Decimal to roman pythonRoman Numeral to Decimal ConversionConverting Roman numerals to decimalRoman numeral converter in RubyRoman numerals to decimalRoman numeral to decimal converterCurrency converter in Python 2.7“Merchants Guide to Galaxy” challengeGreed Dice Scoring Game expanded - Python KoansArea and volume calculatorNumber of possible numbers in roman number string

What would the Romans have called "sorcery"?

How to make payment on the internet without leaving a money trail?

Is there really no realistic way for a skeleton monster to move around without magic?

whey we use polarized capacitor?

Are tax years 2016 & 2017 back taxes deductible for tax year 2018?

How is it possible to have an ability score that is less than 3?

How does one intimidate enemies without having the capacity for violence?

Extreme, but not acceptable situation and I can't start the work tomorrow morning

Why is the design of haulage companies so “special”?

What are these boxed doors outside store fronts in New York?

How long does it take to type this?

Email Account under attack (really) - anything I can do?

Is there a familial term for apples and pears?

XeLaTeX and pdfLaTeX ignore hyphenation

Why are 150k or 200k jobs considered good when there are 300k+ births a month?

The use of multiple foreign keys on same column in SQL Server

Banach space and Hilbert space topology

What makes Graph invariants so useful/important?

black dwarf stars and dark matter

What would happen to a modern skyscraper if it rains micro blackholes?

Circuitry of TV splitters

Should I join office cleaning event for free?

Draw simple lines in Inkscape

How can I fix this gap between bookcases I made?



Decimal to roman python


Roman Numeral to Decimal ConversionConverting Roman numerals to decimalRoman numeral converter in RubyRoman numerals to decimalRoman numeral to decimal converterCurrency converter in Python 2.7“Merchants Guide to Galaxy” challengeGreed Dice Scoring Game expanded - Python KoansArea and volume calculatorNumber of possible numbers in roman number string






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








6












$begingroup$


I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
500: 'D', 900: 'CM', 1000: 'M'

divide_list = [1000, 100, 10, 1]

def not_in_dict(fixed_decimal, divide_num):
sub_count = 0
sub_roman_multi = roman_dict[divide_num]
temp_decimal = fixed_decimal
while temp_decimal not in roman_dict:
temp_decimal -= divide_num
sub_count += 1
return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

def decimal_to_roman(decimal):
original_decimal = decimal
roman = ""
for divide_num in divide_list:
if decimal >= divide_num:
reminder = decimal//divide_num
if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
roman += roman_dict[(reminder*divide_num)]
decimal -= reminder*divide_num
else:
roman += not_in_dict(reminder*divide_num, divide_num)
decimal -= (reminder*divide_num)
return str(original_decimal)+' = '+roman









share|improve this question









New contributor




Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$


















    6












    $begingroup$


    I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



    roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
    500: 'D', 900: 'CM', 1000: 'M'

    divide_list = [1000, 100, 10, 1]

    def not_in_dict(fixed_decimal, divide_num):
    sub_count = 0
    sub_roman_multi = roman_dict[divide_num]
    temp_decimal = fixed_decimal
    while temp_decimal not in roman_dict:
    temp_decimal -= divide_num
    sub_count += 1
    return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

    def decimal_to_roman(decimal):
    original_decimal = decimal
    roman = ""
    for divide_num in divide_list:
    if decimal >= divide_num:
    reminder = decimal//divide_num
    if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
    roman += roman_dict[(reminder*divide_num)]
    decimal -= reminder*divide_num
    else:
    roman += not_in_dict(reminder*divide_num, divide_num)
    decimal -= (reminder*divide_num)
    return str(original_decimal)+' = '+roman









    share|improve this question









    New contributor




    Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      6












      6








      6





      $begingroup$


      I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



      roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
      500: 'D', 900: 'CM', 1000: 'M'

      divide_list = [1000, 100, 10, 1]

      def not_in_dict(fixed_decimal, divide_num):
      sub_count = 0
      sub_roman_multi = roman_dict[divide_num]
      temp_decimal = fixed_decimal
      while temp_decimal not in roman_dict:
      temp_decimal -= divide_num
      sub_count += 1
      return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

      def decimal_to_roman(decimal):
      original_decimal = decimal
      roman = ""
      for divide_num in divide_list:
      if decimal >= divide_num:
      reminder = decimal//divide_num
      if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
      roman += roman_dict[(reminder*divide_num)]
      decimal -= reminder*divide_num
      else:
      roman += not_in_dict(reminder*divide_num, divide_num)
      decimal -= (reminder*divide_num)
      return str(original_decimal)+' = '+roman









      share|improve this question









      New contributor




      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



      roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
      500: 'D', 900: 'CM', 1000: 'M'

      divide_list = [1000, 100, 10, 1]

      def not_in_dict(fixed_decimal, divide_num):
      sub_count = 0
      sub_roman_multi = roman_dict[divide_num]
      temp_decimal = fixed_decimal
      while temp_decimal not in roman_dict:
      temp_decimal -= divide_num
      sub_count += 1
      return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

      def decimal_to_roman(decimal):
      original_decimal = decimal
      roman = ""
      for divide_num in divide_list:
      if decimal >= divide_num:
      reminder = decimal//divide_num
      if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
      roman += roman_dict[(reminder*divide_num)]
      decimal -= reminder*divide_num
      else:
      roman += not_in_dict(reminder*divide_num, divide_num)
      decimal -= (reminder*divide_num)
      return str(original_decimal)+' = '+roman






      python roman-numerals






      share|improve this question









      New contributor




      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited Apr 4 at 11:53









      Graipher

      26.8k54396




      26.8k54396






      New contributor




      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked Apr 4 at 10:23









      OfeksOfeks

      333




      333




      New contributor




      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















          1 Answer
          1






          active

          oldest

          votes


















          10












          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$












          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            Apr 4 at 13:36











          • $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            Apr 4 at 14:01











          Your Answer





          StackExchange.ifUsing("editor", function ()
          return StackExchange.using("mathjaxEditing", function ()
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
          );
          );
          , "mathjax-editing");

          StackExchange.ifUsing("editor", function ()
          StackExchange.using("externalEditor", function ()
          StackExchange.using("snippets", function ()
          StackExchange.snippets.init();
          );
          );
          , "code-snippets");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "196"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: false,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: null,
          bindNavPrevention: true,
          postfix: "",
          imageUploader:
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          ,
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );






          Ofeks is a new contributor. Be nice, and check out our Code of Conduct.









          draft saved

          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216852%2fdecimal-to-roman-python%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          10












          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$












          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            Apr 4 at 13:36











          • $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            Apr 4 at 14:01















          10












          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$












          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            Apr 4 at 13:36











          • $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            Apr 4 at 14:01













          10












          10








          10





          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$



          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Apr 4 at 14:44

























          answered Apr 4 at 12:01









          GraipherGraipher

          26.8k54396




          26.8k54396











          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            Apr 4 at 13:36











          • $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            Apr 4 at 14:01
















          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            Apr 4 at 13:36











          • $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            Apr 4 at 14:01















          $begingroup$
          wow. looks so easy now, thank you. that's great.
          $endgroup$
          – Ofeks
          Apr 4 at 13:36





          $begingroup$
          wow. looks so easy now, thank you. that's great.
          $endgroup$
          – Ofeks
          Apr 4 at 13:36













          $begingroup$
          @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
          $endgroup$
          – Graipher
          Apr 4 at 14:01




          $begingroup$
          @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
          $endgroup$
          – Graipher
          Apr 4 at 14:01










          Ofeks is a new contributor. Be nice, and check out our Code of Conduct.









          draft saved

          draft discarded


















          Ofeks is a new contributor. Be nice, and check out our Code of Conduct.












          Ofeks is a new contributor. Be nice, and check out our Code of Conduct.











          Ofeks is a new contributor. Be nice, and check out our Code of Conduct.














          Thanks for contributing an answer to Code Review Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid


          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.

          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216852%2fdecimal-to-roman-python%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Sum ergo cogito? 1 nng

          419 nièngy_Soadمي 19bal1.5o_g

          Queiggey Chernihivv 9NnOo i Zw X QqKk LpB