Sending ajax POST data to controllersending information from one controller to anotherTrying to run an AJAX script from the admin area in magentoHow to send a form key with post data using ajax to a controller in magento?jQuery ajax data to controllerMagento ajax form does not post dataCall an external URL and post data to it (same as an HTML form does) from a controllerAJAX login, how to pass data response from controller to jQuery with AjaxMagento 2.2.4 : post data in urlMagento 2 AJAX Post to another module's controller
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Sending ajax POST data to controller
sending information from one controller to anotherTrying to run an AJAX script from the admin area in magentoHow to send a form key with post data using ajax to a controller in magento?jQuery ajax data to controllerMagento ajax form does not post dataCall an external URL and post data to it (same as an HTML form does) from a controllerAJAX login, how to pass data response from controller to jQuery with AjaxMagento 2.2.4 : post data in urlMagento 2 AJAX Post to another module's controller
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
This is my ajax request:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function()
$(".emailfocusout").focusout(function()
$.ajax(
url: '/checkout/Email/Email',
type: 'POST',
data: 'email': 'che607@yahoo.com',
contentType: 'application/json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
);
);
</script>
This is my controller:
public function EmailAction()
// TODO: Implement me! Here are some hints ;-)
$email = $this->getRequest()->getParam('email');
var_dump($email);
echo $email;
I can't save - data: 'email': 'che607@yahoo.com' - to - $email = $this->getRequest()->getParam('email');
What am I doing wrong?
* UPDATE - SOLVED *
I took data out of the ajax request. And in URL I put:
url: '/checkout/Email/Email/email/me@example.com',
I worked like that.
controllers ajax post-data
edited Nov 19 '18 at 15:12
Abhishek Panchal
3,6203929
asked Aug 5 '18 at 16:16
Che FigueroaChe Figueroa
112
add a comment |
This is my ajax request:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function()
$(".emailfocusout").focusout(function()
$.ajax(
url: '/checkout/Email/Email',
type: 'POST',
data: 'email': 'che607@yahoo.com',
contentType: 'application/json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
);
);
</script>
This is my controller:
public function EmailAction()
// TODO: Implement me! Here are some hints ;-)
$email = $this->getRequest()->getParam('email');
var_dump($email);
echo $email;
I can't save - data: 'email': 'che607@yahoo.com' - to - $email = $this->getRequest()->getParam('email');
What am I doing wrong?
* UPDATE - SOLVED *
I took data out of the ajax request. And in URL I put:
url: '/checkout/Email/Email/email/me@example.com',
I worked like that.
controllers ajax post-data
edited Nov 19 '18 at 15:12
Abhishek Panchal
3,6203929
asked Aug 5 '18 at 16:16
Che FigueroaChe Figueroa
112
can you please upload your model file or database install script?
– Rohan Hapani
Aug 5 '18 at 16:24
Do you getting data in controller?
– Prashant Valanda
Aug 5 '18 at 18:35
add a comment |
This is my ajax request:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function()
$(".emailfocusout").focusout(function()
$.ajax(
url: '/checkout/Email/Email',
type: 'POST',
data: 'email': 'che607@yahoo.com',
contentType: 'application/json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
);
);
</script>
This is my controller:
public function EmailAction()
// TODO: Implement me! Here are some hints ;-)
$email = $this->getRequest()->getParam('email');
var_dump($email);
echo $email;
I can't save - data: 'email': 'che607@yahoo.com' - to - $email = $this->getRequest()->getParam('email');
What am I doing wrong?
* UPDATE - SOLVED *
I took data out of the ajax request. And in URL I put:
url: '/checkout/Email/Email/email/me@example.com',
I worked like that.
controllers ajax post-data
edited Nov 19 '18 at 15:12
Abhishek Panchal
3,6203929
asked Aug 5 '18 at 16:16
Che FigueroaChe Figueroa
112
This is my ajax request:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function()
$(".emailfocusout").focusout(function()
$.ajax(
url: '/checkout/Email/Email',
type: 'POST',
data: 'email': 'che607@yahoo.com',
contentType: 'application/json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
);
);
</script>
This is my controller:
public function EmailAction()
// TODO: Implement me! Here are some hints ;-)
$email = $this->getRequest()->getParam('email');
var_dump($email);
echo $email;
I can't save - data: 'email': 'che607@yahoo.com' - to - $email = $this->getRequest()->getParam('email');
What am I doing wrong?
* UPDATE - SOLVED *
I took data out of the ajax request. And in URL I put:
url: '/checkout/Email/Email/email/me@example.com',
I worked like that.
controllers ajax post-data
controllers ajax post-data
edited Nov 19 '18 at 15:12
Abhishek Panchal
3,6203929
asked Aug 5 '18 at 16:16
Che FigueroaChe Figueroa
112
edited Nov 19 '18 at 15:12
Abhishek Panchal
3,6203929
asked Aug 5 '18 at 16:16
Che FigueroaChe Figueroa
112
edited Nov 19 '18 at 15:12
Abhishek Panchal
3,6203929
edited Nov 19 '18 at 15:12
Abhishek Panchal
3,6203929
edited Nov 19 '18 at 15:12
Abhishek Panchal
3,6203929
3,6203929
asked Aug 5 '18 at 16:16
Che FigueroaChe Figueroa
112
asked Aug 5 '18 at 16:16
Che FigueroaChe Figueroa
112
asked Aug 5 '18 at 16:16
Che FigueroaChe Figueroa
112
112
can you please upload your model file or database install script?
– Rohan Hapani
Aug 5 '18 at 16:24
Do you getting data in controller?
– Prashant Valanda
Aug 5 '18 at 18:35
add a comment |
can you please upload your model file or database install script?
– Rohan Hapani
Aug 5 '18 at 16:24
Do you getting data in controller?
– Prashant Valanda
Aug 5 '18 at 18:35
can you please upload your model file or database install script?
– Rohan Hapani
Aug 5 '18 at 16:24
can you please upload your model file or database install script?
– Rohan Hapani
Aug 5 '18 at 16:24
Do you getting data in controller?
– Prashant Valanda
Aug 5 '18 at 18:35
Do you getting data in controller?
– Prashant Valanda
Aug 5 '18 at 18:35
add a comment |
2 Answers
2
active
oldest
votes
just use only
data: 'email=me@example.com',
and if you want to send dynamic email value use
data:'email='+$("input[name='email']").val(),
edited Aug 5 '18 at 20:04
Marius♦
168k28324694
answered Aug 5 '18 at 16:27
Ansar HusainAnsar Husain
1,773218
add a comment |
Change this,
$.ajax(
url: '/checkout/Email/Email',
type: 'POST',
data: 'email': 'che607@yahoo.com',
contentType: 'application/json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
to
$.ajax(
type: 'POST',
url: '/checkout/Email/Email',
data: 'email': 'che607@yahoo.com',
dataType: 'json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
answered Aug 6 '18 at 7:20
Anjali PatilAnjali Patil
64
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
just use only
data: 'email=me@example.com',
and if you want to send dynamic email value use
data:'email='+$("input[name='email']").val(),
edited Aug 5 '18 at 20:04
Marius♦
168k28324694
answered Aug 5 '18 at 16:27
Ansar HusainAnsar Husain
1,773218
add a comment |
just use only
data: 'email=me@example.com',
and if you want to send dynamic email value use
data:'email='+$("input[name='email']").val(),
edited Aug 5 '18 at 20:04
Marius♦
168k28324694
answered Aug 5 '18 at 16:27
Ansar HusainAnsar Husain
1,773218
add a comment |
just use only
data: 'email=me@example.com',
and if you want to send dynamic email value use
data:'email='+$("input[name='email']").val(),
edited Aug 5 '18 at 20:04
Marius♦
168k28324694
answered Aug 5 '18 at 16:27
Ansar HusainAnsar Husain
1,773218
just use only
data: 'email=me@example.com',
and if you want to send dynamic email value use
data:'email='+$("input[name='email']").val(),
edited Aug 5 '18 at 20:04
Marius♦
168k28324694
answered Aug 5 '18 at 16:27
Ansar HusainAnsar Husain
1,773218
edited Aug 5 '18 at 20:04
Marius♦
168k28324694
edited Aug 5 '18 at 20:04
Marius♦
168k28324694
edited Aug 5 '18 at 20:04
Marius♦
168k28324694
168k28324694
answered Aug 5 '18 at 16:27
Ansar HusainAnsar Husain
1,773218
answered Aug 5 '18 at 16:27
Ansar HusainAnsar Husain
1,773218
answered Aug 5 '18 at 16:27
Ansar HusainAnsar Husain
1,773218
1,773218
add a comment |
add a comment |
Change this,
$.ajax(
url: '/checkout/Email/Email',
type: 'POST',
data: 'email': 'che607@yahoo.com',
contentType: 'application/json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
to
$.ajax(
type: 'POST',
url: '/checkout/Email/Email',
data: 'email': 'che607@yahoo.com',
dataType: 'json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
answered Aug 6 '18 at 7:20
Anjali PatilAnjali Patil
64
add a comment |
Change this,
$.ajax(
url: '/checkout/Email/Email',
type: 'POST',
data: 'email': 'che607@yahoo.com',
contentType: 'application/json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
to
$.ajax(
type: 'POST',
url: '/checkout/Email/Email',
data: 'email': 'che607@yahoo.com',
dataType: 'json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
answered Aug 6 '18 at 7:20
Anjali PatilAnjali Patil
64
add a comment |
Change this,
$.ajax(
url: '/checkout/Email/Email',
type: 'POST',
data: 'email': 'che607@yahoo.com',
contentType: 'application/json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
to
$.ajax(
type: 'POST',
url: '/checkout/Email/Email',
data: 'email': 'che607@yahoo.com',
dataType: 'json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
answered Aug 6 '18 at 7:20
Anjali PatilAnjali Patil
64
Change this,
$.ajax(
url: '/checkout/Email/Email',
type: 'POST',
data: 'email': 'che607@yahoo.com',
contentType: 'application/json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
to
$.ajax(
type: 'POST',
url: '/checkout/Email/Email',
data: 'email': 'che607@yahoo.com',
dataType: 'json',
success: function(data)
console.log('SUCCESS: ', data);
,
error: function(data)
console.log('ERROR: ', data);
,
);
answered Aug 6 '18 at 7:20
Anjali PatilAnjali Patil
64
answered Aug 6 '18 at 7:20
Anjali PatilAnjali Patil
64
answered Aug 6 '18 at 7:20
Anjali PatilAnjali Patil
64
answered Aug 6 '18 at 7:20
Anjali PatilAnjali Patil
64
64
add a comment |
add a comment |
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can you please upload your model file or database install script?
– Rohan Hapani
Aug 5 '18 at 16:24
Do you getting data in controller?
– Prashant Valanda
Aug 5 '18 at 18:35