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5

I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.

function execute_function() 
# Launch job
 number_of_jobs=$1
 echo "Launching $number_of_jobs jobs"
 for i in 1..$1; do
 job_id=`head /dev/urandom 

When I run it, I always get:

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"

shell-script shell osx brace-expansion

share|improve this question

edited 2 days ago

Kusalananda♦

139k17261433

asked 2 days ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

5

I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.

function execute_function() 
# Launch job
 number_of_jobs=$1
 echo "Launching $number_of_jobs jobs"
 for i in 1..$1; do
 job_id=`head /dev/urandom 

When I run it, I always get:

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"

shell-script shell osx brace-expansion

share|improve this question

edited 2 days ago

Kusalananda♦

139k17261433

asked 2 days ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.

function execute_function() 
# Launch job
 number_of_jobs=$1
 echo "Launching $number_of_jobs jobs"
 for i in 1..$1; do
 job_id=`head /dev/urandom 

When I run it, I always get:

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"

shell-script shell osx brace-expansion

share|improve this question

edited 2 days ago

Kusalananda♦

139k17261433

asked 2 days ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

function execute_function() 
# Launch job
 number_of_jobs=$1
 echo "Launching $number_of_jobs jobs"
 for i in 1..$1; do
 job_id=`head /dev/urandom 

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

share|improve this question

edited 2 days ago

Kusalananda♦

139k17261433

asked 2 days ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 2 days ago

Kusalananda♦

139k17261433

asked 2 days ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited 2 days ago

Kusalananda♦

139k17261433

edited 2 days ago

Kusalananda♦

139k17261433

asked 2 days ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 2 days ago

spicyramenspicyramen

1284

2 Answers
2

active

oldest

votes

5

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited 2 days ago

answered 2 days ago

Jakub JindraJakub Jindra

598413

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That worked perfectly
  
  – spicyramen
  2 days ago
  

  
  
  
  

add a comment | 

6

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited 2 days ago

answered 2 days ago

Kusalananda♦Kusalananda

139k17261433

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  include #!/bin/zsh as first line. (you may need to check the path.
  
  – ctrl-alt-delor
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  what about #!/usr/bin/env zsh?
  
  – Jakub Jindra
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.
  
  – Kusalananda♦
  2 days ago
  
  

  
  
  
  

add a comment | 

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5

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited 2 days ago

answered 2 days ago

Jakub JindraJakub Jindra

598413

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That worked perfectly
  
  – spicyramen
  2 days ago
  

  
  
  
  

add a comment | 

5

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited 2 days ago

answered 2 days ago

Jakub JindraJakub Jindra

598413

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That worked perfectly
  
  – spicyramen
  2 days ago
  

  
  
  
  

add a comment | 

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited 2 days ago

answered 2 days ago

Jakub JindraJakub Jindra

598413

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited 2 days ago

answered 2 days ago

Jakub JindraJakub Jindra

598413

answered 2 days ago

Jakub JindraJakub Jindra

598413

answered 2 days ago

Jakub JindraJakub Jindra

598413

6

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited 2 days ago

answered 2 days ago

Kusalananda♦Kusalananda

139k17261433

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  include #!/bin/zsh as first line. (you may need to check the path.
  
  – ctrl-alt-delor
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  what about #!/usr/bin/env zsh?
  
  – Jakub Jindra
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.
  
  – Kusalananda♦
  2 days ago
  
  

  
  
  
  

add a comment | 

6

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited 2 days ago

answered 2 days ago

Kusalananda♦Kusalananda

139k17261433

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  include #!/bin/zsh as first line. (you may need to check the path.
  
  – ctrl-alt-delor
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  what about #!/usr/bin/env zsh?
  
  – Jakub Jindra
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.
  
  – Kusalananda♦
  2 days ago
  
  

  
  
  
  

add a comment | 

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited 2 days ago

answered 2 days ago

Kusalananda♦Kusalananda

139k17261433

share|improve this answer

edited 2 days ago

answered 2 days ago

Kusalananda♦Kusalananda

139k17261433

answered 2 days ago

Kusalananda♦Kusalananda

139k17261433

answered 2 days ago

Kusalananda♦Kusalananda

139k17261433