I'm thinking of a number Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?systematic number removalWhat is a Voluminous Number™?Ten-digit number that satisfy divisibilty rules for 2,3,4,5,6,7,8,9,10&11What mysterious whole number am I?

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I'm thinking of a number



Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?systematic number removalWhat is a Voluminous Number™?Ten-digit number that satisfy divisibilty rules for 2,3,4,5,6,7,8,9,10&11What mysterious whole number am I?










10












$begingroup$


The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.



What number am I thinking of?



Hint 1:




"There are X As in a B", but almost every B contains at least X + 2 As.




Hint 2:




"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs











share|improve this question









$endgroup$











  • $begingroup$
    It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
    $endgroup$
    – EKons
    Apr 14 at 18:40










  • $begingroup$
    @EKons But rot13(n zneevrq pbhcyr) is correct.
    $endgroup$
    – Rupert Morrish
    Apr 14 at 20:09















10












$begingroup$


The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.



What number am I thinking of?



Hint 1:




"There are X As in a B", but almost every B contains at least X + 2 As.




Hint 2:




"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs











share|improve this question









$endgroup$











  • $begingroup$
    It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
    $endgroup$
    – EKons
    Apr 14 at 18:40










  • $begingroup$
    @EKons But rot13(n zneevrq pbhcyr) is correct.
    $endgroup$
    – Rupert Morrish
    Apr 14 at 20:09













10












10








10





$begingroup$


The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.



What number am I thinking of?



Hint 1:




"There are X As in a B", but almost every B contains at least X + 2 As.




Hint 2:




"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs











share|improve this question









$endgroup$




The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.



What number am I thinking of?



Hint 1:




"There are X As in a B", but almost every B contains at least X + 2 As.




Hint 2:




"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs








number-property






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Apr 14 at 4:13









Rupert MorrishRupert Morrish

3,6851935




3,6851935











  • $begingroup$
    It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
    $endgroup$
    – EKons
    Apr 14 at 18:40










  • $begingroup$
    @EKons But rot13(n zneevrq pbhcyr) is correct.
    $endgroup$
    – Rupert Morrish
    Apr 14 at 20:09
















  • $begingroup$
    It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
    $endgroup$
    – EKons
    Apr 14 at 18:40










  • $begingroup$
    @EKons But rot13(n zneevrq pbhcyr) is correct.
    $endgroup$
    – Rupert Morrish
    Apr 14 at 20:09















$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
Apr 14 at 18:40




$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
Apr 14 at 18:40












$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
Apr 14 at 20:09




$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
Apr 14 at 20:09










1 Answer
1






active

oldest

votes


















18












$begingroup$

A number which fits is




$52$




Hint 1:




There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.




Hint 2:




It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
$365/7 approx 52.14...$ and $366/7 approx 52.28...$







share|improve this answer









$endgroup$













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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    18












    $begingroup$

    A number which fits is




    $52$




    Hint 1:




    There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.




    Hint 2:




    It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
    $365/7 approx 52.14...$ and $366/7 approx 52.28...$







    share|improve this answer









    $endgroup$

















      18












      $begingroup$

      A number which fits is




      $52$




      Hint 1:




      There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.




      Hint 2:




      It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
      $365/7 approx 52.14...$ and $366/7 approx 52.28...$







      share|improve this answer









      $endgroup$















        18












        18








        18





        $begingroup$

        A number which fits is




        $52$




        Hint 1:




        There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.




        Hint 2:




        It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
        $365/7 approx 52.14...$ and $366/7 approx 52.28...$







        share|improve this answer









        $endgroup$



        A number which fits is




        $52$




        Hint 1:




        There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.




        Hint 2:




        It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
        $365/7 approx 52.14...$ and $366/7 approx 52.28...$








        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Apr 14 at 5:42









        TomTom

        36.4k3132209




        36.4k3132209



























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