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Why is arima in R one time step off?


One step ahead forecast with new data collected sequentiallyauto.arima and predictionWhy are fitted values different from one-step ahead forecasts?Why can't my (auto.)arima-model forecast my time series?ARIMA: extract date/time information from ARIMA model(S)ARIMA — Hints with Time SeriesOne-Step Ahead ForecastARIMA(1,0,0) one-step ahead prediction in R/forecastARIMA forecasts are way offARIMA predicts the one step ahead of the actual prediction






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3












$begingroup$


I've recently noticed an odd behavior in a few timeseries methods. Let's fit an arima model (ar1) to the annual subspots data



library(forecast)
library(ggplot2)

mod_arima <- arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


Now, if we use forecast to get the fit on the model, it's a year off. Compare these two plots:



ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = fitted(mod_arima),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



To one where we delete the first value and tack on an NA at the end





ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = c(fitted(mod_arima)[-1], NA),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



The second lines up perfectly, while the first is obviously one year off. What's going on here?










share|cite|improve this question









$endgroup$







  • 3




    $begingroup$
    This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
    $endgroup$
    – Richard Hardy
    Apr 23 at 17:01

















3












$begingroup$


I've recently noticed an odd behavior in a few timeseries methods. Let's fit an arima model (ar1) to the annual subspots data



library(forecast)
library(ggplot2)

mod_arima <- arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


Now, if we use forecast to get the fit on the model, it's a year off. Compare these two plots:



ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = fitted(mod_arima),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



To one where we delete the first value and tack on an NA at the end





ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = c(fitted(mod_arima)[-1], NA),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



The second lines up perfectly, while the first is obviously one year off. What's going on here?










share|cite|improve this question









$endgroup$







  • 3




    $begingroup$
    This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
    $endgroup$
    – Richard Hardy
    Apr 23 at 17:01













3












3








3


1



$begingroup$


I've recently noticed an odd behavior in a few timeseries methods. Let's fit an arima model (ar1) to the annual subspots data



library(forecast)
library(ggplot2)

mod_arima <- arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


Now, if we use forecast to get the fit on the model, it's a year off. Compare these two plots:



ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = fitted(mod_arima),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



To one where we delete the first value and tack on an NA at the end





ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = c(fitted(mod_arima)[-1], NA),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



The second lines up perfectly, while the first is obviously one year off. What's going on here?










share|cite|improve this question









$endgroup$




I've recently noticed an odd behavior in a few timeseries methods. Let's fit an arima model (ar1) to the annual subspots data



library(forecast)
library(ggplot2)

mod_arima <- arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


Now, if we use forecast to get the fit on the model, it's a year off. Compare these two plots:



ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = fitted(mod_arima),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



To one where we delete the first value and tack on an NA at the end





ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = c(fitted(mod_arima)[-1], NA),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



The second lines up perfectly, while the first is obviously one year off. What's going on here?







r time-series forecasting arima






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Apr 23 at 16:49









jebyrnesjebyrnes

593415




593415







  • 3




    $begingroup$
    This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
    $endgroup$
    – Richard Hardy
    Apr 23 at 17:01












  • 3




    $begingroup$
    This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
    $endgroup$
    – Richard Hardy
    Apr 23 at 17:01







3




3




$begingroup$
This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
$endgroup$
– Richard Hardy
Apr 23 at 17:01




$begingroup$
This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
$endgroup$
– Richard Hardy
Apr 23 at 17:01










2 Answers
2






active

oldest

votes


















4












$begingroup$

As Richard Hardy writes: if your prediction $haty_t+1$ of $y_t+1$ is pretty much your last observation $y_t$, then of course you would expect $haty_t+1$ to line up with $y_t$, which would show exactly as the one year lag you wonder about.



And if you specify



arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


then you fitted exactly that: an AR(1) model. The AR(1) coefficient is estimated to be about 0.81. (With an intercept. Also, if you add the year as a regressor, you will model a trend. Did you intend to do this?)



Incidentally, if you allow auto.arima() to fit a model, it will choose an ARIMA(2,1,3) model, which will not exhibit this lag:



sunspots



library(forecast)
model <- auto.arima(sunspot.year)
plot(sunspot.year)
lines(model$fit,col="red")


You could also include the known sunspot period of length 11, though auto.arima() won't automatically fit a SARIMA.






share|cite|improve this answer









$endgroup$




















    3












    $begingroup$

    You're fitting an $ARIMA(1,0,0)$ model to your data, which means that your fitted model has the form:



    $hatY_t+1-m = a(Y_t-m) + epsilon$



    So it looks like it's a year off, because all the model is doing is copying the value from the current year $Y_t$, with an adjustment $a$ and a drift term, and making that the prediction for the next year $hatY_t+1$.



    Your data looks highly cyclical, you might want to try fitting a seasonal ARIMA model instead of a simple AR(1) or AR(2).






    share|cite|improve this answer











    $endgroup$













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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      4












      $begingroup$

      As Richard Hardy writes: if your prediction $haty_t+1$ of $y_t+1$ is pretty much your last observation $y_t$, then of course you would expect $haty_t+1$ to line up with $y_t$, which would show exactly as the one year lag you wonder about.



      And if you specify



      arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


      then you fitted exactly that: an AR(1) model. The AR(1) coefficient is estimated to be about 0.81. (With an intercept. Also, if you add the year as a regressor, you will model a trend. Did you intend to do this?)



      Incidentally, if you allow auto.arima() to fit a model, it will choose an ARIMA(2,1,3) model, which will not exhibit this lag:



      sunspots



      library(forecast)
      model <- auto.arima(sunspot.year)
      plot(sunspot.year)
      lines(model$fit,col="red")


      You could also include the known sunspot period of length 11, though auto.arima() won't automatically fit a SARIMA.






      share|cite|improve this answer









      $endgroup$

















        4












        $begingroup$

        As Richard Hardy writes: if your prediction $haty_t+1$ of $y_t+1$ is pretty much your last observation $y_t$, then of course you would expect $haty_t+1$ to line up with $y_t$, which would show exactly as the one year lag you wonder about.



        And if you specify



        arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


        then you fitted exactly that: an AR(1) model. The AR(1) coefficient is estimated to be about 0.81. (With an intercept. Also, if you add the year as a regressor, you will model a trend. Did you intend to do this?)



        Incidentally, if you allow auto.arima() to fit a model, it will choose an ARIMA(2,1,3) model, which will not exhibit this lag:



        sunspots



        library(forecast)
        model <- auto.arima(sunspot.year)
        plot(sunspot.year)
        lines(model$fit,col="red")


        You could also include the known sunspot period of length 11, though auto.arima() won't automatically fit a SARIMA.






        share|cite|improve this answer









        $endgroup$















          4












          4








          4





          $begingroup$

          As Richard Hardy writes: if your prediction $haty_t+1$ of $y_t+1$ is pretty much your last observation $y_t$, then of course you would expect $haty_t+1$ to line up with $y_t$, which would show exactly as the one year lag you wonder about.



          And if you specify



          arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


          then you fitted exactly that: an AR(1) model. The AR(1) coefficient is estimated to be about 0.81. (With an intercept. Also, if you add the year as a regressor, you will model a trend. Did you intend to do this?)



          Incidentally, if you allow auto.arima() to fit a model, it will choose an ARIMA(2,1,3) model, which will not exhibit this lag:



          sunspots



          library(forecast)
          model <- auto.arima(sunspot.year)
          plot(sunspot.year)
          lines(model$fit,col="red")


          You could also include the known sunspot period of length 11, though auto.arima() won't automatically fit a SARIMA.






          share|cite|improve this answer









          $endgroup$



          As Richard Hardy writes: if your prediction $haty_t+1$ of $y_t+1$ is pretty much your last observation $y_t$, then of course you would expect $haty_t+1$ to line up with $y_t$, which would show exactly as the one year lag you wonder about.



          And if you specify



          arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


          then you fitted exactly that: an AR(1) model. The AR(1) coefficient is estimated to be about 0.81. (With an intercept. Also, if you add the year as a regressor, you will model a trend. Did you intend to do this?)



          Incidentally, if you allow auto.arima() to fit a model, it will choose an ARIMA(2,1,3) model, which will not exhibit this lag:



          sunspots



          library(forecast)
          model <- auto.arima(sunspot.year)
          plot(sunspot.year)
          lines(model$fit,col="red")


          You could also include the known sunspot period of length 11, though auto.arima() won't automatically fit a SARIMA.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Apr 23 at 17:24









          Stephan KolassaStephan Kolassa

          48.7k8102185




          48.7k8102185























              3












              $begingroup$

              You're fitting an $ARIMA(1,0,0)$ model to your data, which means that your fitted model has the form:



              $hatY_t+1-m = a(Y_t-m) + epsilon$



              So it looks like it's a year off, because all the model is doing is copying the value from the current year $Y_t$, with an adjustment $a$ and a drift term, and making that the prediction for the next year $hatY_t+1$.



              Your data looks highly cyclical, you might want to try fitting a seasonal ARIMA model instead of a simple AR(1) or AR(2).






              share|cite|improve this answer











              $endgroup$

















                3












                $begingroup$

                You're fitting an $ARIMA(1,0,0)$ model to your data, which means that your fitted model has the form:



                $hatY_t+1-m = a(Y_t-m) + epsilon$



                So it looks like it's a year off, because all the model is doing is copying the value from the current year $Y_t$, with an adjustment $a$ and a drift term, and making that the prediction for the next year $hatY_t+1$.



                Your data looks highly cyclical, you might want to try fitting a seasonal ARIMA model instead of a simple AR(1) or AR(2).






                share|cite|improve this answer











                $endgroup$















                  3












                  3








                  3





                  $begingroup$

                  You're fitting an $ARIMA(1,0,0)$ model to your data, which means that your fitted model has the form:



                  $hatY_t+1-m = a(Y_t-m) + epsilon$



                  So it looks like it's a year off, because all the model is doing is copying the value from the current year $Y_t$, with an adjustment $a$ and a drift term, and making that the prediction for the next year $hatY_t+1$.



                  Your data looks highly cyclical, you might want to try fitting a seasonal ARIMA model instead of a simple AR(1) or AR(2).






                  share|cite|improve this answer











                  $endgroup$



                  You're fitting an $ARIMA(1,0,0)$ model to your data, which means that your fitted model has the form:



                  $hatY_t+1-m = a(Y_t-m) + epsilon$



                  So it looks like it's a year off, because all the model is doing is copying the value from the current year $Y_t$, with an adjustment $a$ and a drift term, and making that the prediction for the next year $hatY_t+1$.



                  Your data looks highly cyclical, you might want to try fitting a seasonal ARIMA model instead of a simple AR(1) or AR(2).







                  share|cite|improve this answer














                  share|cite|improve this answer



                  share|cite|improve this answer








                  edited Apr 23 at 18:46









                  Stephan Kolassa

                  48.7k8102185




                  48.7k8102185










                  answered Apr 23 at 17:24









                  Skander H.Skander H.

                  4,0251233




                  4,0251233



























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