How to set letter above or below the symbol? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)How can I make an overset symbol at the same size and height as bar except with a different symbol?Write above the symbol math “subset”Superimpose letter on integral symbolDecrease vertical whitespace when stacking above and below arrowChange vertical space in oversetSymbol: “maps isomorphically”adjusting symbols above letter in mathmodedouble tilde symbol under letterLetter with circle above — not a dot — in math modeHow to print “~” in order to put text above it
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How to set letter above or below the symbol?
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)How can I make an overset symbol at the same size and height as bar except with a different symbol?Write above the symbol math “subset”Superimpose letter on integral symbolDecrease vertical whitespace when stacking above and below arrowChange vertical space in oversetSymbol: “maps isomorphically”adjusting symbols above letter in mathmodedouble tilde symbol under letterLetter with circle above — not a dot — in math modeHow to print “~” in order to put text above it
I have known oversetK to set above. However how to do like this:
stacking-symbols
edited Apr 15 at 3:53
JouleV
14k22664
asked Apr 15 at 3:06
Z MarioZ Mario
262
New contributor
Z Mario is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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I have known oversetK to set above. However how to do like this:
stacking-symbols
edited Apr 15 at 3:53
JouleV
14k22664
asked Apr 15 at 3:06
Z MarioZ Mario
262
New contributor
Z Mario is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I have known oversetK to set above. However how to do like this:
stacking-symbols
edited Apr 15 at 3:53
JouleV
14k22664
asked Apr 15 at 3:06
Z MarioZ Mario
262
New contributor
Z Mario is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have known oversetK to set above. However how to do like this:
stacking-symbols
stacking-symbols
edited Apr 15 at 3:53
JouleV
14k22664
asked Apr 15 at 3:06
Z MarioZ Mario
262
New contributor
Z Mario is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Apr 15 at 3:53
JouleV
14k22664
asked Apr 15 at 3:06
Z MarioZ Mario
262
New contributor
Z Mario is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Apr 15 at 3:53
JouleV
14k22664
edited Apr 15 at 3:53
JouleV
14k22664
edited Apr 15 at 3:53
JouleV
14k22664
14k22664
asked Apr 15 at 3:06
Z MarioZ Mario
262
New contributor
Z Mario is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Apr 15 at 3:06
Z MarioZ Mario
262
asked Apr 15 at 3:06
Z MarioZ Mario
262
262
New contributor
Z Mario is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Z Mario is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Z Mario is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
The same vertical size as sum:
documentclassarticle
usepackageamsmath
makeatletter
newcommandnnnDOTSBnnn@slimits@
newcommandnnn@mathop
newcommandnnn@@[2]%
vphantomsum%
ifx#1displaystylebig#2else#2fi
makeatother
begindocument
[
nnn_k=1^Kquad sum_k=1^K
]
begincenter% just to show inline math below displaystyle
$nnn_k=1^K$quad$sum_k=1^K$
endcenter
enddocument
answered Apr 15 at 6:31
egregegreg
735k8919343257
add a comment |
Currently, the width of the widest compnent (k=1) determines the width of the stack. If it is needed so that the width of K or the vertical bars determines the width of the stack, please let me know.
It was not clear (to me) from the context of the question whether the baseline is aligned with the K or the vertical bars. Thus, I offer both possibilities. In the latter, the bars will be sized the same as sum:
documentclassarticle
usepackagestackengine,scalerel,mathtools
DeclareMathOperator*vbarsscalerel*rule.6pt10ptmkern2murule.6pt10ptsum
stackMath
parskip1ex
begindocument
K baseline:
$stackunder[2pt]Kstackunder[2pt]%
rule.6pt15ptmkern2murule.6pt15ptscriptstyle k=1$
bigskip
Rule baseline:
$vbars^K_k=1$ (textstyle)
$displaystylevbars^K_k=1$ (displaystyle)
enddocument
In the latter case (vbars math operator), if one wishes the rule thickness and gap to remain the same in both text and display styles, then, in the definition of vbars, merely change scalerel to stretchrel.
answered Apr 15 at 3:09
Steven B. SegletesSteven B. Segletes
163k9206419
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The same vertical size as sum:
documentclassarticle
usepackageamsmath
makeatletter
newcommandnnnDOTSBnnn@slimits@
newcommandnnn@mathop
newcommandnnn@@[2]%
vphantomsum%
ifx#1displaystylebig#2else#2fi
makeatother
begindocument
[
nnn_k=1^Kquad sum_k=1^K
]
begincenter% just to show inline math below displaystyle
$nnn_k=1^K$quad$sum_k=1^K$
endcenter
enddocument
answered Apr 15 at 6:31
egregegreg
735k8919343257
add a comment |
The same vertical size as sum:
documentclassarticle
usepackageamsmath
makeatletter
newcommandnnnDOTSBnnn@slimits@
newcommandnnn@mathop
newcommandnnn@@[2]%
vphantomsum%
ifx#1displaystylebig#2else#2fi
makeatother
begindocument
[
nnn_k=1^Kquad sum_k=1^K
]
begincenter% just to show inline math below displaystyle
$nnn_k=1^K$quad$sum_k=1^K$
endcenter
enddocument
answered Apr 15 at 6:31
egregegreg
735k8919343257
add a comment |
The same vertical size as sum:
documentclassarticle
usepackageamsmath
makeatletter
newcommandnnnDOTSBnnn@slimits@
newcommandnnn@mathop
newcommandnnn@@[2]%
vphantomsum%
ifx#1displaystylebig#2else#2fi
makeatother
begindocument
[
nnn_k=1^Kquad sum_k=1^K
]
begincenter% just to show inline math below displaystyle
$nnn_k=1^K$quad$sum_k=1^K$
endcenter
enddocument
answered Apr 15 at 6:31
egregegreg
735k8919343257
The same vertical size as sum:
documentclassarticle
usepackageamsmath
makeatletter
newcommandnnnDOTSBnnn@slimits@
newcommandnnn@mathop
newcommandnnn@@[2]%
vphantomsum%
ifx#1displaystylebig#2else#2fi
makeatother
begindocument
[
nnn_k=1^Kquad sum_k=1^K
]
begincenter% just to show inline math below displaystyle
$nnn_k=1^K$quad$sum_k=1^K$
endcenter
enddocument
answered Apr 15 at 6:31
egregegreg
735k8919343257
answered Apr 15 at 6:31
egregegreg
735k8919343257
answered Apr 15 at 6:31
egregegreg
735k8919343257
answered Apr 15 at 6:31
egregegreg
735k8919343257
735k8919343257
add a comment |
add a comment |
Currently, the width of the widest compnent (k=1) determines the width of the stack. If it is needed so that the width of K or the vertical bars determines the width of the stack, please let me know.
It was not clear (to me) from the context of the question whether the baseline is aligned with the K or the vertical bars. Thus, I offer both possibilities. In the latter, the bars will be sized the same as sum:
documentclassarticle
usepackagestackengine,scalerel,mathtools
DeclareMathOperator*vbarsscalerel*rule.6pt10ptmkern2murule.6pt10ptsum
stackMath
parskip1ex
begindocument
K baseline:
$stackunder[2pt]Kstackunder[2pt]%
rule.6pt15ptmkern2murule.6pt15ptscriptstyle k=1$
bigskip
Rule baseline:
$vbars^K_k=1$ (textstyle)
$displaystylevbars^K_k=1$ (displaystyle)
enddocument
In the latter case (vbars math operator), if one wishes the rule thickness and gap to remain the same in both text and display styles, then, in the definition of vbars, merely change scalerel to stretchrel.
answered Apr 15 at 3:09
Steven B. SegletesSteven B. Segletes
163k9206419
add a comment |
Currently, the width of the widest compnent (k=1) determines the width of the stack. If it is needed so that the width of K or the vertical bars determines the width of the stack, please let me know.
It was not clear (to me) from the context of the question whether the baseline is aligned with the K or the vertical bars. Thus, I offer both possibilities. In the latter, the bars will be sized the same as sum:
documentclassarticle
usepackagestackengine,scalerel,mathtools
DeclareMathOperator*vbarsscalerel*rule.6pt10ptmkern2murule.6pt10ptsum
stackMath
parskip1ex
begindocument
K baseline:
$stackunder[2pt]Kstackunder[2pt]%
rule.6pt15ptmkern2murule.6pt15ptscriptstyle k=1$
bigskip
Rule baseline:
$vbars^K_k=1$ (textstyle)
$displaystylevbars^K_k=1$ (displaystyle)
enddocument
In the latter case (vbars math operator), if one wishes the rule thickness and gap to remain the same in both text and display styles, then, in the definition of vbars, merely change scalerel to stretchrel.
answered Apr 15 at 3:09
Steven B. SegletesSteven B. Segletes
163k9206419
add a comment |
Currently, the width of the widest compnent (k=1) determines the width of the stack. If it is needed so that the width of K or the vertical bars determines the width of the stack, please let me know.
It was not clear (to me) from the context of the question whether the baseline is aligned with the K or the vertical bars. Thus, I offer both possibilities. In the latter, the bars will be sized the same as sum:
documentclassarticle
usepackagestackengine,scalerel,mathtools
DeclareMathOperator*vbarsscalerel*rule.6pt10ptmkern2murule.6pt10ptsum
stackMath
parskip1ex
begindocument
K baseline:
$stackunder[2pt]Kstackunder[2pt]%
rule.6pt15ptmkern2murule.6pt15ptscriptstyle k=1$
bigskip
Rule baseline:
$vbars^K_k=1$ (textstyle)
$displaystylevbars^K_k=1$ (displaystyle)
enddocument
In the latter case (vbars math operator), if one wishes the rule thickness and gap to remain the same in both text and display styles, then, in the definition of vbars, merely change scalerel to stretchrel.
answered Apr 15 at 3:09
Steven B. SegletesSteven B. Segletes
163k9206419
Currently, the width of the widest compnent (k=1) determines the width of the stack. If it is needed so that the width of K or the vertical bars determines the width of the stack, please let me know.
It was not clear (to me) from the context of the question whether the baseline is aligned with the K or the vertical bars. Thus, I offer both possibilities. In the latter, the bars will be sized the same as sum:
documentclassarticle
usepackagestackengine,scalerel,mathtools
DeclareMathOperator*vbarsscalerel*rule.6pt10ptmkern2murule.6pt10ptsum
stackMath
parskip1ex
begindocument
K baseline:
$stackunder[2pt]Kstackunder[2pt]%
rule.6pt15ptmkern2murule.6pt15ptscriptstyle k=1$
bigskip
Rule baseline:
$vbars^K_k=1$ (textstyle)
$displaystylevbars^K_k=1$ (displaystyle)
enddocument
In the latter case (vbars math operator), if one wishes the rule thickness and gap to remain the same in both text and display styles, then, in the definition of vbars, merely change scalerel to stretchrel.
answered Apr 15 at 3:09
Steven B. SegletesSteven B. Segletes
163k9206419
edited Apr 15 at 10:22
answered Apr 15 at 3:09
Steven B. SegletesSteven B. Segletes
163k9206419
answered Apr 15 at 3:09
Steven B. SegletesSteven B. Segletes
163k9206419
answered Apr 15 at 3:09
Steven B. SegletesSteven B. Segletes
163k9206419
163k9206419
add a comment |
add a comment |
Z Mario is a new contributor. Be nice, and check out our Code of Conduct.
Z Mario is a new contributor. Be nice, and check out our Code of Conduct.
Z Mario is a new contributor. Be nice, and check out our Code of Conduct.
Z Mario is a new contributor. Be nice, and check out our Code of Conduct.
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