What produces gravitational waves with “periods between about 100 - 8000 seconds”? Unicorn Meta Zoo #1: Why another podcast? Announcing the arrival of Valued Associate #679: Cesar ManaraCan't pulsars and stars be used for gravitational wave measurement?Redshift for gravitational waves?Frequency of gravitational wave detectionWould humans hear gravity waves from a binary BH fusion nearby?What are gravitational waves actually?LIGO gravitational wave chirp signal frequencyWhich of the following statements about gravitational waves are true?What is the detection threshold of gravitational waves for LIGO?“Who saw” the binary neutron star merger first? What was the sequence of events? (GRB/GW170817)Do gravitational waves have distinct bands or parameters from which a source redshift can be inferred?Would an X-ray-based pulsar timing array in orbit or on the Moon to study GW background be effective?

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What produces gravitational waves with “periods between about 100 - 8000 seconds”?



Unicorn Meta Zoo #1: Why another podcast?
Announcing the arrival of Valued Associate #679: Cesar ManaraCan't pulsars and stars be used for gravitational wave measurement?Redshift for gravitational waves?Frequency of gravitational wave detectionWould humans hear gravity waves from a binary BH fusion nearby?What are gravitational waves actually?LIGO gravitational wave chirp signal frequencyWhich of the following statements about gravitational waves are true?What is the detection threshold of gravitational waves for LIGO?“Who saw” the binary neutron star merger first? What was the sequence of events? (GRB/GW170817)Do gravitational waves have distinct bands or parameters from which a source redshift can be inferred?Would an X-ray-based pulsar timing array in orbit or on the Moon to study GW background be effective?










4












$begingroup$


The Ulysses mission has a compelling story. I was sent to Jupiter to perform a gravitational assist shooting it out of the plane of the ecliptic in order to fly over the Sun's north and south poles to perform "fast latitude scans". Because of its design it was used for several important lines of scientific study.



Ulysses contained a pair of coherent transponders which received signals from Earth, shifted them in frequency in a coherent way using phase-locked loops and beamed them immediately back to Earth at two different frequencies.



From ESA's write up of the Ulysses Gravitational Wave Experiment:




In the spacecraft Doppler tracking method, the Earth and spacecraft constitute the two objects whose time-varying separation is monitored to detect a passing gravitational wave. The monitoring is accomplished with high-precision Doppler tracking in which a constant frequency microwave radio signal (S-band) is transmitted from the Earth to the spacecraft (uplink); the signal is transponded (received and coherently amplified) at the spacecraft; and then transmitted back to Earth (downlink) in both S- and X-band signals. This Dual frequency downlink is required in order to calibrate the interplanetary media which affects the two frequency bands differently. The downlink signal is recorded at Earth and its frequency is compared to the constant uplink frequency f0 to extract the Doppler signal, δf / f0.




The article goes on to say:




Since the optimum size of a gravitational wave detector is the wave length, interplanetary dimensions are needed for detecting gravitational waves in the mHz range. Doppler tracking of Ulysses provides sensitive detections of gravitational waves in this low frequency band. The driving noise source is the fluctuations in the refractive index of interplanetary plasma. This dictates the timing of the experiment to be near solar opposition and sets the target accuracy for the fractional frequency change at 3.0 × 10-14 for integration times of the order of 1000 seconds.



SUMMARY OF OBJECTIVES



The objective of the gravitational wave investigation on Ulysses is to search for low frequency gravitational waves crossing the Solar System. Because of the great distance to the spacecraft, this method is most sensitive to wave periods between about 100 - 8000 seconds, a band which is not accessible to ground-based experiments which are superior for periods below 1 second.




You can read more about Ulysses in eoPortal's Ulysses where I found both the link above and the following:



B. Bertotti, R. Ambrosini, S. W. Asmar, J. P. Brenkle, G. Comoretto, G. Giampieri, L. Iess, A. Messeri, H. D. Wahlquist, “The gravitational wave experiment,” Astronomy and Astrophysics Supplement Series, Ulysses Instruments Special Issue, Vol. 92, No. 2, pp. 431-440, Jan. 1992




Question: What produces gravitational waves with "periods between about 100 - 8000 seconds"?










share|improve this question









$endgroup$











  • $begingroup$
    Binary black holes that are not in the final stage of their approach. The frequency of the GW increases as the BHs get closer together - look at the graphs from LIGO and you'll see frequency speeding up towards the end. In the early stages it could take them a very long time to complete an orbit - just like binary stars, really. But amplitude is quite a bit lower in the early stages, so hopefully this new detector is much more sensitive amplitude-wise.
    $endgroup$
    – Florin Andrei
    Apr 20 at 7:11















4












$begingroup$


The Ulysses mission has a compelling story. I was sent to Jupiter to perform a gravitational assist shooting it out of the plane of the ecliptic in order to fly over the Sun's north and south poles to perform "fast latitude scans". Because of its design it was used for several important lines of scientific study.



Ulysses contained a pair of coherent transponders which received signals from Earth, shifted them in frequency in a coherent way using phase-locked loops and beamed them immediately back to Earth at two different frequencies.



From ESA's write up of the Ulysses Gravitational Wave Experiment:




In the spacecraft Doppler tracking method, the Earth and spacecraft constitute the two objects whose time-varying separation is monitored to detect a passing gravitational wave. The monitoring is accomplished with high-precision Doppler tracking in which a constant frequency microwave radio signal (S-band) is transmitted from the Earth to the spacecraft (uplink); the signal is transponded (received and coherently amplified) at the spacecraft; and then transmitted back to Earth (downlink) in both S- and X-band signals. This Dual frequency downlink is required in order to calibrate the interplanetary media which affects the two frequency bands differently. The downlink signal is recorded at Earth and its frequency is compared to the constant uplink frequency f0 to extract the Doppler signal, δf / f0.




The article goes on to say:




Since the optimum size of a gravitational wave detector is the wave length, interplanetary dimensions are needed for detecting gravitational waves in the mHz range. Doppler tracking of Ulysses provides sensitive detections of gravitational waves in this low frequency band. The driving noise source is the fluctuations in the refractive index of interplanetary plasma. This dictates the timing of the experiment to be near solar opposition and sets the target accuracy for the fractional frequency change at 3.0 × 10-14 for integration times of the order of 1000 seconds.



SUMMARY OF OBJECTIVES



The objective of the gravitational wave investigation on Ulysses is to search for low frequency gravitational waves crossing the Solar System. Because of the great distance to the spacecraft, this method is most sensitive to wave periods between about 100 - 8000 seconds, a band which is not accessible to ground-based experiments which are superior for periods below 1 second.




You can read more about Ulysses in eoPortal's Ulysses where I found both the link above and the following:



B. Bertotti, R. Ambrosini, S. W. Asmar, J. P. Brenkle, G. Comoretto, G. Giampieri, L. Iess, A. Messeri, H. D. Wahlquist, “The gravitational wave experiment,” Astronomy and Astrophysics Supplement Series, Ulysses Instruments Special Issue, Vol. 92, No. 2, pp. 431-440, Jan. 1992




Question: What produces gravitational waves with "periods between about 100 - 8000 seconds"?










share|improve this question









$endgroup$











  • $begingroup$
    Binary black holes that are not in the final stage of their approach. The frequency of the GW increases as the BHs get closer together - look at the graphs from LIGO and you'll see frequency speeding up towards the end. In the early stages it could take them a very long time to complete an orbit - just like binary stars, really. But amplitude is quite a bit lower in the early stages, so hopefully this new detector is much more sensitive amplitude-wise.
    $endgroup$
    – Florin Andrei
    Apr 20 at 7:11













4












4








4





$begingroup$


The Ulysses mission has a compelling story. I was sent to Jupiter to perform a gravitational assist shooting it out of the plane of the ecliptic in order to fly over the Sun's north and south poles to perform "fast latitude scans". Because of its design it was used for several important lines of scientific study.



Ulysses contained a pair of coherent transponders which received signals from Earth, shifted them in frequency in a coherent way using phase-locked loops and beamed them immediately back to Earth at two different frequencies.



From ESA's write up of the Ulysses Gravitational Wave Experiment:




In the spacecraft Doppler tracking method, the Earth and spacecraft constitute the two objects whose time-varying separation is monitored to detect a passing gravitational wave. The monitoring is accomplished with high-precision Doppler tracking in which a constant frequency microwave radio signal (S-band) is transmitted from the Earth to the spacecraft (uplink); the signal is transponded (received and coherently amplified) at the spacecraft; and then transmitted back to Earth (downlink) in both S- and X-band signals. This Dual frequency downlink is required in order to calibrate the interplanetary media which affects the two frequency bands differently. The downlink signal is recorded at Earth and its frequency is compared to the constant uplink frequency f0 to extract the Doppler signal, δf / f0.




The article goes on to say:




Since the optimum size of a gravitational wave detector is the wave length, interplanetary dimensions are needed for detecting gravitational waves in the mHz range. Doppler tracking of Ulysses provides sensitive detections of gravitational waves in this low frequency band. The driving noise source is the fluctuations in the refractive index of interplanetary plasma. This dictates the timing of the experiment to be near solar opposition and sets the target accuracy for the fractional frequency change at 3.0 × 10-14 for integration times of the order of 1000 seconds.



SUMMARY OF OBJECTIVES



The objective of the gravitational wave investigation on Ulysses is to search for low frequency gravitational waves crossing the Solar System. Because of the great distance to the spacecraft, this method is most sensitive to wave periods between about 100 - 8000 seconds, a band which is not accessible to ground-based experiments which are superior for periods below 1 second.




You can read more about Ulysses in eoPortal's Ulysses where I found both the link above and the following:



B. Bertotti, R. Ambrosini, S. W. Asmar, J. P. Brenkle, G. Comoretto, G. Giampieri, L. Iess, A. Messeri, H. D. Wahlquist, “The gravitational wave experiment,” Astronomy and Astrophysics Supplement Series, Ulysses Instruments Special Issue, Vol. 92, No. 2, pp. 431-440, Jan. 1992




Question: What produces gravitational waves with "periods between about 100 - 8000 seconds"?










share|improve this question









$endgroup$




The Ulysses mission has a compelling story. I was sent to Jupiter to perform a gravitational assist shooting it out of the plane of the ecliptic in order to fly over the Sun's north and south poles to perform "fast latitude scans". Because of its design it was used for several important lines of scientific study.



Ulysses contained a pair of coherent transponders which received signals from Earth, shifted them in frequency in a coherent way using phase-locked loops and beamed them immediately back to Earth at two different frequencies.



From ESA's write up of the Ulysses Gravitational Wave Experiment:




In the spacecraft Doppler tracking method, the Earth and spacecraft constitute the two objects whose time-varying separation is monitored to detect a passing gravitational wave. The monitoring is accomplished with high-precision Doppler tracking in which a constant frequency microwave radio signal (S-band) is transmitted from the Earth to the spacecraft (uplink); the signal is transponded (received and coherently amplified) at the spacecraft; and then transmitted back to Earth (downlink) in both S- and X-band signals. This Dual frequency downlink is required in order to calibrate the interplanetary media which affects the two frequency bands differently. The downlink signal is recorded at Earth and its frequency is compared to the constant uplink frequency f0 to extract the Doppler signal, δf / f0.




The article goes on to say:




Since the optimum size of a gravitational wave detector is the wave length, interplanetary dimensions are needed for detecting gravitational waves in the mHz range. Doppler tracking of Ulysses provides sensitive detections of gravitational waves in this low frequency band. The driving noise source is the fluctuations in the refractive index of interplanetary plasma. This dictates the timing of the experiment to be near solar opposition and sets the target accuracy for the fractional frequency change at 3.0 × 10-14 for integration times of the order of 1000 seconds.



SUMMARY OF OBJECTIVES



The objective of the gravitational wave investigation on Ulysses is to search for low frequency gravitational waves crossing the Solar System. Because of the great distance to the spacecraft, this method is most sensitive to wave periods between about 100 - 8000 seconds, a band which is not accessible to ground-based experiments which are superior for periods below 1 second.




You can read more about Ulysses in eoPortal's Ulysses where I found both the link above and the following:



B. Bertotti, R. Ambrosini, S. W. Asmar, J. P. Brenkle, G. Comoretto, G. Giampieri, L. Iess, A. Messeri, H. D. Wahlquist, “The gravitational wave experiment,” Astronomy and Astrophysics Supplement Series, Ulysses Instruments Special Issue, Vol. 92, No. 2, pp. 431-440, Jan. 1992




Question: What produces gravitational waves with "periods between about 100 - 8000 seconds"?







gravitational-waves artificial-satellite nasa






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Apr 20 at 4:16









uhohuhoh

7,65822275




7,65822275











  • $begingroup$
    Binary black holes that are not in the final stage of their approach. The frequency of the GW increases as the BHs get closer together - look at the graphs from LIGO and you'll see frequency speeding up towards the end. In the early stages it could take them a very long time to complete an orbit - just like binary stars, really. But amplitude is quite a bit lower in the early stages, so hopefully this new detector is much more sensitive amplitude-wise.
    $endgroup$
    – Florin Andrei
    Apr 20 at 7:11
















  • $begingroup$
    Binary black holes that are not in the final stage of their approach. The frequency of the GW increases as the BHs get closer together - look at the graphs from LIGO and you'll see frequency speeding up towards the end. In the early stages it could take them a very long time to complete an orbit - just like binary stars, really. But amplitude is quite a bit lower in the early stages, so hopefully this new detector is much more sensitive amplitude-wise.
    $endgroup$
    – Florin Andrei
    Apr 20 at 7:11















$begingroup$
Binary black holes that are not in the final stage of their approach. The frequency of the GW increases as the BHs get closer together - look at the graphs from LIGO and you'll see frequency speeding up towards the end. In the early stages it could take them a very long time to complete an orbit - just like binary stars, really. But amplitude is quite a bit lower in the early stages, so hopefully this new detector is much more sensitive amplitude-wise.
$endgroup$
– Florin Andrei
Apr 20 at 7:11




$begingroup$
Binary black holes that are not in the final stage of their approach. The frequency of the GW increases as the BHs get closer together - look at the graphs from LIGO and you'll see frequency speeding up towards the end. In the early stages it could take them a very long time to complete an orbit - just like binary stars, really. But amplitude is quite a bit lower in the early stages, so hopefully this new detector is much more sensitive amplitude-wise.
$endgroup$
– Florin Andrei
Apr 20 at 7:11










1 Answer
1






active

oldest

votes


















5












$begingroup$

Any binary system produces gravitational waves at twice it's orbital frequency, i.e. with periods of half it's orbital period. So binary systems with periods between 200s and 16000s will produce such waves.



We can use Kepler's third law to say something about these:
$$ a = left(fracGM4piright)^1/3 P^2/3,$$
where $P$ is the orbital period, $M$ is the total mass of the binary system and $a$ is the orbital separation.



For a binary with $Msim 1M_odot$ and $200<P<16000$s, then $0.11 < a < 2.00 R_odot$. Since normal stars of mass $sim 0.5M_odot$ have radii that are similar to this, then the stars would probably need to be stellar remnants (white dwarfs, neutron stars or black holes) except right at the longest period end, where it might be possible to observe W Uma binaries. More massive binaries have separations that increase as $M^1/3$, but the radii of normal stars increases more like $M$, so this conclusion is even firmer at larger masses.



It could be possible to have a compact binary involving a low mass star plus a compact object - perhaps a Roche lobe filling one, so as well as "double degenerates", the long period end of this range would include Cataclysmic Variables and Low Mass X-ray binary counterparts, with orbital periods of a few hours.



Of course gravitational wave strain goes as something like $M P^-4/3 d^-1$, where $d$ is the distance. These binaries are much longer period than the (presumably rare) massive, merging black holes seen so far and so probably need to be close, in our own Galaxy, to be detected.



e.g. LIGO was capable of detecting $M sim 30 M_odot$ merging black holes, with $P sim 0.02$ s at distances of a billion light years. A similar strain amplitude would be produced by a $Msim 2M_odot$ binary with $P= 200$ s at a distance of 300 light years.






share|improve this answer











$endgroup$












  • $begingroup$
    Thanks for the clear answer! I'm curious how the strain scales with $M$. Perhaps some of that weakness could be made up by the pair being fairly massive?
    $endgroup$
    – uhoh
    Apr 20 at 8:01











  • $begingroup$
    I just ran across this deleted answer, saw that the supernovae fit within the 100-8000 limits and thought to add a supplemental answer. Then I saw it was your deleted answer. Do you think adding a reference to this phenomenon might be useful here?
    $endgroup$
    – uhoh
    yesterday






  • 1




    $begingroup$
    @uhoh Look again. The x-axis is frequency, not period
    $endgroup$
    – Rob Jeffries
    21 hours ago










  • $begingroup$
    and so it is, thanks!
    $endgroup$
    – uhoh
    19 hours ago











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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









5












$begingroup$

Any binary system produces gravitational waves at twice it's orbital frequency, i.e. with periods of half it's orbital period. So binary systems with periods between 200s and 16000s will produce such waves.



We can use Kepler's third law to say something about these:
$$ a = left(fracGM4piright)^1/3 P^2/3,$$
where $P$ is the orbital period, $M$ is the total mass of the binary system and $a$ is the orbital separation.



For a binary with $Msim 1M_odot$ and $200<P<16000$s, then $0.11 < a < 2.00 R_odot$. Since normal stars of mass $sim 0.5M_odot$ have radii that are similar to this, then the stars would probably need to be stellar remnants (white dwarfs, neutron stars or black holes) except right at the longest period end, where it might be possible to observe W Uma binaries. More massive binaries have separations that increase as $M^1/3$, but the radii of normal stars increases more like $M$, so this conclusion is even firmer at larger masses.



It could be possible to have a compact binary involving a low mass star plus a compact object - perhaps a Roche lobe filling one, so as well as "double degenerates", the long period end of this range would include Cataclysmic Variables and Low Mass X-ray binary counterparts, with orbital periods of a few hours.



Of course gravitational wave strain goes as something like $M P^-4/3 d^-1$, where $d$ is the distance. These binaries are much longer period than the (presumably rare) massive, merging black holes seen so far and so probably need to be close, in our own Galaxy, to be detected.



e.g. LIGO was capable of detecting $M sim 30 M_odot$ merging black holes, with $P sim 0.02$ s at distances of a billion light years. A similar strain amplitude would be produced by a $Msim 2M_odot$ binary with $P= 200$ s at a distance of 300 light years.






share|improve this answer











$endgroup$












  • $begingroup$
    Thanks for the clear answer! I'm curious how the strain scales with $M$. Perhaps some of that weakness could be made up by the pair being fairly massive?
    $endgroup$
    – uhoh
    Apr 20 at 8:01











  • $begingroup$
    I just ran across this deleted answer, saw that the supernovae fit within the 100-8000 limits and thought to add a supplemental answer. Then I saw it was your deleted answer. Do you think adding a reference to this phenomenon might be useful here?
    $endgroup$
    – uhoh
    yesterday






  • 1




    $begingroup$
    @uhoh Look again. The x-axis is frequency, not period
    $endgroup$
    – Rob Jeffries
    21 hours ago










  • $begingroup$
    and so it is, thanks!
    $endgroup$
    – uhoh
    19 hours ago















5












$begingroup$

Any binary system produces gravitational waves at twice it's orbital frequency, i.e. with periods of half it's orbital period. So binary systems with periods between 200s and 16000s will produce such waves.



We can use Kepler's third law to say something about these:
$$ a = left(fracGM4piright)^1/3 P^2/3,$$
where $P$ is the orbital period, $M$ is the total mass of the binary system and $a$ is the orbital separation.



For a binary with $Msim 1M_odot$ and $200<P<16000$s, then $0.11 < a < 2.00 R_odot$. Since normal stars of mass $sim 0.5M_odot$ have radii that are similar to this, then the stars would probably need to be stellar remnants (white dwarfs, neutron stars or black holes) except right at the longest period end, where it might be possible to observe W Uma binaries. More massive binaries have separations that increase as $M^1/3$, but the radii of normal stars increases more like $M$, so this conclusion is even firmer at larger masses.



It could be possible to have a compact binary involving a low mass star plus a compact object - perhaps a Roche lobe filling one, so as well as "double degenerates", the long period end of this range would include Cataclysmic Variables and Low Mass X-ray binary counterparts, with orbital periods of a few hours.



Of course gravitational wave strain goes as something like $M P^-4/3 d^-1$, where $d$ is the distance. These binaries are much longer period than the (presumably rare) massive, merging black holes seen so far and so probably need to be close, in our own Galaxy, to be detected.



e.g. LIGO was capable of detecting $M sim 30 M_odot$ merging black holes, with $P sim 0.02$ s at distances of a billion light years. A similar strain amplitude would be produced by a $Msim 2M_odot$ binary with $P= 200$ s at a distance of 300 light years.






share|improve this answer











$endgroup$












  • $begingroup$
    Thanks for the clear answer! I'm curious how the strain scales with $M$. Perhaps some of that weakness could be made up by the pair being fairly massive?
    $endgroup$
    – uhoh
    Apr 20 at 8:01











  • $begingroup$
    I just ran across this deleted answer, saw that the supernovae fit within the 100-8000 limits and thought to add a supplemental answer. Then I saw it was your deleted answer. Do you think adding a reference to this phenomenon might be useful here?
    $endgroup$
    – uhoh
    yesterday






  • 1




    $begingroup$
    @uhoh Look again. The x-axis is frequency, not period
    $endgroup$
    – Rob Jeffries
    21 hours ago










  • $begingroup$
    and so it is, thanks!
    $endgroup$
    – uhoh
    19 hours ago













5












5








5





$begingroup$

Any binary system produces gravitational waves at twice it's orbital frequency, i.e. with periods of half it's orbital period. So binary systems with periods between 200s and 16000s will produce such waves.



We can use Kepler's third law to say something about these:
$$ a = left(fracGM4piright)^1/3 P^2/3,$$
where $P$ is the orbital period, $M$ is the total mass of the binary system and $a$ is the orbital separation.



For a binary with $Msim 1M_odot$ and $200<P<16000$s, then $0.11 < a < 2.00 R_odot$. Since normal stars of mass $sim 0.5M_odot$ have radii that are similar to this, then the stars would probably need to be stellar remnants (white dwarfs, neutron stars or black holes) except right at the longest period end, where it might be possible to observe W Uma binaries. More massive binaries have separations that increase as $M^1/3$, but the radii of normal stars increases more like $M$, so this conclusion is even firmer at larger masses.



It could be possible to have a compact binary involving a low mass star plus a compact object - perhaps a Roche lobe filling one, so as well as "double degenerates", the long period end of this range would include Cataclysmic Variables and Low Mass X-ray binary counterparts, with orbital periods of a few hours.



Of course gravitational wave strain goes as something like $M P^-4/3 d^-1$, where $d$ is the distance. These binaries are much longer period than the (presumably rare) massive, merging black holes seen so far and so probably need to be close, in our own Galaxy, to be detected.



e.g. LIGO was capable of detecting $M sim 30 M_odot$ merging black holes, with $P sim 0.02$ s at distances of a billion light years. A similar strain amplitude would be produced by a $Msim 2M_odot$ binary with $P= 200$ s at a distance of 300 light years.






share|improve this answer











$endgroup$



Any binary system produces gravitational waves at twice it's orbital frequency, i.e. with periods of half it's orbital period. So binary systems with periods between 200s and 16000s will produce such waves.



We can use Kepler's third law to say something about these:
$$ a = left(fracGM4piright)^1/3 P^2/3,$$
where $P$ is the orbital period, $M$ is the total mass of the binary system and $a$ is the orbital separation.



For a binary with $Msim 1M_odot$ and $200<P<16000$s, then $0.11 < a < 2.00 R_odot$. Since normal stars of mass $sim 0.5M_odot$ have radii that are similar to this, then the stars would probably need to be stellar remnants (white dwarfs, neutron stars or black holes) except right at the longest period end, where it might be possible to observe W Uma binaries. More massive binaries have separations that increase as $M^1/3$, but the radii of normal stars increases more like $M$, so this conclusion is even firmer at larger masses.



It could be possible to have a compact binary involving a low mass star plus a compact object - perhaps a Roche lobe filling one, so as well as "double degenerates", the long period end of this range would include Cataclysmic Variables and Low Mass X-ray binary counterparts, with orbital periods of a few hours.



Of course gravitational wave strain goes as something like $M P^-4/3 d^-1$, where $d$ is the distance. These binaries are much longer period than the (presumably rare) massive, merging black holes seen so far and so probably need to be close, in our own Galaxy, to be detected.



e.g. LIGO was capable of detecting $M sim 30 M_odot$ merging black holes, with $P sim 0.02$ s at distances of a billion light years. A similar strain amplitude would be produced by a $Msim 2M_odot$ binary with $P= 200$ s at a distance of 300 light years.







share|improve this answer














share|improve this answer



share|improve this answer








edited yesterday

























answered Apr 20 at 7:56









Rob JeffriesRob Jeffries

55.2k4114177




55.2k4114177











  • $begingroup$
    Thanks for the clear answer! I'm curious how the strain scales with $M$. Perhaps some of that weakness could be made up by the pair being fairly massive?
    $endgroup$
    – uhoh
    Apr 20 at 8:01











  • $begingroup$
    I just ran across this deleted answer, saw that the supernovae fit within the 100-8000 limits and thought to add a supplemental answer. Then I saw it was your deleted answer. Do you think adding a reference to this phenomenon might be useful here?
    $endgroup$
    – uhoh
    yesterday






  • 1




    $begingroup$
    @uhoh Look again. The x-axis is frequency, not period
    $endgroup$
    – Rob Jeffries
    21 hours ago










  • $begingroup$
    and so it is, thanks!
    $endgroup$
    – uhoh
    19 hours ago
















  • $begingroup$
    Thanks for the clear answer! I'm curious how the strain scales with $M$. Perhaps some of that weakness could be made up by the pair being fairly massive?
    $endgroup$
    – uhoh
    Apr 20 at 8:01











  • $begingroup$
    I just ran across this deleted answer, saw that the supernovae fit within the 100-8000 limits and thought to add a supplemental answer. Then I saw it was your deleted answer. Do you think adding a reference to this phenomenon might be useful here?
    $endgroup$
    – uhoh
    yesterday






  • 1




    $begingroup$
    @uhoh Look again. The x-axis is frequency, not period
    $endgroup$
    – Rob Jeffries
    21 hours ago










  • $begingroup$
    and so it is, thanks!
    $endgroup$
    – uhoh
    19 hours ago















$begingroup$
Thanks for the clear answer! I'm curious how the strain scales with $M$. Perhaps some of that weakness could be made up by the pair being fairly massive?
$endgroup$
– uhoh
Apr 20 at 8:01





$begingroup$
Thanks for the clear answer! I'm curious how the strain scales with $M$. Perhaps some of that weakness could be made up by the pair being fairly massive?
$endgroup$
– uhoh
Apr 20 at 8:01













$begingroup$
I just ran across this deleted answer, saw that the supernovae fit within the 100-8000 limits and thought to add a supplemental answer. Then I saw it was your deleted answer. Do you think adding a reference to this phenomenon might be useful here?
$endgroup$
– uhoh
yesterday




$begingroup$
I just ran across this deleted answer, saw that the supernovae fit within the 100-8000 limits and thought to add a supplemental answer. Then I saw it was your deleted answer. Do you think adding a reference to this phenomenon might be useful here?
$endgroup$
– uhoh
yesterday




1




1




$begingroup$
@uhoh Look again. The x-axis is frequency, not period
$endgroup$
– Rob Jeffries
21 hours ago




$begingroup$
@uhoh Look again. The x-axis is frequency, not period
$endgroup$
– Rob Jeffries
21 hours ago












$begingroup$
and so it is, thanks!
$endgroup$
– uhoh
19 hours ago




$begingroup$
and so it is, thanks!
$endgroup$
– uhoh
19 hours ago

















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