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How do I find out when a node was added to an availability group?


Replicate a database to one secondary replica, but not the other secondary replica using Availability Groupadding node to existing availability groupOne Availability group, two primary nodesWindows patching on 3 node Always On Availability GroupIncreasing tempdb data files on 2 node Availability GroupSQL Server 2014: Graceful shutdown of an Availability Group nodeCan't resume synchronization after patch failed on secondary node of Availability GroupSQL Server 2016 Availability Group - 2 Nodes as Primary & Readable Secondary, 1 Node as DRAvailability Group cluster memory issue after network issues. How to dump HADR Log Block Msg Pool?Failure to create availability group






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5















Ideally, I am looking for T-SQL that returns two columns: the node name, and the date/time that node was added to the availability group, for all nodes in a given availability group.










share|improve this question




























    5















    Ideally, I am looking for T-SQL that returns two columns: the node name, and the date/time that node was added to the availability group, for all nodes in a given availability group.










    share|improve this question
























      5












      5








      5








      Ideally, I am looking for T-SQL that returns two columns: the node name, and the date/time that node was added to the availability group, for all nodes in a given availability group.










      share|improve this question














      Ideally, I am looking for T-SQL that returns two columns: the node name, and the date/time that node was added to the availability group, for all nodes in a given availability group.







      sql-server availability-groups






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Apr 4 at 13:06









      Mark RaymondMark Raymond

      15614




      15614




















          1 Answer
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          6














          This is as far as I can see not possible with a single T-SQL statement as individual nodes hold only their own create date.



          The sys.availability_replicas page makes reference to a column create_date. This is the datetime value of when the node was added.



          To find the create_date for each replica you would need to first connect that replica and query the table for that instance only as below.



          SELECT [replica_server_name],
          [create_date]
          FROM [master].[sys].[availability_replicas]
          WHERE replica_server_name = @@SERVERNAME





          share|improve this answer























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            1 Answer
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            active

            oldest

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            6














            This is as far as I can see not possible with a single T-SQL statement as individual nodes hold only their own create date.



            The sys.availability_replicas page makes reference to a column create_date. This is the datetime value of when the node was added.



            To find the create_date for each replica you would need to first connect that replica and query the table for that instance only as below.



            SELECT [replica_server_name],
            [create_date]
            FROM [master].[sys].[availability_replicas]
            WHERE replica_server_name = @@SERVERNAME





            share|improve this answer



























              6














              This is as far as I can see not possible with a single T-SQL statement as individual nodes hold only their own create date.



              The sys.availability_replicas page makes reference to a column create_date. This is the datetime value of when the node was added.



              To find the create_date for each replica you would need to first connect that replica and query the table for that instance only as below.



              SELECT [replica_server_name],
              [create_date]
              FROM [master].[sys].[availability_replicas]
              WHERE replica_server_name = @@SERVERNAME





              share|improve this answer

























                6












                6








                6







                This is as far as I can see not possible with a single T-SQL statement as individual nodes hold only their own create date.



                The sys.availability_replicas page makes reference to a column create_date. This is the datetime value of when the node was added.



                To find the create_date for each replica you would need to first connect that replica and query the table for that instance only as below.



                SELECT [replica_server_name],
                [create_date]
                FROM [master].[sys].[availability_replicas]
                WHERE replica_server_name = @@SERVERNAME





                share|improve this answer













                This is as far as I can see not possible with a single T-SQL statement as individual nodes hold only their own create date.



                The sys.availability_replicas page makes reference to a column create_date. This is the datetime value of when the node was added.



                To find the create_date for each replica you would need to first connect that replica and query the table for that instance only as below.



                SELECT [replica_server_name],
                [create_date]
                FROM [master].[sys].[availability_replicas]
                WHERE replica_server_name = @@SERVERNAME






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Apr 4 at 13:11









                George.PalaciosGeorge.Palacios

                2,537826




                2,537826



























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