12
Ubaid HassanUbaid Hassan
37513
New contributor
Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
marked as duplicate by Qmechanic♦ Apr 12 at 8:05
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
$begingroup$
Possible duplicates: physics.stackexchange.com/q/9661/2451 and links therein.
$endgroup$
– Qmechanic♦
Apr 12 at 8:08
add a comment |
$begingroup$
This question already has an answer here:
Protons' repulsion within a nucleus
3 answers
If the nucleus is densely positively charged, why don’t the protons in the nucleus repel from each other and move towards the orbiting electrons?
Because each proton is not only being repelled by the other protons, it is also being pulled by the oppositely charged electrons
Why don’t these conditions make the atomic model impossible? I understand that electrons are in energy levels start so cannot force their way into the nucleus, but why not the reverse?
electromagnetism forces nuclear-physics protons strong-force
edited Apr 12 at 8:02
Qmechanic♦
108k122001246
asked Apr 11 at 14:12
Ubaid HassanUbaid Hassan
37513
New contributor
Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
This question already has an answer here:
Protons' repulsion within a nucleus
3 answers
If the nucleus is densely positively charged, why don’t the protons in the nucleus repel from each other and move towards the orbiting electrons?
Because each proton is not only being repelled by the other protons, it is also being pulled by the oppositely charged electrons
Why don’t these conditions make the atomic model impossible? I understand that electrons are in energy levels start so cannot force their way into the nucleus, but why not the reverse?
This question already has an answer here:
Protons' repulsion within a nucleus
3 answers
electromagnetism forces nuclear-physics protons strong-force
electromagnetism forces nuclear-physics protons strong-force
edited Apr 12 at 8:02
Qmechanic♦
108k122001246
asked Apr 11 at 14:12
Ubaid HassanUbaid Hassan
37513
New contributor
Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Apr 12 at 8:02
Qmechanic♦
108k122001246
asked Apr 11 at 14:12
Ubaid HassanUbaid Hassan
37513
New contributor
Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Apr 12 at 8:02
Qmechanic♦
108k122001246
edited Apr 12 at 8:02
Qmechanic♦
108k122001246
edited Apr 12 at 8:02
Qmechanic♦
108k122001246
108k122001246
asked Apr 11 at 14:12
Ubaid HassanUbaid Hassan
37513
New contributor
Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Apr 11 at 14:12
Ubaid HassanUbaid Hassan
37513
asked Apr 11 at 14:12
Ubaid HassanUbaid Hassan
37513
37513
New contributor
Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
marked as duplicate by Qmechanic♦ Apr 12 at 8:05
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Qmechanic♦ Apr 12 at 8:05
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
$begingroup$
Possible duplicates: physics.stackexchange.com/q/9661/2451 and links therein.
$endgroup$
– Qmechanic♦
Apr 12 at 8:08
add a comment |
$begingroup$
Possible duplicates: physics.stackexchange.com/q/9661/2451 and links therein.
$endgroup$
– Qmechanic♦
Apr 12 at 8:08
$begingroup$
Possible duplicates: physics.stackexchange.com/q/9661/2451 and links therein.
$endgroup$
– Qmechanic♦
Apr 12 at 8:08
$begingroup$
Possible duplicates: physics.stackexchange.com/q/9661/2451 and links therein.
$endgroup$
– Qmechanic♦
Apr 12 at 8:08
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
There is another fundamental force of nature apart from the electromagnetic and the gravitational force. This is the strong nuclear force. Its presence is in between the interactions of protons and neutrons themselves or between protons and neutrons.
Unfortunately, the strong force has no macroscopic effect as to feel the interaction themselves because the typical range where they are stronger than the electromagnetic interactions is at the range of femtometres ($10^-15 mathrm m$).
At such ranges, the strong force is stronger than the electromagnetic repulsion between the protons to hold them together.
As for your second question on the nucleus itself travelling to the electron, if you think in terms of the centre of mass, the nucleus has higher mass than the electron and so the centre of mass of the system would be closer to the nucleus than it is to the electron. But in this case, the centre of mass is probably within the nucleus itself which is why it is a feasible idea to say that the electron reveolves around the nucleus. Although it is correct to say that the electron revolves around the combined centre of mass of the system.
EDIT: There is something that I have to add on for completeness -
As @dmckee has pointed out in his comment, the strong nuclear force is not fundamental by itself (I apologise) but is instead the result of a fundamental strong nuclear interaction originating between the gluons and the quarks that constitute these protons and neutrons.
But essentially the strong nuclear force arises from this interaction. And hence the nucleus is stable from electromangetic repulsions due to the charge the protons carry.
answered Apr 11 at 14:26
KV18KV18
1,171516
$endgroup$
2
$begingroup$
It's not really correct to say the electron revolves around anything, really. This is the point at which things get Quantum.
$endgroup$
– Hearth
Apr 11 at 21:54
6
$begingroup$
The "strong nuclear force" is—arguably—not properly regarded as fundamental. The fundamental strong interaction binds quarks and gluons into hadrons. Long-lived hadrons (mostly the low mass baryons AKA the neutron and the proton) are then held into clusters by the "residual strong force" (AKA nuclear force or strong nuclear force). The nuclear force bears roughly the same relationship to the fundamental strong force that van~der~Waals inter-atomic forces do the electromagnetic binding of atoms: they are the relatively weak left-overs that results from imperfect cancellation.
$endgroup$
– dmckee♦
Apr 12 at 1:08
$begingroup$
The attraction is operative on the neighboring nucleons only, while electostatic repulsion is long-distance. The repulsion force, in any case is not so much weaker than the attraction maybe at most by a factor of 10, even close by. So once you have about 100 protons, the repulsion starts to exceed the attraction. That is why we have the Mendeleev periodic table of the elements which ends at atomic number 118.
$endgroup$
– Kostas
Apr 12 at 20:49
add a comment |
$begingroup$
The electrostatic repulsion force is long-distance, and the nuclear attraction is short-distance. So, protons do repel, and this is precisely what makes really large nuclei unstable.
Secondly, electrons in the S-wave orbital have nonzero wavefunction at the nucleus, so effectively they are able to penetrate into the nucleus, and that is what makes reverse-beta decay possible.
answered Apr 11 at 14:26
KostasKostas
41217
$endgroup$
1
$begingroup$
+1 for pointing out large nuclei suffer the effect the OP conjectured.
$endgroup$
– J.G.
Apr 11 at 21:40
add a comment |
$begingroup$
In navy nuke school, the analogy for the strong nuclear force was Velcro. I.e. attraction but at "touching" distances only.
The strong nuclear force is sort of like a "glue" of neutrons that hold multiproton nuclei together. There are certain ratios of neutron to proton amount than seem to work best. See this chart: https://en.wikipedia.org/wiki/File:Isotopes_and_half-life.svg Note the rough 1:1 pattern but with a bit more "neutron glue" needed as you get to heavier elements.
There are also patterns of odd/even preferences and "magic numbers" (filled nuclear shells) which shows things are more complicated than just the "glue" idea, even if that holds as a first level insight. See https://en.wikipedia.org/wiki/Even_and_odd_atomic_nuclei and https://en.wikipedia.org/wiki/Magic_number_(physics)
Electrons do enter the nucleus (have some wave function in there). They can get captured in a decay process called electron capture, albeit rarely. See http://wtamu.edu/~cbaird/sq/2013/08/08/why-dont-electrons-in-the-atom-enter-the-nucleus/
I would also point out that free neutrons are unstable: https://en.wikipedia.org/wiki/Neutron#Free_neutron_decay So, you probably don't need to worry about some sort of "electron capture death of the universe" where everything ends up neutrons.
answered Apr 11 at 22:40
guestguest
512
New contributor
guest is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
There is another fundamental force of nature apart from the electromagnetic and the gravitational force. This is the strong nuclear force. Its presence is in between the interactions of protons and neutrons themselves or between protons and neutrons.
Unfortunately, the strong force has no macroscopic effect as to feel the interaction themselves because the typical range where they are stronger than the electromagnetic interactions is at the range of femtometres ($10^-15 mathrm m$).
At such ranges, the strong force is stronger than the electromagnetic repulsion between the protons to hold them together.
As for your second question on the nucleus itself travelling to the electron, if you think in terms of the centre of mass, the nucleus has higher mass than the electron and so the centre of mass of the system would be closer to the nucleus than it is to the electron. But in this case, the centre of mass is probably within the nucleus itself which is why it is a feasible idea to say that the electron reveolves around the nucleus. Although it is correct to say that the electron revolves around the combined centre of mass of the system.
EDIT: There is something that I have to add on for completeness -
As @dmckee has pointed out in his comment, the strong nuclear force is not fundamental by itself (I apologise) but is instead the result of a fundamental strong nuclear interaction originating between the gluons and the quarks that constitute these protons and neutrons.
But essentially the strong nuclear force arises from this interaction. And hence the nucleus is stable from electromangetic repulsions due to the charge the protons carry.
answered Apr 11 at 14:26
KV18KV18
1,171516
$endgroup$
2
$begingroup$
It's not really correct to say the electron revolves around anything, really. This is the point at which things get Quantum.
$endgroup$
– Hearth
Apr 11 at 21:54
6
$begingroup$
The "strong nuclear force" is—arguably—not properly regarded as fundamental. The fundamental strong interaction binds quarks and gluons into hadrons. Long-lived hadrons (mostly the low mass baryons AKA the neutron and the proton) are then held into clusters by the "residual strong force" (AKA nuclear force or strong nuclear force). The nuclear force bears roughly the same relationship to the fundamental strong force that van~der~Waals inter-atomic forces do the electromagnetic binding of atoms: they are the relatively weak left-overs that results from imperfect cancellation.
$endgroup$
– dmckee♦
Apr 12 at 1:08
$begingroup$
The attraction is operative on the neighboring nucleons only, while electostatic repulsion is long-distance. The repulsion force, in any case is not so much weaker than the attraction maybe at most by a factor of 10, even close by. So once you have about 100 protons, the repulsion starts to exceed the attraction. That is why we have the Mendeleev periodic table of the elements which ends at atomic number 118.
$endgroup$
– Kostas
Apr 12 at 20:49
add a comment |
$begingroup$
There is another fundamental force of nature apart from the electromagnetic and the gravitational force. This is the strong nuclear force. Its presence is in between the interactions of protons and neutrons themselves or between protons and neutrons.
Unfortunately, the strong force has no macroscopic effect as to feel the interaction themselves because the typical range where they are stronger than the electromagnetic interactions is at the range of femtometres ($10^-15 mathrm m$).
At such ranges, the strong force is stronger than the electromagnetic repulsion between the protons to hold them together.
As for your second question on the nucleus itself travelling to the electron, if you think in terms of the centre of mass, the nucleus has higher mass than the electron and so the centre of mass of the system would be closer to the nucleus than it is to the electron. But in this case, the centre of mass is probably within the nucleus itself which is why it is a feasible idea to say that the electron reveolves around the nucleus. Although it is correct to say that the electron revolves around the combined centre of mass of the system.
EDIT: There is something that I have to add on for completeness -
As @dmckee has pointed out in his comment, the strong nuclear force is not fundamental by itself (I apologise) but is instead the result of a fundamental strong nuclear interaction originating between the gluons and the quarks that constitute these protons and neutrons.
But essentially the strong nuclear force arises from this interaction. And hence the nucleus is stable from electromangetic repulsions due to the charge the protons carry.
answered Apr 11 at 14:26
KV18KV18
1,171516
$endgroup$
2
$begingroup$
It's not really correct to say the electron revolves around anything, really. This is the point at which things get Quantum.
$endgroup$
– Hearth
Apr 11 at 21:54
6
$begingroup$
The "strong nuclear force" is—arguably—not properly regarded as fundamental. The fundamental strong interaction binds quarks and gluons into hadrons. Long-lived hadrons (mostly the low mass baryons AKA the neutron and the proton) are then held into clusters by the "residual strong force" (AKA nuclear force or strong nuclear force). The nuclear force bears roughly the same relationship to the fundamental strong force that van~der~Waals inter-atomic forces do the electromagnetic binding of atoms: they are the relatively weak left-overs that results from imperfect cancellation.
$endgroup$
– dmckee♦
Apr 12 at 1:08
$begingroup$
The attraction is operative on the neighboring nucleons only, while electostatic repulsion is long-distance. The repulsion force, in any case is not so much weaker than the attraction maybe at most by a factor of 10, even close by. So once you have about 100 protons, the repulsion starts to exceed the attraction. That is why we have the Mendeleev periodic table of the elements which ends at atomic number 118.
$endgroup$
– Kostas
Apr 12 at 20:49
add a comment |
$begingroup$
There is another fundamental force of nature apart from the electromagnetic and the gravitational force. This is the strong nuclear force. Its presence is in between the interactions of protons and neutrons themselves or between protons and neutrons.
Unfortunately, the strong force has no macroscopic effect as to feel the interaction themselves because the typical range where they are stronger than the electromagnetic interactions is at the range of femtometres ($10^-15 mathrm m$).
At such ranges, the strong force is stronger than the electromagnetic repulsion between the protons to hold them together.
As for your second question on the nucleus itself travelling to the electron, if you think in terms of the centre of mass, the nucleus has higher mass than the electron and so the centre of mass of the system would be closer to the nucleus than it is to the electron. But in this case, the centre of mass is probably within the nucleus itself which is why it is a feasible idea to say that the electron reveolves around the nucleus. Although it is correct to say that the electron revolves around the combined centre of mass of the system.
EDIT: There is something that I have to add on for completeness -
As @dmckee has pointed out in his comment, the strong nuclear force is not fundamental by itself (I apologise) but is instead the result of a fundamental strong nuclear interaction originating between the gluons and the quarks that constitute these protons and neutrons.
But essentially the strong nuclear force arises from this interaction. And hence the nucleus is stable from electromangetic repulsions due to the charge the protons carry.
answered Apr 11 at 14:26
KV18KV18
1,171516
$endgroup$
There is another fundamental force of nature apart from the electromagnetic and the gravitational force. This is the strong nuclear force. Its presence is in between the interactions of protons and neutrons themselves or between protons and neutrons.
Unfortunately, the strong force has no macroscopic effect as to feel the interaction themselves because the typical range where they are stronger than the electromagnetic interactions is at the range of femtometres ($10^-15 mathrm m$).
At such ranges, the strong force is stronger than the electromagnetic repulsion between the protons to hold them together.
As for your second question on the nucleus itself travelling to the electron, if you think in terms of the centre of mass, the nucleus has higher mass than the electron and so the centre of mass of the system would be closer to the nucleus than it is to the electron. But in this case, the centre of mass is probably within the nucleus itself which is why it is a feasible idea to say that the electron reveolves around the nucleus. Although it is correct to say that the electron revolves around the combined centre of mass of the system.
EDIT: There is something that I have to add on for completeness -
As @dmckee has pointed out in his comment, the strong nuclear force is not fundamental by itself (I apologise) but is instead the result of a fundamental strong nuclear interaction originating between the gluons and the quarks that constitute these protons and neutrons.
But essentially the strong nuclear force arises from this interaction. And hence the nucleus is stable from electromangetic repulsions due to the charge the protons carry.
answered Apr 11 at 14:26
KV18KV18
1,171516
edited Apr 12 at 8:14
answered Apr 11 at 14:26
KV18KV18
1,171516
answered Apr 11 at 14:26
KV18KV18
1,171516
answered Apr 11 at 14:26
KV18KV18
1,171516
1,171516
2
$begingroup$
It's not really correct to say the electron revolves around anything, really. This is the point at which things get Quantum.
$endgroup$
– Hearth
Apr 11 at 21:54
6
$begingroup$
The "strong nuclear force" is—arguably—not properly regarded as fundamental. The fundamental strong interaction binds quarks and gluons into hadrons. Long-lived hadrons (mostly the low mass baryons AKA the neutron and the proton) are then held into clusters by the "residual strong force" (AKA nuclear force or strong nuclear force). The nuclear force bears roughly the same relationship to the fundamental strong force that van~der~Waals inter-atomic forces do the electromagnetic binding of atoms: they are the relatively weak left-overs that results from imperfect cancellation.
$endgroup$
– dmckee♦
Apr 12 at 1:08
$begingroup$
The attraction is operative on the neighboring nucleons only, while electostatic repulsion is long-distance. The repulsion force, in any case is not so much weaker than the attraction maybe at most by a factor of 10, even close by. So once you have about 100 protons, the repulsion starts to exceed the attraction. That is why we have the Mendeleev periodic table of the elements which ends at atomic number 118.
$endgroup$
– Kostas
Apr 12 at 20:49
add a comment |
2
$begingroup$
It's not really correct to say the electron revolves around anything, really. This is the point at which things get Quantum.
$endgroup$
– Hearth
Apr 11 at 21:54
6
$begingroup$
The "strong nuclear force" is—arguably—not properly regarded as fundamental. The fundamental strong interaction binds quarks and gluons into hadrons. Long-lived hadrons (mostly the low mass baryons AKA the neutron and the proton) are then held into clusters by the "residual strong force" (AKA nuclear force or strong nuclear force). The nuclear force bears roughly the same relationship to the fundamental strong force that van~der~Waals inter-atomic forces do the electromagnetic binding of atoms: they are the relatively weak left-overs that results from imperfect cancellation.
$endgroup$
– dmckee♦
Apr 12 at 1:08
$begingroup$
The attraction is operative on the neighboring nucleons only, while electostatic repulsion is long-distance. The repulsion force, in any case is not so much weaker than the attraction maybe at most by a factor of 10, even close by. So once you have about 100 protons, the repulsion starts to exceed the attraction. That is why we have the Mendeleev periodic table of the elements which ends at atomic number 118.
$endgroup$
– Kostas
Apr 12 at 20:49
2
2
$begingroup$
It's not really correct to say the electron revolves around anything, really. This is the point at which things get Quantum.
$endgroup$
– Hearth
Apr 11 at 21:54
$begingroup$
It's not really correct to say the electron revolves around anything, really. This is the point at which things get Quantum.
$endgroup$
– Hearth
Apr 11 at 21:54
6
6
$begingroup$
The "strong nuclear force" is—arguably—not properly regarded as fundamental. The fundamental strong interaction binds quarks and gluons into hadrons. Long-lived hadrons (mostly the low mass baryons AKA the neutron and the proton) are then held into clusters by the "residual strong force" (AKA nuclear force or strong nuclear force). The nuclear force bears roughly the same relationship to the fundamental strong force that van~der~Waals inter-atomic forces do the electromagnetic binding of atoms: they are the relatively weak left-overs that results from imperfect cancellation.
$endgroup$
– dmckee♦
Apr 12 at 1:08
$begingroup$
The "strong nuclear force" is—arguably—not properly regarded as fundamental. The fundamental strong interaction binds quarks and gluons into hadrons. Long-lived hadrons (mostly the low mass baryons AKA the neutron and the proton) are then held into clusters by the "residual strong force" (AKA nuclear force or strong nuclear force). The nuclear force bears roughly the same relationship to the fundamental strong force that van~der~Waals inter-atomic forces do the electromagnetic binding of atoms: they are the relatively weak left-overs that results from imperfect cancellation.
$endgroup$
– dmckee♦
Apr 12 at 1:08
$begingroup$
The attraction is operative on the neighboring nucleons only, while electostatic repulsion is long-distance. The repulsion force, in any case is not so much weaker than the attraction maybe at most by a factor of 10, even close by. So once you have about 100 protons, the repulsion starts to exceed the attraction. That is why we have the Mendeleev periodic table of the elements which ends at atomic number 118.
$endgroup$
– Kostas
Apr 12 at 20:49
$begingroup$
The attraction is operative on the neighboring nucleons only, while electostatic repulsion is long-distance. The repulsion force, in any case is not so much weaker than the attraction maybe at most by a factor of 10, even close by. So once you have about 100 protons, the repulsion starts to exceed the attraction. That is why we have the Mendeleev periodic table of the elements which ends at atomic number 118.
$endgroup$
– Kostas
Apr 12 at 20:49
add a comment |
$begingroup$
The electrostatic repulsion force is long-distance, and the nuclear attraction is short-distance. So, protons do repel, and this is precisely what makes really large nuclei unstable.
Secondly, electrons in the S-wave orbital have nonzero wavefunction at the nucleus, so effectively they are able to penetrate into the nucleus, and that is what makes reverse-beta decay possible.
answered Apr 11 at 14:26
KostasKostas
41217
$endgroup$
1
$begingroup$
+1 for pointing out large nuclei suffer the effect the OP conjectured.
$endgroup$
– J.G.
Apr 11 at 21:40
add a comment |
$begingroup$
The electrostatic repulsion force is long-distance, and the nuclear attraction is short-distance. So, protons do repel, and this is precisely what makes really large nuclei unstable.
Secondly, electrons in the S-wave orbital have nonzero wavefunction at the nucleus, so effectively they are able to penetrate into the nucleus, and that is what makes reverse-beta decay possible.
answered Apr 11 at 14:26
KostasKostas
41217
$endgroup$
1
$begingroup$
+1 for pointing out large nuclei suffer the effect the OP conjectured.
$endgroup$
– J.G.
Apr 11 at 21:40
add a comment |
$begingroup$
The electrostatic repulsion force is long-distance, and the nuclear attraction is short-distance. So, protons do repel, and this is precisely what makes really large nuclei unstable.
Secondly, electrons in the S-wave orbital have nonzero wavefunction at the nucleus, so effectively they are able to penetrate into the nucleus, and that is what makes reverse-beta decay possible.
answered Apr 11 at 14:26
KostasKostas
41217
$endgroup$
The electrostatic repulsion force is long-distance, and the nuclear attraction is short-distance. So, protons do repel, and this is precisely what makes really large nuclei unstable.
Secondly, electrons in the S-wave orbital have nonzero wavefunction at the nucleus, so effectively they are able to penetrate into the nucleus, and that is what makes reverse-beta decay possible.
answered Apr 11 at 14:26
KostasKostas
41217
answered Apr 11 at 14:26
KostasKostas
41217
answered Apr 11 at 14:26
KostasKostas
41217
answered Apr 11 at 14:26
KostasKostas
41217
41217
1
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+1 for pointing out large nuclei suffer the effect the OP conjectured.
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– J.G.
Apr 11 at 21:40
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1
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+1 for pointing out large nuclei suffer the effect the OP conjectured.
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– J.G.
Apr 11 at 21:40
1
1
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+1 for pointing out large nuclei suffer the effect the OP conjectured.
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– J.G.
Apr 11 at 21:40
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+1 for pointing out large nuclei suffer the effect the OP conjectured.
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– J.G.
Apr 11 at 21:40
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In navy nuke school, the analogy for the strong nuclear force was Velcro. I.e. attraction but at "touching" distances only.
The strong nuclear force is sort of like a "glue" of neutrons that hold multiproton nuclei together. There are certain ratios of neutron to proton amount than seem to work best. See this chart: https://en.wikipedia.org/wiki/File:Isotopes_and_half-life.svg Note the rough 1:1 pattern but with a bit more "neutron glue" needed as you get to heavier elements.
There are also patterns of odd/even preferences and "magic numbers" (filled nuclear shells) which shows things are more complicated than just the "glue" idea, even if that holds as a first level insight. See https://en.wikipedia.org/wiki/Even_and_odd_atomic_nuclei and https://en.wikipedia.org/wiki/Magic_number_(physics)
Electrons do enter the nucleus (have some wave function in there). They can get captured in a decay process called electron capture, albeit rarely. See http://wtamu.edu/~cbaird/sq/2013/08/08/why-dont-electrons-in-the-atom-enter-the-nucleus/
I would also point out that free neutrons are unstable: https://en.wikipedia.org/wiki/Neutron#Free_neutron_decay So, you probably don't need to worry about some sort of "electron capture death of the universe" where everything ends up neutrons.
answered Apr 11 at 22:40
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In navy nuke school, the analogy for the strong nuclear force was Velcro. I.e. attraction but at "touching" distances only.
The strong nuclear force is sort of like a "glue" of neutrons that hold multiproton nuclei together. There are certain ratios of neutron to proton amount than seem to work best. See this chart: https://en.wikipedia.org/wiki/File:Isotopes_and_half-life.svg Note the rough 1:1 pattern but with a bit more "neutron glue" needed as you get to heavier elements.
There are also patterns of odd/even preferences and "magic numbers" (filled nuclear shells) which shows things are more complicated than just the "glue" idea, even if that holds as a first level insight. See https://en.wikipedia.org/wiki/Even_and_odd_atomic_nuclei and https://en.wikipedia.org/wiki/Magic_number_(physics)
Electrons do enter the nucleus (have some wave function in there). They can get captured in a decay process called electron capture, albeit rarely. See http://wtamu.edu/~cbaird/sq/2013/08/08/why-dont-electrons-in-the-atom-enter-the-nucleus/
I would also point out that free neutrons are unstable: https://en.wikipedia.org/wiki/Neutron#Free_neutron_decay So, you probably don't need to worry about some sort of "electron capture death of the universe" where everything ends up neutrons.
answered Apr 11 at 22:40
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In navy nuke school, the analogy for the strong nuclear force was Velcro. I.e. attraction but at "touching" distances only.
The strong nuclear force is sort of like a "glue" of neutrons that hold multiproton nuclei together. There are certain ratios of neutron to proton amount than seem to work best. See this chart: https://en.wikipedia.org/wiki/File:Isotopes_and_half-life.svg Note the rough 1:1 pattern but with a bit more "neutron glue" needed as you get to heavier elements.
There are also patterns of odd/even preferences and "magic numbers" (filled nuclear shells) which shows things are more complicated than just the "glue" idea, even if that holds as a first level insight. See https://en.wikipedia.org/wiki/Even_and_odd_atomic_nuclei and https://en.wikipedia.org/wiki/Magic_number_(physics)
Electrons do enter the nucleus (have some wave function in there). They can get captured in a decay process called electron capture, albeit rarely. See http://wtamu.edu/~cbaird/sq/2013/08/08/why-dont-electrons-in-the-atom-enter-the-nucleus/
I would also point out that free neutrons are unstable: https://en.wikipedia.org/wiki/Neutron#Free_neutron_decay So, you probably don't need to worry about some sort of "electron capture death of the universe" where everything ends up neutrons.
answered Apr 11 at 22:40
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In navy nuke school, the analogy for the strong nuclear force was Velcro. I.e. attraction but at "touching" distances only.
The strong nuclear force is sort of like a "glue" of neutrons that hold multiproton nuclei together. There are certain ratios of neutron to proton amount than seem to work best. See this chart: https://en.wikipedia.org/wiki/File:Isotopes_and_half-life.svg Note the rough 1:1 pattern but with a bit more "neutron glue" needed as you get to heavier elements.
There are also patterns of odd/even preferences and "magic numbers" (filled nuclear shells) which shows things are more complicated than just the "glue" idea, even if that holds as a first level insight. See https://en.wikipedia.org/wiki/Even_and_odd_atomic_nuclei and https://en.wikipedia.org/wiki/Magic_number_(physics)
Electrons do enter the nucleus (have some wave function in there). They can get captured in a decay process called electron capture, albeit rarely. See http://wtamu.edu/~cbaird/sq/2013/08/08/why-dont-electrons-in-the-atom-enter-the-nucleus/
I would also point out that free neutrons are unstable: https://en.wikipedia.org/wiki/Neutron#Free_neutron_decay So, you probably don't need to worry about some sort of "electron capture death of the universe" where everything ends up neutrons.
answered Apr 11 at 22:40
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edited Apr 11 at 22:55
answered Apr 11 at 22:40
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answered Apr 11 at 22:40
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answered Apr 11 at 22:40
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New contributor
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Possible duplicates: physics.stackexchange.com/q/9661/2451 and links therein.
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– Qmechanic♦
Apr 12 at 8:08