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Problem with fill color


TikZ: Cropping the Bounding BoxRotate a node but not its content: the case of the ellipse decorationTikZ scaling graphic and adjust node position and keep font sizeAsymptote: 3D fill color is undesiredFill color with tikzpictureFill color intersectionsHow can I color fill the annulus with tikz?pgfplots - Problem with the fill commandTikZ fill using draw colorHow to fill a right-angle mark with a color?













3















I use the following command to create regular polygons. The 5th argument is there to insert options for styling the polygons. Though the line width is 0.3mm as I set it, it looks like the fill=red option is not accepted.



documentclassarticle
usepackageamsmath,tikz,tkz-euclide,pgfplots,calculator

newcommandpolygon[5][]
pgfmathsetmacroangle360/#2
pgfmathsetmacroa(#2-1)/2
FLOORasol
pgfmathsetmacrostartangle-90 + angle/2
foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
draw[#5] (x:#3) -- (x + angle:#3) -- cycle;
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)
foreach [count=i] j in #4
pgfmathsetmacroxstartangle - angle*(i+sol)
node[anchor=center] at (x:#3+.3) $j$;

begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red

endtikzpicture
enddocument


I don't know if the structure of the command is not allowing any other option.










share|improve this question






















  • In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

    – Kpym
    2 days ago












  • I want to fill the area inside the polygon and I thought that it can be done trough draw command.

    – mac
    2 days ago
















3















I use the following command to create regular polygons. The 5th argument is there to insert options for styling the polygons. Though the line width is 0.3mm as I set it, it looks like the fill=red option is not accepted.



documentclassarticle
usepackageamsmath,tikz,tkz-euclide,pgfplots,calculator

newcommandpolygon[5][]
pgfmathsetmacroangle360/#2
pgfmathsetmacroa(#2-1)/2
FLOORasol
pgfmathsetmacrostartangle-90 + angle/2
foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
draw[#5] (x:#3) -- (x + angle:#3) -- cycle;
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)
foreach [count=i] j in #4
pgfmathsetmacroxstartangle - angle*(i+sol)
node[anchor=center] at (x:#3+.3) $j$;

begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red

endtikzpicture
enddocument


I don't know if the structure of the command is not allowing any other option.










share|improve this question






















  • In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

    – Kpym
    2 days ago












  • I want to fill the area inside the polygon and I thought that it can be done trough draw command.

    – mac
    2 days ago














3












3








3








I use the following command to create regular polygons. The 5th argument is there to insert options for styling the polygons. Though the line width is 0.3mm as I set it, it looks like the fill=red option is not accepted.



documentclassarticle
usepackageamsmath,tikz,tkz-euclide,pgfplots,calculator

newcommandpolygon[5][]
pgfmathsetmacroangle360/#2
pgfmathsetmacroa(#2-1)/2
FLOORasol
pgfmathsetmacrostartangle-90 + angle/2
foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
draw[#5] (x:#3) -- (x + angle:#3) -- cycle;
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)
foreach [count=i] j in #4
pgfmathsetmacroxstartangle - angle*(i+sol)
node[anchor=center] at (x:#3+.3) $j$;

begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red

endtikzpicture
enddocument


I don't know if the structure of the command is not allowing any other option.










share|improve this question














I use the following command to create regular polygons. The 5th argument is there to insert options for styling the polygons. Though the line width is 0.3mm as I set it, it looks like the fill=red option is not accepted.



documentclassarticle
usepackageamsmath,tikz,tkz-euclide,pgfplots,calculator

newcommandpolygon[5][]
pgfmathsetmacroangle360/#2
pgfmathsetmacroa(#2-1)/2
FLOORasol
pgfmathsetmacrostartangle-90 + angle/2
foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
draw[#5] (x:#3) -- (x + angle:#3) -- cycle;
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)
foreach [count=i] j in #4
pgfmathsetmacroxstartangle - angle*(i+sol)
node[anchor=center] at (x:#3+.3) $j$;

begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red

endtikzpicture
enddocument


I don't know if the structure of the command is not allowing any other option.







tikz-pgf tikz-styles fill polygon






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 2 days ago









macmac

732716




732716












  • In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

    – Kpym
    2 days ago












  • I want to fill the area inside the polygon and I thought that it can be done trough draw command.

    – mac
    2 days ago


















  • In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

    – Kpym
    2 days ago












  • I want to fill the area inside the polygon and I thought that it can be done trough draw command.

    – mac
    2 days ago

















In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

– Kpym
2 days ago






In draw[#5] (x:#3) -- (x + angle:#3) -- cycle; you have nothing to fill (this is just a segment drawn twice), so fill=red is useless here. It is not clear what you want to fill. Do you want (0,0) in place of (cycle) here?

– Kpym
2 days ago














I want to fill the area inside the polygon and I thought that it can be done trough draw command.

– mac
2 days ago






I want to fill the area inside the polygon and I thought that it can be done trough draw command.

– mac
2 days ago











1 Answer
1






active

oldest

votes


















4














I am wondering why you don't follow approaches like this



documentclassarticle
usepackageamsmath,tikz
usetikzlibraryshapes

newcommandpolygon[5][]%
node[draw,#5,regular polygon,regular polygon sides=#2,minimum size=2*#3cm] (p) ;
foreach i[count=j] in #4
path (p.center)--(p.corner j) node[pos=1.2] $i$;



begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red
endtikzpicture
enddocument


enter image description here



However, I think you should not define a macro for this.




If you want to follow your way, Kpym has given you the right way: use (0,0) instead of cycle. However, one has to do a bit more. Also, there will be a very thin white line.



documentclassarticle
usepackageamsmath,tikz,tkz-euclide,pgfplots,calculator

newcommandpolygon[5][]%
pgfmathsetmacroangle360/#2
pgfmathsetmacroa(#2-1)/2
FLOORasol
pgfmathsetmacrostartangle-90 + angle/2
foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
fill[#5] (x:#3) -- (x + angle:#3) -- (0,0);
draw[#5] (x:#3) -- (x + angle:#3);
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)

foreach [count=i] j in #4
pgfmathsetmacroxstartangle - angle*(i+sol)
node[anchor=center] at (x:#3+.3) $j$;

foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)



begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red

endtikzpicture
enddocument


enter image description here






share|improve this answer




















  • 1





    The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

    – mac
    2 days ago











  • My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

    – Sebastiano
    2 days ago












  • @Sebastiano I will add in a while. However, I don't see anything strange.

    – JouleV
    2 days ago











  • @JouleV In the 2nd picture (2nd code).

    – Sebastiano
    2 days ago






  • 1





    Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

    – JouleV
    2 days ago











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4














I am wondering why you don't follow approaches like this



documentclassarticle
usepackageamsmath,tikz
usetikzlibraryshapes

newcommandpolygon[5][]%
node[draw,#5,regular polygon,regular polygon sides=#2,minimum size=2*#3cm] (p) ;
foreach i[count=j] in #4
path (p.center)--(p.corner j) node[pos=1.2] $i$;



begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red
endtikzpicture
enddocument


enter image description here



However, I think you should not define a macro for this.




If you want to follow your way, Kpym has given you the right way: use (0,0) instead of cycle. However, one has to do a bit more. Also, there will be a very thin white line.



documentclassarticle
usepackageamsmath,tikz,tkz-euclide,pgfplots,calculator

newcommandpolygon[5][]%
pgfmathsetmacroangle360/#2
pgfmathsetmacroa(#2-1)/2
FLOORasol
pgfmathsetmacrostartangle-90 + angle/2
foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
fill[#5] (x:#3) -- (x + angle:#3) -- (0,0);
draw[#5] (x:#3) -- (x + angle:#3);
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)

foreach [count=i] j in #4
pgfmathsetmacroxstartangle - angle*(i+sol)
node[anchor=center] at (x:#3+.3) $j$;

foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)



begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red

endtikzpicture
enddocument


enter image description here






share|improve this answer




















  • 1





    The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

    – mac
    2 days ago











  • My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

    – Sebastiano
    2 days ago












  • @Sebastiano I will add in a while. However, I don't see anything strange.

    – JouleV
    2 days ago











  • @JouleV In the 2nd picture (2nd code).

    – Sebastiano
    2 days ago






  • 1





    Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

    – JouleV
    2 days ago















4














I am wondering why you don't follow approaches like this



documentclassarticle
usepackageamsmath,tikz
usetikzlibraryshapes

newcommandpolygon[5][]%
node[draw,#5,regular polygon,regular polygon sides=#2,minimum size=2*#3cm] (p) ;
foreach i[count=j] in #4
path (p.center)--(p.corner j) node[pos=1.2] $i$;



begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red
endtikzpicture
enddocument


enter image description here



However, I think you should not define a macro for this.




If you want to follow your way, Kpym has given you the right way: use (0,0) instead of cycle. However, one has to do a bit more. Also, there will be a very thin white line.



documentclassarticle
usepackageamsmath,tikz,tkz-euclide,pgfplots,calculator

newcommandpolygon[5][]%
pgfmathsetmacroangle360/#2
pgfmathsetmacroa(#2-1)/2
FLOORasol
pgfmathsetmacrostartangle-90 + angle/2
foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
fill[#5] (x:#3) -- (x + angle:#3) -- (0,0);
draw[#5] (x:#3) -- (x + angle:#3);
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)

foreach [count=i] j in #4
pgfmathsetmacroxstartangle - angle*(i+sol)
node[anchor=center] at (x:#3+.3) $j$;

foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)



begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red

endtikzpicture
enddocument


enter image description here






share|improve this answer




















  • 1





    The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

    – mac
    2 days ago











  • My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

    – Sebastiano
    2 days ago












  • @Sebastiano I will add in a while. However, I don't see anything strange.

    – JouleV
    2 days ago











  • @JouleV In the 2nd picture (2nd code).

    – Sebastiano
    2 days ago






  • 1





    Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

    – JouleV
    2 days ago













4












4








4







I am wondering why you don't follow approaches like this



documentclassarticle
usepackageamsmath,tikz
usetikzlibraryshapes

newcommandpolygon[5][]%
node[draw,#5,regular polygon,regular polygon sides=#2,minimum size=2*#3cm] (p) ;
foreach i[count=j] in #4
path (p.center)--(p.corner j) node[pos=1.2] $i$;



begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red
endtikzpicture
enddocument


enter image description here



However, I think you should not define a macro for this.




If you want to follow your way, Kpym has given you the right way: use (0,0) instead of cycle. However, one has to do a bit more. Also, there will be a very thin white line.



documentclassarticle
usepackageamsmath,tikz,tkz-euclide,pgfplots,calculator

newcommandpolygon[5][]%
pgfmathsetmacroangle360/#2
pgfmathsetmacroa(#2-1)/2
FLOORasol
pgfmathsetmacrostartangle-90 + angle/2
foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
fill[#5] (x:#3) -- (x + angle:#3) -- (0,0);
draw[#5] (x:#3) -- (x + angle:#3);
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)

foreach [count=i] j in #4
pgfmathsetmacroxstartangle - angle*(i+sol)
node[anchor=center] at (x:#3+.3) $j$;

foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)



begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red

endtikzpicture
enddocument


enter image description here






share|improve this answer















I am wondering why you don't follow approaches like this



documentclassarticle
usepackageamsmath,tikz
usetikzlibraryshapes

newcommandpolygon[5][]%
node[draw,#5,regular polygon,regular polygon sides=#2,minimum size=2*#3cm] (p) ;
foreach i[count=j] in #4
path (p.center)--(p.corner j) node[pos=1.2] $i$;



begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red
endtikzpicture
enddocument


enter image description here



However, I think you should not define a macro for this.




If you want to follow your way, Kpym has given you the right way: use (0,0) instead of cycle. However, one has to do a bit more. Also, there will be a very thin white line.



documentclassarticle
usepackageamsmath,tikz,tkz-euclide,pgfplots,calculator

newcommandpolygon[5][]%
pgfmathsetmacroangle360/#2
pgfmathsetmacroa(#2-1)/2
FLOORasol
pgfmathsetmacrostartangle-90 + angle/2
foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
fill[#5] (x:#3) -- (x + angle:#3) -- (0,0);
draw[#5] (x:#3) -- (x + angle:#3);
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)

foreach [count=i] j in #4
pgfmathsetmacroxstartangle - angle*(i+sol)
node[anchor=center] at (x:#3+.3) $j$;

foreach i in 1,2,...,#2
pgfmathsetmacroxstartangle + angle*i
tkzDefPoint(x:#3)A_#2
tkzDrawPoint(A_#2)



begindocument
begintikzpicture
draw[line width=0.3mm] (0,0) circle (1);
polygon[]61A,B,varGamma,varDelta,E,Zline width=0.3mm,fill=red

endtikzpicture
enddocument


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 2 days ago

























answered 2 days ago









JouleVJouleV

10.3k22558




10.3k22558







  • 1





    The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

    – mac
    2 days ago











  • My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

    – Sebastiano
    2 days ago












  • @Sebastiano I will add in a while. However, I don't see anything strange.

    – JouleV
    2 days ago











  • @JouleV In the 2nd picture (2nd code).

    – Sebastiano
    2 days ago






  • 1





    Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

    – JouleV
    2 days ago












  • 1





    The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

    – mac
    2 days ago











  • My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

    – Sebastiano
    2 days ago












  • @Sebastiano I will add in a while. However, I don't see anything strange.

    – JouleV
    2 days ago











  • @JouleV In the 2nd picture (2nd code).

    – Sebastiano
    2 days ago






  • 1





    Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

    – JouleV
    2 days ago







1




1





The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

– mac
2 days ago





The first sulotion is neat and simple. I had no idea that there was a ready to use option for regular polygons. Also I realised, as Kpym mentioned, that each time I was drawing the same segment twice, so there was no polygon to fill.

– mac
2 days ago













My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

– Sebastiano
2 days ago






My upvoted surely. Can you put, please, in first plane the gray bullet near Gamma? There is a strange closure of the exagon.

– Sebastiano
2 days ago














@Sebastiano I will add in a while. However, I don't see anything strange.

– JouleV
2 days ago





@Sebastiano I will add in a while. However, I don't see anything strange.

– JouleV
2 days ago













@JouleV In the 2nd picture (2nd code).

– Sebastiano
2 days ago





@JouleV In the 2nd picture (2nd code).

– Sebastiano
2 days ago




1




1





Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

– JouleV
2 days ago





Ah, ok, I will find some ways to solve. Anyway that way is not recommended clearly.

– JouleV
2 days ago

















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