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ContourPlot — How do I color by contour curvature?


Custom contour labels in ContourPlotListContourPlot is blocking my geometryHow to plot the contour of f[x,y]==0 if always f[x,y]>=0Contour coloring and (List)ContourPlot projectionMore stream lines in a ListStreamPlotContourPlot - unequal contour spacingContourPlot color problems3D Stack of Disks with dedicated height plotsHow to color Contours in ContourPlot with custom ColorFunctionChanging the color of a specific curve in ContourPlot













10












$begingroup$


I'm plotting the stream lines of fluid flow past a cylinder, and I would like the colors to increase with contour curvature (i.e. increase as the velocity of the flow increases. Here's a MWE that seems to color it based on the the y-axis value:



ψ[r_, θ_] := U (r - a^2/r) Sin[θ]
r = Sqrt[x^2 + y^2];
θ = ArcSin[y/r];

stream = ContourPlot[
ψ[r, θ] /. U -> 10, a -> 1,
x, -5,5, y, -5, 5,
Contours -> 10 Table[i, i, -10, 10, 0.025]
];

cyl = Graphics[Disk[0, 0, 1]];

Show[stream, cyl]


stream lines around a cylinder










share|improve this question











$endgroup$
















    10












    $begingroup$


    I'm plotting the stream lines of fluid flow past a cylinder, and I would like the colors to increase with contour curvature (i.e. increase as the velocity of the flow increases. Here's a MWE that seems to color it based on the the y-axis value:



    ψ[r_, θ_] := U (r - a^2/r) Sin[θ]
    r = Sqrt[x^2 + y^2];
    θ = ArcSin[y/r];

    stream = ContourPlot[
    ψ[r, θ] /. U -> 10, a -> 1,
    x, -5,5, y, -5, 5,
    Contours -> 10 Table[i, i, -10, 10, 0.025]
    ];

    cyl = Graphics[Disk[0, 0, 1]];

    Show[stream, cyl]


    stream lines around a cylinder










    share|improve this question











    $endgroup$














      10












      10








      10


      2



      $begingroup$


      I'm plotting the stream lines of fluid flow past a cylinder, and I would like the colors to increase with contour curvature (i.e. increase as the velocity of the flow increases. Here's a MWE that seems to color it based on the the y-axis value:



      ψ[r_, θ_] := U (r - a^2/r) Sin[θ]
      r = Sqrt[x^2 + y^2];
      θ = ArcSin[y/r];

      stream = ContourPlot[
      ψ[r, θ] /. U -> 10, a -> 1,
      x, -5,5, y, -5, 5,
      Contours -> 10 Table[i, i, -10, 10, 0.025]
      ];

      cyl = Graphics[Disk[0, 0, 1]];

      Show[stream, cyl]


      stream lines around a cylinder










      share|improve this question











      $endgroup$




      I'm plotting the stream lines of fluid flow past a cylinder, and I would like the colors to increase with contour curvature (i.e. increase as the velocity of the flow increases. Here's a MWE that seems to color it based on the the y-axis value:



      ψ[r_, θ_] := U (r - a^2/r) Sin[θ]
      r = Sqrt[x^2 + y^2];
      θ = ArcSin[y/r];

      stream = ContourPlot[
      ψ[r, θ] /. U -> 10, a -> 1,
      x, -5,5, y, -5, 5,
      Contours -> 10 Table[i, i, -10, 10, 0.025]
      ];

      cyl = Graphics[Disk[0, 0, 1]];

      Show[stream, cyl]


      stream lines around a cylinder







      plotting color






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited yesterday









      m_goldberg

      87.7k872198




      87.7k872198










      asked yesterday









      dpholmesdpholmes

      345111




      345111




















          1 Answer
          1






          active

          oldest

          votes


















          12












          $begingroup$

          f = ψ[r, θ] /. U -> 10, a -> 1;
          gradf = D[f, x, y, 1];
          Hessf = D[f, x, y, 2];
          normal = gradf[[1]]/Sqrt[gradf[[1]].gradf[[1]]] // Simplify;
          secondfundamentalform = -PseudoInverse[gradf].Hessf // ComplexExpand // Simplify;
          tangent = RotationMatrix[Pi/2].normal;
          curvaturevector = (secondfundamentalform.tangent).tangent // Simplify;
          signedcurvature = curvaturevector.normal // Simplify;

          stream = ContourPlot[
          ψ[r, θ] /. U -> 10, a -> 1, x, -5, 5, y, -5, 5,
          Contours -> 10 Table[i, i, -10, 10, 0.2],
          ContourShading -> None
          ];
          curvatureplot = DensityPlot[signedcurvature, x, -5, 5, y, -5, 5,
          ColorFunction -> "RedGreenSplit",
          ClippingStyle -> Automatic,
          PlotPoints -> 100,
          PlotRange -> -1, 1
          ];
          Show[
          curvatureplot,
          stream,
          cyl
          ]


          enter image description here






          share|improve this answer











          $endgroup$












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            1 Answer
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            1 Answer
            1






            active

            oldest

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            active

            oldest

            votes






            active

            oldest

            votes









            12












            $begingroup$

            f = ψ[r, θ] /. U -> 10, a -> 1;
            gradf = D[f, x, y, 1];
            Hessf = D[f, x, y, 2];
            normal = gradf[[1]]/Sqrt[gradf[[1]].gradf[[1]]] // Simplify;
            secondfundamentalform = -PseudoInverse[gradf].Hessf // ComplexExpand // Simplify;
            tangent = RotationMatrix[Pi/2].normal;
            curvaturevector = (secondfundamentalform.tangent).tangent // Simplify;
            signedcurvature = curvaturevector.normal // Simplify;

            stream = ContourPlot[
            ψ[r, θ] /. U -> 10, a -> 1, x, -5, 5, y, -5, 5,
            Contours -> 10 Table[i, i, -10, 10, 0.2],
            ContourShading -> None
            ];
            curvatureplot = DensityPlot[signedcurvature, x, -5, 5, y, -5, 5,
            ColorFunction -> "RedGreenSplit",
            ClippingStyle -> Automatic,
            PlotPoints -> 100,
            PlotRange -> -1, 1
            ];
            Show[
            curvatureplot,
            stream,
            cyl
            ]


            enter image description here






            share|improve this answer











            $endgroup$

















              12












              $begingroup$

              f = ψ[r, θ] /. U -> 10, a -> 1;
              gradf = D[f, x, y, 1];
              Hessf = D[f, x, y, 2];
              normal = gradf[[1]]/Sqrt[gradf[[1]].gradf[[1]]] // Simplify;
              secondfundamentalform = -PseudoInverse[gradf].Hessf // ComplexExpand // Simplify;
              tangent = RotationMatrix[Pi/2].normal;
              curvaturevector = (secondfundamentalform.tangent).tangent // Simplify;
              signedcurvature = curvaturevector.normal // Simplify;

              stream = ContourPlot[
              ψ[r, θ] /. U -> 10, a -> 1, x, -5, 5, y, -5, 5,
              Contours -> 10 Table[i, i, -10, 10, 0.2],
              ContourShading -> None
              ];
              curvatureplot = DensityPlot[signedcurvature, x, -5, 5, y, -5, 5,
              ColorFunction -> "RedGreenSplit",
              ClippingStyle -> Automatic,
              PlotPoints -> 100,
              PlotRange -> -1, 1
              ];
              Show[
              curvatureplot,
              stream,
              cyl
              ]


              enter image description here






              share|improve this answer











              $endgroup$















                12












                12








                12





                $begingroup$

                f = ψ[r, θ] /. U -> 10, a -> 1;
                gradf = D[f, x, y, 1];
                Hessf = D[f, x, y, 2];
                normal = gradf[[1]]/Sqrt[gradf[[1]].gradf[[1]]] // Simplify;
                secondfundamentalform = -PseudoInverse[gradf].Hessf // ComplexExpand // Simplify;
                tangent = RotationMatrix[Pi/2].normal;
                curvaturevector = (secondfundamentalform.tangent).tangent // Simplify;
                signedcurvature = curvaturevector.normal // Simplify;

                stream = ContourPlot[
                ψ[r, θ] /. U -> 10, a -> 1, x, -5, 5, y, -5, 5,
                Contours -> 10 Table[i, i, -10, 10, 0.2],
                ContourShading -> None
                ];
                curvatureplot = DensityPlot[signedcurvature, x, -5, 5, y, -5, 5,
                ColorFunction -> "RedGreenSplit",
                ClippingStyle -> Automatic,
                PlotPoints -> 100,
                PlotRange -> -1, 1
                ];
                Show[
                curvatureplot,
                stream,
                cyl
                ]


                enter image description here






                share|improve this answer











                $endgroup$



                f = ψ[r, θ] /. U -> 10, a -> 1;
                gradf = D[f, x, y, 1];
                Hessf = D[f, x, y, 2];
                normal = gradf[[1]]/Sqrt[gradf[[1]].gradf[[1]]] // Simplify;
                secondfundamentalform = -PseudoInverse[gradf].Hessf // ComplexExpand // Simplify;
                tangent = RotationMatrix[Pi/2].normal;
                curvaturevector = (secondfundamentalform.tangent).tangent // Simplify;
                signedcurvature = curvaturevector.normal // Simplify;

                stream = ContourPlot[
                ψ[r, θ] /. U -> 10, a -> 1, x, -5, 5, y, -5, 5,
                Contours -> 10 Table[i, i, -10, 10, 0.2],
                ContourShading -> None
                ];
                curvatureplot = DensityPlot[signedcurvature, x, -5, 5, y, -5, 5,
                ColorFunction -> "RedGreenSplit",
                ClippingStyle -> Automatic,
                PlotPoints -> 100,
                PlotRange -> -1, 1
                ];
                Show[
                curvatureplot,
                stream,
                cyl
                ]


                enter image description here







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 20 hours ago

























                answered yesterday









                Henrik SchumacherHenrik Schumacher

                57.4k578158




                57.4k578158



























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