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Loop in macOS not working
Does the shebang determine the shell which runs the script?How can I use $variable in a shell brace expansion of a sequence?Listing numbered files using wildcard sequence with predefined rangePrevent SIGINT from interrupting function call and child process(es) withinUse bash's read builtin without a while loopCron only occasionally sends e-mail on output and errorsCan the Bash shell “Ignore” Excess copy-paste text?Ampersand after for loop on shell scriptsHow to elaborate multiple selected files by drag & drop in a bash scriptSSH connections running in the background don't exit if multiple connections have been started by the same shellCan't get SSH access from MacOS host to QEMU Sparc guestSet comparator with variables within a variable, then have shell expand those variables each time it's echo'dIs it possible to source ~/.profile in the current shell from a script?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.
function execute_function()
# Launch job
number_of_jobs=$1
echo "Launching $number_of_jobs jobs"
for i in 1..$1; do
job_id=`head /dev/urandom
When I run it, I always get:
execute_function 10
Launching 10 jobs
Launching Job: XX9BWC
1..10
The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"
shell-script shell osx brace-expansion
edited 2 days ago
Kusalananda♦
139k17261433
asked 2 days ago
spicyramenspicyramen
1284
New contributor
spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.
function execute_function()
# Launch job
number_of_jobs=$1
echo "Launching $number_of_jobs jobs"
for i in 1..$1; do
job_id=`head /dev/urandom
When I run it, I always get:
execute_function 10
Launching 10 jobs
Launching Job: XX9BWC
1..10
The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"
shell-script shell osx brace-expansion
edited 2 days ago
Kusalananda♦
139k17261433
asked 2 days ago
spicyramenspicyramen
1284
New contributor
spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.
function execute_function()
# Launch job
number_of_jobs=$1
echo "Launching $number_of_jobs jobs"
for i in 1..$1; do
job_id=`head /dev/urandom
When I run it, I always get:
execute_function 10
Launching 10 jobs
Launching Job: XX9BWC
1..10
The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"
shell-script shell osx brace-expansion
edited 2 days ago
Kusalananda♦
139k17261433
asked 2 days ago
spicyramenspicyramen
1284
New contributor
spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.
function execute_function()
# Launch job
number_of_jobs=$1
echo "Launching $number_of_jobs jobs"
for i in 1..$1; do
job_id=`head /dev/urandom
When I run it, I always get:
execute_function 10
Launching 10 jobs
Launching Job: XX9BWC
1..10
The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"
shell-script shell osx brace-expansion
shell-script shell osx brace-expansion
edited 2 days ago
Kusalananda♦
139k17261433
asked 2 days ago
spicyramenspicyramen
1284
New contributor
spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
Kusalananda♦
139k17261433
asked 2 days ago
spicyramenspicyramen
1284
New contributor
spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
Kusalananda♦
139k17261433
edited 2 days ago
Kusalananda♦
139k17261433
edited 2 days ago
Kusalananda♦
139k17261433
139k17261433
asked 2 days ago
spicyramenspicyramen
1284
New contributor
spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
spicyramenspicyramen
1284
asked 2 days ago
spicyramenspicyramen
1284
1284
New contributor
spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
The problem here is variable in braces expansion.
Try rewriting it to
for ((i=1;i<=$1;i++))
do
#your code here
done
answered 2 days ago
Jakub JindraJakub Jindra
598413
That worked perfectly
– spicyramen
2 days ago
add a comment |
Your script is written for zsh but you are executing it with bash.
bash does not support using variables as ranges in brace-expansions.
To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.
See also:
- Listing numbered files using wildcard sequence with predefined range
- How can I use $variable in a shell brace expansion of a sequence?
- Does the shebang determine the shell which runs the script?
answered 2 days ago
Kusalananda♦Kusalananda
139k17261433
1
include#!/bin/zshas first line. (you may need to check the path.
– ctrl-alt-delor
2 days ago
what about#!/usr/bin/env zsh?
– Jakub Jindra
2 days ago
@JakubJindra That would work to, but the default location ofzshis/bin/zshon macOS. Obviously, you may want to useenvif you need to use a 3rd-party installation ofzsh. However, this is not the essence of this particular question.
– Kusalananda♦
2 days ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The problem here is variable in braces expansion.
Try rewriting it to
for ((i=1;i<=$1;i++))
do
#your code here
done
answered 2 days ago
Jakub JindraJakub Jindra
598413
That worked perfectly
– spicyramen
2 days ago
add a comment |
The problem here is variable in braces expansion.
Try rewriting it to
for ((i=1;i<=$1;i++))
do
#your code here
done
answered 2 days ago
Jakub JindraJakub Jindra
598413
That worked perfectly
– spicyramen
2 days ago
add a comment |
The problem here is variable in braces expansion.
Try rewriting it to
for ((i=1;i<=$1;i++))
do
#your code here
done
answered 2 days ago
Jakub JindraJakub Jindra
598413
The problem here is variable in braces expansion.
Try rewriting it to
for ((i=1;i<=$1;i++))
do
#your code here
done
answered 2 days ago
Jakub JindraJakub Jindra
598413
edited 2 days ago
answered 2 days ago
Jakub JindraJakub Jindra
598413
answered 2 days ago
Jakub JindraJakub Jindra
598413
answered 2 days ago
Jakub JindraJakub Jindra
598413
598413
That worked perfectly
– spicyramen
2 days ago
add a comment |
That worked perfectly
– spicyramen
2 days ago
That worked perfectly
– spicyramen
2 days ago
That worked perfectly
– spicyramen
2 days ago
add a comment |
Your script is written for zsh but you are executing it with bash.
bash does not support using variables as ranges in brace-expansions.
To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.
See also:
- Listing numbered files using wildcard sequence with predefined range
- How can I use $variable in a shell brace expansion of a sequence?
- Does the shebang determine the shell which runs the script?
answered 2 days ago
Kusalananda♦Kusalananda
139k17261433
1
include#!/bin/zshas first line. (you may need to check the path.
– ctrl-alt-delor
2 days ago
what about#!/usr/bin/env zsh?
– Jakub Jindra
2 days ago
@JakubJindra That would work to, but the default location ofzshis/bin/zshon macOS. Obviously, you may want to useenvif you need to use a 3rd-party installation ofzsh. However, this is not the essence of this particular question.
– Kusalananda♦
2 days ago
add a comment |
Your script is written for zsh but you are executing it with bash.
bash does not support using variables as ranges in brace-expansions.
To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.
See also:
- Listing numbered files using wildcard sequence with predefined range
- How can I use $variable in a shell brace expansion of a sequence?
- Does the shebang determine the shell which runs the script?
answered 2 days ago
Kusalananda♦Kusalananda
139k17261433
1
include#!/bin/zshas first line. (you may need to check the path.
– ctrl-alt-delor
2 days ago
what about#!/usr/bin/env zsh?
– Jakub Jindra
2 days ago
@JakubJindra That would work to, but the default location ofzshis/bin/zshon macOS. Obviously, you may want to useenvif you need to use a 3rd-party installation ofzsh. However, this is not the essence of this particular question.
– Kusalananda♦
2 days ago
add a comment |
Your script is written for zsh but you are executing it with bash.
bash does not support using variables as ranges in brace-expansions.
To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.
See also:
- Listing numbered files using wildcard sequence with predefined range
- How can I use $variable in a shell brace expansion of a sequence?
- Does the shebang determine the shell which runs the script?
answered 2 days ago
Kusalananda♦Kusalananda
139k17261433
Your script is written for zsh but you are executing it with bash.
bash does not support using variables as ranges in brace-expansions.
To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.
See also:
- Listing numbered files using wildcard sequence with predefined range
- How can I use $variable in a shell brace expansion of a sequence?
- Does the shebang determine the shell which runs the script?
answered 2 days ago
Kusalananda♦Kusalananda
139k17261433
edited 2 days ago
answered 2 days ago
Kusalananda♦Kusalananda
139k17261433
answered 2 days ago
Kusalananda♦Kusalananda
139k17261433
answered 2 days ago
Kusalananda♦Kusalananda
139k17261433
139k17261433
1
include#!/bin/zshas first line. (you may need to check the path.
– ctrl-alt-delor
2 days ago
what about#!/usr/bin/env zsh?
– Jakub Jindra
2 days ago
@JakubJindra That would work to, but the default location ofzshis/bin/zshon macOS. Obviously, you may want to useenvif you need to use a 3rd-party installation ofzsh. However, this is not the essence of this particular question.
– Kusalananda♦
2 days ago
add a comment |
1
include#!/bin/zshas first line. (you may need to check the path.
– ctrl-alt-delor
2 days ago
what about#!/usr/bin/env zsh?
– Jakub Jindra
2 days ago
@JakubJindra That would work to, but the default location ofzshis/bin/zshon macOS. Obviously, you may want to useenvif you need to use a 3rd-party installation ofzsh. However, this is not the essence of this particular question.
– Kusalananda♦
2 days ago
1
1
include
#!/bin/zsh as first line. (you may need to check the path.– ctrl-alt-delor
2 days ago
include
#!/bin/zsh as first line. (you may need to check the path.– ctrl-alt-delor
2 days ago
what about
#!/usr/bin/env zsh?– Jakub Jindra
2 days ago
what about
#!/usr/bin/env zsh?– Jakub Jindra
2 days ago
@JakubJindra That would work to, but the default location of
zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.– Kusalananda♦
2 days ago
@JakubJindra That would work to, but the default location of
zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.– Kusalananda♦
2 days ago
add a comment |
spicyramen is a new contributor. Be nice, and check out our Code of Conduct.
spicyramen is a new contributor. Be nice, and check out our Code of Conduct.
spicyramen is a new contributor. Be nice, and check out our Code of Conduct.
spicyramen is a new contributor. Be nice, and check out our Code of Conduct.
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